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Year 11 OCR PE: Unit Test Mock Paper Walkthrough | Year 11 OCR 体育:单元测试模拟卷解析

2026-07-20 14:23 · 本文部分内容由AI辅助创作

📚 Year 11 OCR PE: Unit Test Mock Paper Walkthrough | Year 11 OCR 体育:单元测试模拟卷解析

This walkthrough covers a mock unit test designed for the OCR GCSE (9–1) Physical Education specification, specifically targeting topics from Component 01: Physical Factors Affecting Performance. Each question is modelled on real exam style, with detailed model answers and examiner insights to help you understand exactly what is required for top marks. Use this as a revision tool to test your knowledge and improve your exam technique.

本解析针对 OCR GCSE(9–1)体育学科组件01“影响运动表现的身体因素”设计的一套单元测试模拟卷。每道题目都仿照真实考试风格,并配有详细的参考答案与考官点评,帮助你准确理解高分所需的内容。可将此作为复习工具,检验知识掌握程度并提升应试技巧。

1. Cardiac Output Response to Exercise | 运动时的心输出量反应

Question: Explain how cardiac output changes during a 1500 m race and why this change is necessary for performance. (4 marks)

问题:解释在1500米跑过程中,心输出量如何变化,并说明这种变化为何对运动表现至关重要。(4分)

At the start of the race, cardiac output (Q) increases rapidly due to a rise in both heart rate (HR) and stroke volume (SV). As exercise continues, SV plateaus at around 40–60% of maximum effort, so further increases in Q are driven almost entirely by HR. Cardiac output may reach values of 20–25 L/min in a trained athlete. This elevation is essential because working muscles require more oxygen for aerobic respiration and need to remove carbon dioxide efficiently. A higher Q ensures enhanced oxygen delivery and waste removal, delaying fatigue and maintaining a high work rate.

在比赛开始阶段,心输出量(Q)因心率(HR)和每搏输出量(SV)同时增加而快速上升。随着运动继续,每搏输出量在大约40–60%最大用力时趋于平稳,因此后续心输出量的提升几乎完全由心率驱动。训练有素的运动员心输出量可达20–25升/分钟。这种升高至关重要,因为工作的肌肉需要更多氧气来进行有氧呼吸,并且需要高效清除二氧化碳。更高的心输出量保证了充足的氧气供应和废物排出,从而延缓疲劳并维持高强度的运动表现。

Cardiac Output (Q) = Stroke Volume (SV) × Heart Rate (HR)

心输出量(Q)= 每搏输出量(SV)× 心率(HR)


2. Components of a Lever System | 杠杆系统的组成

Question: Using a sporting example, identify the three components of a lever system and explain how they interact to produce movement. (3 marks)

问题:以一个运动实例说明杠杆系统的三个组成部分,并解释它们如何相互作用以产生运动。(3分)

In a bicep curl, the lever system consists of a fulcrum (the elbow joint), an effort (the force produced by the biceps muscle), and a load (the weight in the hand). The biceps contracts, pulling on the radius, which rotates the forearm around the elbow. This is a third-class lever because the effort is applied between the fulcrum and the load. The effort must therefore be greater than the load, but the arrangement allows a large range of motion and speed at the distal end of the lever.

在肱二头肌弯举中,杠杆系统由支点(肘关节)、动力(肱二头肌产生的力)和阻力(手中的重量)组成。肱二头肌收缩,牵拉桡骨,使前臂绕肘关节旋转。这是一个第三类杠杆,因为动力作用在支点和阻力之间。因此动力必须大于阻力,但这种排列使得杠杆远端能够获得较大的活动幅度和速度。


3. Aerobic vs Anaerobic Respiration | 有氧呼吸与无氧呼吸

Question: Compare aerobic and anaerobic respiration in terms of oxygen use, energy yield, and by-products. Give a sporting situation where each is dominant. (6 marks)

问题:从氧气使用、能量产出和副产物的角度比较有氧呼吸和无氧呼吸,并分别举出以各方式为主导的运动情境。(6分)

Aerobic respiration uses oxygen to break down glucose and fatty acids, producing a large amount of ATP (approximately 38 molecules per glucose), carbon dioxide, and water. It is the dominant energy pathway during prolonged, moderate-intensity activities such as a marathon. Anaerobic respiration occurs without oxygen, yields only 2 ATP per glucose molecule, and produces lactic acid as a by-product. It dominates in short, high-intensity bursts such as a 100 m sprint. The lactate accumulation contributes to muscular fatigue if not cleared. While the aerobic system offers high energy yield and sustainability, the anaerobic system provides immediate energy but is limited in duration.

