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Year 10 Eduqas Engineering – Interdisciplinary Integrated Question Training | Year 10 Eduqas 工程:跨学科综合题型训练

2026-07-20 10:42 · 本文部分内容由AI辅助创作

📚 Year 10 Eduqas Engineering – Interdisciplinary Integrated Question Training | Year 10 Eduqas 工程:跨学科综合题型训练

Welcome to this focused revision guide designed to help Year 10 students master the interdisciplinary nature of the Eduqas Engineering exam. Real-world engineering problems rarely fall into a single subject category – they combine mathematics, physics, material science, design, and systems thinking. The exam will test your ability to draw connections across these areas, so practising integrated questions is essential.

欢迎使用这份针对 Year 10 学生的专项复习指南,旨在帮助你掌握 Eduqas 工程考试中的跨学科特性。现实世界的工程问题很少属于单一学科类别——它们结合了数学、物理、材料科学、设计以及系统思维。考试会考查你在这些领域之间建立联系的能力,因此进行综合题型训练至关重要。


1. Understanding Interdisciplinary Integration | 理解跨学科整合

Interdisciplinary integration means that a single exam question may ask you to calculate a mechanical load, select an appropriate material based on cost and properties, and justify your choice using scientific principles – all in one scenario. Understanding how these layers fit together is the first step.

跨学科整合意味着同一道考题可能会要求你计算机械载荷、根据成本和性能选择合适的材料,并运用科学原理证明你的选择——所有这些都在同一个场景中。理解这些层次如何结合是第一步。

For example, a typical Eduqas question might describe a drone frame that must be lightweight yet strong. You would need to calculate the stress on the frame (physics/mechanics), pick a material from a table of properties (material science), and explain how you would manufacture the part (design/manufacturing).

例如,一道典型的 Eduqas 题目可能描述一个需要轻便而坚固的无人机框架。你需要计算框架上的应力(物理/力学),从性能表格中选择一种材料(材料科学),并说明如何制造该零件(设计/制造)。


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2. Core Mathematics for Engineering | 核心工程数学

Engineering is built on mathematics. You must be comfortable with algebra, trigonometry, unit conversions, and basic statistics. Common calculations include areas, volumes, speeds, and forces. Remember that all equations used should be clearly stated before substituting numbers.

工程学建立在数学之上。你必须熟练掌握代数、三角学、单位换算和基本统计。常见的计算包括面积、体积、速度和受力。请记住,在代入数值之前,应清楚地列出所用公式。

adius r = 10 mm = 1 cm, length = 20 cm. Volume V = π × r² × L = 3.14 × 1² × 20 = 62.8 cm³.

示例:一根圆柱形钢棒的直径为 20 mm,长度为 200 mm。计算其体积(单位 cm³)。首先,半径 r = 10 mm = 1 cm,长度 = 20 cm。体积 V = π × r² × L = 3.14 × 1² × 20 = 62.8 cm³。

Key formulae you should memorise include: area of a circle (A = π × r²), Ohm's law (V = I × R), and pressure (P = F / A).

你应熟记的关键公式包括:圆的面积 (A = π × r²)、欧姆定律 (V = I × R) 以及压强 (P = F / A)。


3. Physics Principles in Engineering | 工程中的物理原理

ndamental laws that govern how structures, machines, and electronic systems behave. Newton' ed to determine forces acting on components. Energy and power calculations are also common in motor and heating scenarios.

物理学提供了支配结构、机器和电子系统行为的基本定律。牛顿第二定律 F = m × a 常用于确定作用在部件上的力。在电机和加热场景中,能量和功率的计算也很常见。

/s²). Work done = m × g × h = 5 × 9.8 × 3 = 147 J. Power = Work / time = 147 / 2 = 73.5 W.

示例:一台电机在 2 秒内将 5 kg 的重物垂直提升 3 米。计算输出功率(设 g = 9.8 m/s²)。做功 = m × g × h = 5 × 9.8 × 3 = 147 J。功率 = 功 / 时间 = 147 / 2 = 73.5 W。

might ask you to design a simple sensor circuit and calculate the required resistor to protect an LED.

在电子学中,欧姆定律 V = I × R 和功率

Published by TutorHao | