📚 Interdisciplinary Integrated Question Practice for Year 11 WJEC Physics | WJEC物理跨学科综合题型训练
This article presents a series of typical interdisciplinary questions that combine WJEC Year 11 Physics with biology, chemistry, geography, sports science, and engineering. Each worked example demonstrates how core physical principles are applied beyond the laboratory, reinforcing your ability to analyse unfamiliar contexts and integrate knowledge across subjects.
本文呈现一系列典型的跨学科题型，将WJEC 11年级物理与生物、化学、地理、体育科学及工程学相结合。每个范例展示核心物理原理如何在实验室之外应用，强化你分析陌生情境、跨学科整合知识的能力。
1. Levers in the Human Body: Biomechanics | 人体杠杆：生物力学
n effort force close to the elbow, while the weight in the hand is the load. Using moments: Effort × effort arm = Load × load arm. If the load is 50 N held 0.35 m from the elbow, and the biceps attaches 0.05 m from the elbow, the muscle force needed is F = (50 N × 0.35 m) / 0.05 m = 350 N. This shows muscles exert forces much larger than the loads lifted.
在生物力学中，杠杆原理可解释肌肉如何产生运动。以前臂为杠杆，肘关节为支点。肱二头肌在靠近肘关节处施加动力，手中重物为阻力。利用力矩平衡：动力 × 动力臂 = 阻力 × 阻力臂。若手托重物50 N距肘0.35 m，二头肌附着点距肘0.05 m，则肌肉力 F = (50 N × 0.35 m) / 0.05 m = 350 N。这表明肌肉需施加远大于负荷的力。
2. Electrical Signals and the Heart: ECG Physics | 心电信号：心电图物理
k up these voltages through the skin, which acts as a resistor. The measured voltage V = E – readings. Physics helps optimise electrode materials and circuit design to minimise noise.
心电图(ECG)记录心肌细胞去极化产生的微小电势差。电极通过皮肤拾取这些电压，皮肤相当于电阻。测得的电压 V = E - Ir，其中E为生物电源，r为皮肤电阻。良好的电极接触（低电阻）可确保准确读数。物理学有助于优化电极材料和电路设计以降低噪声。
3. Fuels and Energy: Calorimetry | 燃料与能量：量热学
er. Using the equation ΔQ = m c Δθ, where m is mass of water, c = 4200 J/kg°C, and Δθ the temperature rise. If 2 g of a fuel raises 100 g water by 15°C, energy transferred = 0.1 kg × 4200 × 15 = 6300 J. The energy per gram = 3150 J/g. This links chemistry (bond energies) with physics (energy conservation).
燃烧燃料将化学能转化为内（热）能。在量热实验中，燃料释放的热量用来加热水。利用方程 ΔQ = m c Δθ，m为水的质量，c = 4200 J/kg°C，Δθ为温升。若2 g燃料使100 g水温升15°C，传递的能量 = 0.1 kg × 4200 × 15 = 6300 J。每克能量 = 3150 J/g。这关联了化学（键能）和物理（能量守恒）。
4. Ultrasound Imaging: Wave Physics | 超声成像：波动物理学
reflecting surface is d = v t / 2, where v ≈ 1540 m/s in soft tissue, and t is the round-trip time. If a pulse returns after 80 μs, d = (1540 × 80 × 10⁻⁶) / 2 = 0.0616 m (6.16 cm). The wavelength λ = v / f; for f = 5 MHz, λ = 1540 / (5 × 10⁶) = 3.08 × 10⁻⁴ m. This resolution enables detecting small structures. Physics underpins diagnostic sonography.
超声成像利用高频声波来显示内部器官。换能器发射脉冲并检测回声。反射面距离 d = v t / 2，软组织中的 v ≈ 1540 m/s，t 是往返时间。若脉冲在80 μs后返回，d = (1540 × 80 × 10⁻⁶) / 2 = 0.0616 m (6.16 cm)。波长 λ = v / f；频率 f = 5 MHz 时，λ = 1540 / (5 × 10⁶) = 3.08 × 10⁻⁴ m。这种分辨率可检测微小结构。物理学是诊断超声的基础。
5. Radioactive Decay and Medicine: Half-life Calculations | 放射性衰变与医学：半衰期计算
Radioactive tracers like technetium‑99m (Tc‑99m) are used in medical imaging. Its half‑life T₁/₂ = 6 hours. The activity A after time t is A = A₀ (½
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