有氧呼吸利用氧气分解葡萄糖和脂肪酸,产生大量ATP(每分子葡萄糖约38个)、二氧化碳和水。它是持续时间长、中等强度活动(例如马拉松)中的主导供能路径。无氧呼吸在无氧条件下进行,每分子葡萄糖仅产生2个ATP,并生成乳酸作为副产物。它的主导情境是短时高强度爆发,例如100米短跑。若乳酸未被及时清除,其积累会导致肌肉疲劳。有氧系统产能高且持久,而无氧系统能提供即时能量但持续时间有限。


4. Respiratory System Responses During Exercise | 运动中呼吸系统的反应

Question: Describe the immediate responses of the respiratory system to exercise and explain the role of the diaphragm and intercostal muscles. (4 marks)

问题:描述运动时呼吸系统的即时反应,并解释膈肌和肋间肌的作用。(4分)

At the onset of exercise, breathing rate (frequency) and tidal volume increase, leading to a rise in minute ventilation. The diaphragm contracts more forcefully and flattens, while the external intercostal muscles lift the ribcage upwards and outwards. These actions expand the thoracic cavity, lowering intrapulmonary pressure so that air rushes into the lungs. During expiration, the internal intercostal muscles and abdominal muscles assist in forcing air out more rapidly. These adjustments maximise oxygen uptake and carbon dioxide removal.

运动一开始,呼吸频率和潮气量增加,导致每分通气量上升。膈肌更有力地收缩并变平,同时外肋间肌将胸廓向上向外提拉。这些动作扩大了胸腔容积,降低了肺内压,使空气被吸入肺内。呼气时,内肋间肌和腹肌协助更快地将气体排出。这些调节最大化了氧气的摄入和二氧化碳的排出。


5. Slow-Twitch and Fast-Twitch Muscle Fibres | 慢肌纤维与快肌纤维

Question: Outline the structural and functional differences between Type I and Type IIx muscle fibres and suggest a sport where each type would be an advantage. (5 marks)

问题:概述I型与IIx型肌纤维在结构和功能上的差异,并指出各类型在哪种运动项目中占优势。(5分)

Type I (slow-twitch) fibres have a high density of mitochondria, myoglobin, and capillaries, giving them a red appearance and a high aerobic capacity. They contract slowly but are very resistant to fatigue, making them suited to endurance events such as distance cycling. Type IIx (fast-twitch) fibres contain fewer mitochondria, lower myoglobin levels, and rely more on anaerobic glycolysis. They contract rapidly and generate high force but fatigue quickly. They are advantageous in explosive events like shot put or 100 m sprinting. A marathon runner would possess a greater proportion of Type I fibres, whereas a powerlifter would have more Type IIx fibres.

I型(慢肌)纤维富含线粒体、肌红蛋白和毛细血管,呈红色并具有较高的有氧能力。它们收缩速度慢但抗疲劳能力强,适合如长距离自行车等耐力项目。IIx型(快肌)纤维线粒体较少,肌红蛋白水平低,更依赖无氧糖酵解。它们收缩快、力量大但易疲劳,在铅球或100米短跑等爆发性项目中占优势。马拉松运动员会拥有更高比例的I型纤维,而力量举运动员则拥有更多IIx型纤维。


6. Planes and Axes of Movement | 运动平面和运动轴

Question: For a footballer performing a right-footed pass, identify the plane and axis around which the movement primarily occurs. Explain your choice. (3 marks)

问题:对于足球运动员用右脚传球的动作,指出该动作主要发生在哪个平面和绕哪个轴,并解释你的选择。(3分)

The movement occurs in the sagittal plane about a frontal (mediolateral) axis. When the player swings the right leg forward to strike the ball, the motion runs parallel to the sagittal plane, which divides the body into left and right halves. The rotation happens around the frontal axis, which runs from side to side, allowing flexion and extension at the hip and knee. This combination produces the forward swing of the kicking leg.

