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Mastering Essential Maths Book 7C: Question Types & Solutions | KS3 数学:Essential Maths Book 7C 答案题型解析

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📚 Mastering Essential Maths Book 7C: Question Types & Solutions | KS3 数学:Essential Maths Book 7C 答案题型解析

The Essential Maths Book 7C is a core resource for KS3 students, building fluency in key topics such as number, algebra, geometry, and statistics. This guide analyses the most common question types and provides step-by-step solutions, helping students understand not just the final answer but the reasoning behind it.

Essential Maths Book 7C 是 KS3 阶段的核心教材,帮助学生在数、代数、几何和统计等主题上建立扎实的运算能力。本指南分析最常见的题型并给出逐步解答,帮助学生不仅掌握最终答案,更理解背后的推理过程。

1. Number and Place Value | 数与位值

Place value questions often ask for the value of a specific digit in large numbers or decimals. For example, in the number 45 623.789, the digit 6 represents 600 (six hundred), while the digit 8 represents 0.08 (eight hundredths).

位值问题常要求找出大数或小数中某一位的具体数值。例如,在数字 45 623.789 中,数字 6 表示 600(六百),而数字 8 表示 0.08(百分之八)。

A typical question: Write the value of the digit 3 in the number 4.376. The answer is 0.3 or 3/10 (three tenths). To round 7892 to the nearest hundred, look at the tens digit (9); since it is 5 or above, round up to 7900.

常见题型:写出数字 4.376 中数字 3 的数值。答案是 0.3 或 3/10(十分之三)。将 7892 四舍五入到最近的百位数时,看十位数字(9),由于大于等于 5,向上舍入为 7900。

DigitPlace Value
7 (in 7892)7000
8800
990
22

Common mistake: confusing '0.3' with '0.03'. Always count the decimal places after the point.

常见错误:混淆“0.3”与“0.03”。务必数清小数点后的位数。


2. Addition and Subtraction in Context | 情景中的加减法

Multi-step word problems test calculation accuracy. For instance: 'A cinema has 324 seats. 156 adults and 89 children enter. How many seats are left?' First, 156 + 89 = 245, then 324 - 245 = 79. Answer: 79 seats remain.

多步应用题考查计算准确性。例如:“一家电影院有 324 个座位,入场了 156 位成人和 89 位儿童。还剩多少空座?”先算 156 + 89 = 245,再算 324 - 245 = 79。答案:还剩 79 个座位。

the positive, so -5 + 9 = 4. Using a number line helps visualise the jump from -5 up to 4.

涉及负数的题目经常出现:计算 -5 - (-9)。减去一个负数等于加上它的相反数,所以 -5 + 9 = 4。借助数轴可以直观看到从 -5 跳到 4 的过程。

-5 - (-9) = -5 + 9 = 4

Always check borrowing in column subtraction, particularly when zeros are involved, e.g. 2003 - 867.

列竖式减法时务必检查借位,尤其是出现连续的零时,比如 2003 - 867。


3. Multiplication, Division, and BODMAS | 乘除法与运算顺序

9. Then indices: 8² = 64. Next multiplication: 9 × 3 = 27. Finally addition: 27 + 64 = 91.

运算顺序在 7C 练习中至关重要。典型题目:计算 (15 - 6) × 3 + 8²。按照 BODMAS/BIDMAS 顺序,先算括号:15 - 6 = 9。再算指数:8² = 64。接着乘法:9 × 3 = 27。最后加法:27 + 64 = 91。

d 47 × 8 = 376. Adding them gives 1786. Answers must be checked for place value alignment.

两位数乘法如 47 × 38 要注意书写格式。将 38 拆成 30 和 8:47 × 30 = 1410,47 × 8 = 376。相加得 1786。答案必须核对数位对齐。

4 = 21.25 or 21¼. Students should be confident converting remainders into fractional form.

除法题常将余数表示为分数或小数:85 ÷ 4 = 21.25 或 21¼。学生应熟练掌握将余数转化为分数形式。


4. Fundamentals of Fractions | 分数基础

Equivalent fractions and simplifying are tested. Write 18/24 in simplest form. The highest common factor of 18 and 24 is 6, so divide both by 6 to get 3/4.

