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Year 11 Eduqas Maths: Case Study Practical Walkthroughs | Eduqas 数学案例分析实战演练

2026-07-20 20:16 · 本文部分内容由AI辅助创作

📚 Year 11 Eduqas Maths: Case Study Practical Walkthroughs | Eduqas 数学案例分析实战演练

Case studies in Eduqas GCSE Maths test your ability to apply mathematical concepts to real-life scenarios. This article provides a structured approach, from reading the problem to verifying your answer, using worked examples across topics like percentages, geometry, and statistics.

Eduqas GCSE 数学中的案例分析题考查你将数学概念应用于实际情境的能力。本文将提供一种结构化的解题方法,从阅读问题到验证答案,并配合百分比、几何和统计等主题的实例讲解。


1. Understanding the Case Study Context | 理解案例背景

Start by reading the entire problem statement slowly. Underline key information: numbers, units, and what exactly is being asked. Is the final answer expected in pounds, metres, or as a percentage? Identify the 'story'—it might be about shopping, travel, or a school event.

先慢慢通读整个问题陈述。划出关键信息:数字、单位以及最终要求什么。答案是英镑、米还是百分比?识别'故事'背景——可能是购物、旅行或学校活动。


2. Extracting Data and Units | 提取数据和单位

List all given values with their units. Common units in Eduqas case studies include £, kg, m, cm, minutes, and km. Watch out for mixed units—you may need to convert everything to the same unit before calculating. For example, 1.5 km and 800 m should both be in metres.

列出所有给定的值及其单位。Eduqas 案例中常见的单位有 £、kg、m、cm、分钟和 km。注意混合单位——你可能需要先统一单位再计算。例如 1.5 km 和 800 m 都应转换为米。


3. Identifying the Maths Topics | 确定数学知识点

down the formulas you might need, such as speed = distance ÷ time, or percentage change = (difference ÷ original) × 100.

判断需要哪些数学技能。一个案例分析通常会混合多个主题:百分比、比例、面积、平均值或读图。写下可能需要的公式,如速度 = 距离 ÷ 时间,或百分比变化 =(差值 ÷ 原值)× 100。


4. Planning a Step-by-step Strategy | 制定分步策略

Break the problem into smaller tasks. For instance, if you need to find the total cost of tiling a floor, first calculate the floor area, then the number of tiles, then the number of boxes, and finally the total price. Number each step to stay organised.

将问题分解为更小的任务。例如,如果需要计算铺设地板的总费用,先算地板面积,再算所需地砖数量,再算要多少箱,最后算总价。给每一步编号,保持条理。


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5. Case Study 1: Best Value Shopping | 案例分析1:最佳购物性价比

A shop sells the same brand of rice in three different packs. Pack A: 500 g for £1.20. Pack B: 750 g for £1.70. Pack C: 2 kg for £4.50, with a 'buy one get one half price' offer on Pack C. Which pack gives the lowest price per 100 g when you buy two Pack C bags?

一家商店以三种不同包装出售同一个品牌的大米。A 包:500 g 售价 £1.20。B 包:750 g 售价 £1.70。C 包:2 kg 售价 £4.50,且 C 包有'买一送一半价'优惠。如果购买两包 C,哪种包装每 100 g 的单价最低?

Step 1: Calculate price per gram for Pack A. 500 g costs £1.20, so cost per gram = 1.20 ÷ 500 = £0.0024. Per 100 g = 0.0024 × 100 = £0.24.

步骤1:计算 A 包每克价格。500 g 花费 £1.20,所以每克成本 = 1.20 ÷ 500 = £0.0024。每 100 g = 0.0024 × 100 = £0.24。

Step 2: Pack B: 1.70 ÷ 750 = £0.002267 per gram, so per 100 g = £0.2267 (about 22.7 pence).

步骤2:B 包:1.70 ÷ 750 = £0.002267 每克,所以每 100 g = £0.2267(约 22.7 便士)。

Step 3: Pack C offer: two packs cost £4.50 + (50% of £4.50) = £4.50 + £2.25 = £6.75 for 2 × 2 kg = 4 kg. Cost per gram = 6.75 ÷ 4000 = £0.0016875, per 100 g = £0.16875. This is the best value.

步骤3:C 包优惠:两包价格 = £4.50 + (50% × £4.50) = £4.50 + £2.25 = £6.75,总重 2 × 2 kg = 4 kg。每克成本 = 6.75 ÷ 4000 = £0.0016875,每 100 g = £0.16875。这是最划算的。

Comparative table:

对比表格:

PackWeight (g)Total cost (£)Price per 100 g (£)
A5001.200.240
B7501.700.227
C (offer)40006.750.169

6. Case Study 2: Floor Tiling Project | 案例分析2:地板铺砖工程

A rectangular room measures 4.8 m by 3.5 m. Square tiles of side 40 cm are to be laid. Tiles are sold in boxes of 12, priced at £28.80 per box. The shop recommends buying 5% extra to allow for cutting and breakages. Calculate the total cost of tiles needed.

一个长方形房间尺寸为 4.8 m × 3.5 m,需要铺设边长为 40 cm 的正方形地砖。地砖每箱 12 块,价格 £28.80。商店建议多买 5% 以预留切割和破损。计算所需地砖的总费用。

Convert all to the same unit. Room dimensions in cm: 480 cm by 350 cm. Tile side = 40 cm.

步骤1:统一单位。房间尺寸以厘米计:480 cm × 350 cm。地砖边长 = 40 cm。

one tile = 40 × 40 = 1600 cm². Number of tiles without waste = 168,000 ÷ 1600 = 105 tiles.

步骤2:房间面积 = 480 × 350 = 168,000 cm²。一块地砖面积 = 40 × 40 = 1600 cm²。不计损耗所需地砖数 = 168,000 ÷ 1600 = 105 块。

Step 3: Add 5% extra

Published by TutorHao | Year 11 Mathematics Revision Series | aleveler.com

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