该动作发生在矢状面,绕额状轴(内外侧轴)进行。当球员向前摆动右腿击球时,运动方向与将身体分为左右两半的矢状面平行。旋转绕额状轴(左右走向)发生,允许髋关节和膝关节进行屈伸。这一组合产生了踢球腿的向前摆动。


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7. Vascular Shunting During Exercise | 运动中的血管分流

Question: Describe the process of vascular shunting at the start of a 400 m run. Why is this mechanism important? (4 marks)

问题:描述400米跑开始时血管分流的过程。为什么这一机制至关重要?(4分)

At the onset of exercise, the sympathetic nervous system causes vasodilation of arterioles supplying working skeletal muscles, increasing blood flow to them. At the same time, vasoconstriction occurs in arterioles leading to non-essential organs such as the digestive system and kidneys. This redistribution of blood is known as vascular shunting. The process ensures that a greater percentage of cardiac output is directed towards active muscles, enhancing oxygen delivery and waste removal. During a 400 m sprint, this mechanism helps delay the accumulation of lactate and maintain high-intensity performance.

运动开始时,交感神经系统促使供应工作骨骼肌的小动脉血管舒张,增加其血流量。同时,通向非必需器官(如消化系统和肾脏)的小动脉发生血管收缩。这种血流的重新分配即血管分流。该过程确保更大比例的心输出量被导向活跃肌肉,提升氧气供应和废物清除。在400米跑中,这一机制有助于延缓乳酸堆积,维持高强度表现。


8. Maximal Oxygen Uptake (VO₂ max) | 最大摄氧量(VO₂ max)

Question: Define VO₂ max and explain three factors that can influence an individual's VO₂ max. (4 marks)

问题:定义VO₂ max,并解释影响个人VO₂ max的三个因素。(4分)

VO₂ max is the maximum volume of oxygen that can be taken in, transported, and utilised by the body per minute. It is measured in ml/kg/min and is a key indicator of aerobic endurance capacity. Three factors influencing VO₂ max are: genetics – which determines the proportion of slow-twitch fibres and heart size; training – endurance training can increase stroke volume, blood volume, and mitochondrial density; and age – VO₂ max generally peaks in the mid-20s and declines thereafter. Gender also plays a role, with males typically having higher absolute values due to larger heart and lung volumes.

VO₂ max 是指人体每分钟能够摄入、运输并利用的最大氧气量,单位为毫升/公斤/分钟,是有氧耐力能力的关键指标。影响VO₂ max的三个因素包括:遗传——决定了慢肌纤维比例和心脏大小;训练——耐力训练可增加每搏输出量、血容量和线粒体密度;年龄——VO₂ max通常在25岁左右达到峰值,随后下降。性别也会产生影响,男性由于心肺体积较大,绝对数值通常更高。

VO₂ max = Cardiac Output × Arteriovenous Oxygen Difference

最大摄氧量 = 心输出量 × 动静脉氧差


9. Excess Post-Exercise Oxygen Consumption (EPOC) | 运动后过量氧耗

Question: What is EPOC and why does it occur after a high-intensity interval training (HIIT) session? (4 marks)

问题:什么是EPOC,为什么在高强度间歇训练(HIIT)后会出现EPOC?(4分)

EPOC stands for Excess Post-Exercise Oxygen Consumption, representing the elevated oxygen uptake above resting levels following strenuous exercise. After a HIIT session, the body must restore phosphocreatine stores, convert accumulated lactate back to glucose in the liver (Cori cycle), replenish oxygen bound to myoglobin, and return body temperature and heart rate to resting levels. These processes require additional ATP, which is generated aerobically, hence the increased oxygen consumption. The intensity of the exercise directly influences the magnitude and duration of EPOC.

EPOC 指运动后过量氧耗,即剧烈运动后氧气摄取量高于安静水平的阶段。一次HIIT训练后,身体需要恢复磷酸肌酸储备、在肝脏将积累的乳酸转化为葡萄糖(科里循环)、补充与肌红蛋白结合的氧,并使体温和心率恢复至安静水平。这些过程都需要额外的ATP,而有氧途径会生成ATP,因此导致氧气消耗量增加。运动强度直接影响EPOC的大小和持续时间。


10. Lactic Acid Accumulation and Performance | 乳酸堆积与运动表现

Question: Explain how lactic acid is produced during intense exercise and describe its effects on muscular performance. (5 marks)