等效分数与约分是考点。将 18/24 化为最简形式。18 和 24 的最大公因数是 6,分子分母同除以 6 得到 3/4。

18/24 ÷ 6/6 = 3/4

Comparing fractions requires a common denominator. Which is larger, 3/5 or 5/8? LCM of 5 and 8 is 40. 3/5 = 24/40, 5/8 = 25/40, so 5/8 is larger.

比较分数大小时需通分。3/5 和 5/8 哪个更大?5 和 8 的最小公倍数是 40。3/5 = 24/40,5/8 = 25/40,因此 5/8 更大。

Finding a fraction of an amount: Work out 2/5 of 35. Divide by the denominator: 35 ÷ 5 = 7, then multiply by the numerator: 7 × 2 = 14.

求一个数的几分之几:计算 35 的 2/5。先除以分母:35 ÷ 5 = 7,再乘以分子:7 × 2 = 14。

Mixed numbers and improper fractions conversions appear regularly. 23/4 = 11/4 because 2 × 4 + 3 = 11.

带分数与假分数互化经常出现。23/4 = 11/4,因为 2 × 4 + 3 = 11。


5. Decimals and Percentages | 小数与百分数

Interconversion between fractions, decimals and percentages is a core skill. 0.125 equals 125/1000, which simplifies to 1/8, and as a percentage it is 12.5%.

分数、小数、百分数的互化是一项核心技能。0.125 等于 125/1000,约分为 1/8,换成百分数为 12.5%。

original numbers have one decimal place each, so the answer has two decimal places: 0.12.

小数乘法:0.6 × 0.2。先忽略小数点:6 × 2 = 12。原数各有一位小数,共两位小数,答案为 0.12。

0.6 × 0.2 = 0.12

Percentage of amounts: Find 15% of £200. 10% = £20, 5% = £10, so 15% = £30. Alternatively, multiply 200 by 0.15.

求百分比数值:计算 £200 的 15%。10% = £20,5% = £10,因此 15% = £30。也可用 200 × 0.15 计算。

A table often helps students remember conversions:

FractionDecimalPercentage
1/20.550%
1/40.2525%
3/40.7575%
1/100.110%

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6. Algebra: Expressions and Simple Equations | 代数:表达式与简易方程

a + 2b - a + 3b. Group a terms: 3a - a = 2a. Group b terms: 2b + 3b = 5b. Answer: 2a + 5b.

合并同类项化简表达式是常见题型。化简 3a + 2b - a + 3b。合并 a 项:3a - a = 2a。合并 b 项:2b + 3b = 5b。答案:2a + 5b。

2x = 8. Divide both sides by 2: x = 4. Always verify by substituting back: 2(4) + 3 = 11.

解一步或两步方程:解 2x + 3 = 11。两边同时减 3:2x = 8。两边除以 2:x = 4。务必代入验证:2(4) + 3 = 11。

2x + 3 = 11 → x = 4

a = 3 and b = -2, find the value of 4a - b. Substituting gives 4(3) - (-2) = 12 + 2 = 14.

代入求值题:已知 a = 3,b = -2,求 4a - b 的值。代入得 4(3) - (-2) = 12 + 2 = 14。


7. Geometry: Angles and Lines | 几何:角与线

°. If one angle is 67°, the other is 180° - 67° = 113°. Around a point, angles total 360°.

测试直线与周角的角度性质。直线上所有角的和为 180°。若一个角是 67°,另一个角为 180° - 67° = 113°。绕一点一周的角总和为 360°。

Vertically opposite angles are equal. In a diagram with two intersecting lines, the angle opposite 45° is also 45°. This is frequently used alongside complementary and supplementary relationships.

对顶角相等。在两线相交的图中,45° 的对顶角也是 45°。这一性质常与互余、互补关系结合考查。

sosceles triangles have two equal base angles; identifying them helps find missing angles.

三角形内角和为 180°。已知两角分别为 54° 和 73°,则第三角 = 180° - (54° + 73°) = 53°。等腰三角形两底角相等,识别这一点可求出未知角。


8. Measurement: Perimeter and Area | 测量:周长与面积

26 cm. For composite shapes, ensure all outer sides are added without missing hidden lengths.