问题:解释高强度运动中乳酸是如何产生的,并描述其对肌肉表现的影响。(5分)

When exercise intensity exceeds the point at which oxygen delivery can meet the demands of aerobic respiration, ATP is resynthesised through anaerobic glycolysis. Pyruvate, the end-product of glycolysis, is converted into lactic acid by the enzyme lactate dehydrogenase. Lactic acid rapidly dissociates into lactate and hydrogen ions (H⁺). The accumulation of hydrogen ions lowers the pH inside the muscle cell, inhibiting key glycolytic enzymes and interfering with calcium binding in the contractile process. This results in reduced muscular contraction force, a sensation of burning, and ultimately fatigue, forcing the athlete to slow down.

当运动强度超过有氧呼吸所能提供的氧气供应时,ATP通过无氧糖酵解再合成。糖酵解的终产物丙酮酸在乳酸脱氢酶的作用下转化为乳酸。乳酸迅速解离为乳酸根离子和氢离子(H⁺)。氢离子的积累降低了肌细胞内的pH,抑制关键的糖酵解酶,并干扰收缩过程中钙离子的结合,导致肌肉收缩力量下降,出现灼烧感,并最终产生疲劳,迫使运动员减速。


11. Movement Analysis in a Tennis Serve | 网球发球的动作分析

Question: Analyse the joint actions and muscle contractions occurring at the shoulder and elbow during the acceleration phase of a tennis serve. (6 marks)

问题:分析在网球发球的加速阶段,肩关节和肘关节发生的关节动作与肌肉收缩形态。(6分)

During the acceleration phase, the hitting shoulder moves through a combination of horizontal flexion and medial rotation. The prime movers for these actions are the pectoralis major and anterior deltoid (horizontal flexion) and the subscapularis and latissimus dorsi (medial rotation). All these muscles contract concentrically to accelerate the arm forward. At the elbow, rapid extension occurs, driven by the concentric contraction of the triceps brachii. The movement sequence starts with the powerful rotation of the shoulder, followed by the forceful straightening of the elbow, transferring momentum into the racket head for maximum ball speed.

在加速阶段,持拍侧的肩关节进行水平屈和内旋的组合动作。完成水平屈的原动肌是胸大肌和三角肌前束,而肩胛下肌和背阔肌负责内旋,这些肌肉均向心收缩以加速手臂前移。肘关节则发生快速伸展,由肱三头肌的向心收缩驱动。动作顺序从肩部的强力旋转开始,随后肘部强力打直,将动量传递至拍头,以实现最高球速。


12. Data Interpretation: Heart Rate Response | 数据解读:心率反应

Question: A performer's heart rate is recorded as 60 bpm at rest, 110 bpm after a 5‑minute warm‑up, 172 bpm during a competitive match, and 135 bpm two minutes after the match. Interpret these values and explain the underlying mechanisms. (5 marks)

问题:一名运动员的心率记录为:安静时60 bpm,5分钟热身后110 bpm,竞技比赛中172 bpm,赛后两分钟135 bpm。解读这些数据并解释背后的机制。(5分)

Resting heart rate of 60 bpm indicates good cardiovascular fitness, likely due to a higher stroke volume. The rise to 110 bpm after the warm‑up is caused by the anticipatory response of the sympathetic nervous system, increasing HR even before intense activity. During the match, HR reaches near-maximal levels (172 bpm), driven by the demand for oxygen by working muscles and the activity of the cardiac control centre. The drop to 135 bpm two minutes post‑match demonstrates the initial fast recovery phase, where parasympathetic reactivation slows the heart. The speed of this decline is an indicator of fitness; a well-trained athlete shows a quicker drop. Remaining elevation still reflects EPOC and metabolic recovery.

安静心率60 bpm表明心血管机能良好,可能与较高的每搏输出量有关。热身结束后心率升至110 bpm,这是交感神经的预期性反应所致,即使在剧烈活动开始前心率已上升。比赛中,心率达到接近最大值的172 bpm,这是因为工作肌肉需氧量激增以及心搏控制中枢的驱动。赛后两分钟心率降至135 bpm,体现了初始的快速恢复阶段,此时副交感神经重新激活降低心率。这种下降速度是体能的指标之一;训练有素的运动员下降更快。心率的残余升高仍反映了EPOC和代谢恢复过程。


Published by TutorHao | Physical Education Revision Series | aleveler.com

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