矩形与组合图形的周长:长 8 cm、宽 5 cm 的矩形周长为 2(8+5) = 26 cm。对于组合图形,应确保所有外边长都相加,不要遗漏隐藏边。

ase × height) ÷ 2. A triangle with base 10 m and height 6 m has area (10 × 6) ÷ 2 = 30 m².

矩形面积 = 长 × 宽。上述矩形面积为 8 × 5 = 40 cm²。三角形面积 = (底 × 高) ÷ 2。底 10 m、高 6 m 的三角形面积 = (10 × 6) ÷ 2 = 30 m²。

Area of triangle = (b × h) ÷ 2

Answers must include correct units (cm, cm², m, etc.) and distinguish between perimeter (linear) and area (square). Converting units, such as from mm² to cm², often causes errors.

答案必须注明正确单位(cm、cm²、m 等),并区分周长(长度单位)与面积(平方单位)。单位换算如 mm² 转为 cm² 常导致出错。


9. Statistics: Mean and Charts | 统计:平均数与图表

(most frequent). The median, after ordering 5,7,8,8,12, is 8, and the range is 12 - 5 = 7.

计算平均数:得分 5、8、12、7、8 总和为 40。共有 5 个数,因此平均数为 40 ÷ 5 = 8。众数为 8(出现最频繁)。中位数按顺序 5、7、8、8、12 处于中间的是 8,全距为 12 - 5 = 7。

Interpreting bar charts and pictograms: A bar chart showing favourite fruits may ask, 'How many more chose apples than pears?' frequency of pears from apples. In pictograms, check the key (e.g. one symbol = 4 pupils).

解读条形图和象形图:显示最喜欢的水果的条形图可能问“选择苹果的比选择梨子的多几人?”用苹果的频数减去梨子的频数。在象形图中,注意图例(例如一个符号代表 4 名学生)。

A common answer style: 'The mean is 8, which represents the typical score, but the range of 7 shows a fair spread in data.' This connects calculation with interpretation.

常见答案风格:“平均数为 8,代表典型的得分水平,但全距 7 显示数据分布较广。”这将计算与解释联系起来。


10. Ratio and Proportion | 比和比例

Simplifying ratios: Write 8:12 in simplest form. The highest common factor of 8 and 12 is 4, so divide both by 4 to get 2:3. Ratios must be kept in the same order as the problem states.

化简比:将 8:12 写成最简形式。8 和 12 的最大公因数为 4,同除以 4 得 2:3。比的顺序必须与题目给出的顺序一致。

Sharing in a given ratio: Share £60 in the ratio 2:3. Total parts = 2 + 3 = 5. One part = £60 ÷ 5 = £12. The first share is 2 × £12 = £24, the second share is 3 × £12 = £36.

按比例分配:将 £60 按 2:3 分配。总份数 = 2 + 3 = 5。一份 = £60 ÷ 5 = £12。第一份为 2 × £12 = £24,第二份为 3 × £12 = £36。

Share £60 in 2:3 → £24 and £36

Proportion problems: If 5 pencils cost 75p, what do 8 pencils cost? Find the unit cost: 75 ÷ 5 = 15p per pencil. Then 8 × 15p = 120p or £1.20.

比例问题:若 5 支铅笔 75p,8 支铅笔多少钱?先求单价:75 ÷ 5 = 15p 每支。然后 8 × 15p = 120p,即 £1.20。


11. Sequences and Patterns | 数列与规律

term = 4n + 1 (since 4×1 + 1 = 5). To find the 20th term, substitute n=20: 4(20) + 1 = 81.

求线性数列的第 n 项:5, 9, 13, 17,... 公差为 4。第 n 项 = 4n + 1(因为 4×1 + 1 = 5)。求第 20 项,代入 n=20:4(20) + 1 = 81。

Generating terms: 'Write the first three terms of the sequence with nth term 3n - 2.' For n=1: 3(1)-2=1; n=2: 4; n=3: 7. Answer: 1, 4, 7.

写出数列的前几项:“写出第 n 项为 3n - 2 的数列的前三项。” n=1 时:3(1)-2=1;n=2:4;n=3:7。答案:1, 4, 7。

Picture sequences, such as dot patterns, follow similar linear rules. Count dots and model with 2n+3 type expressions.

图案序列(如点阵)遵循类似的线性规律。

Published by TutorHao | KS3 Mathematics Revision Series | aleveler.com

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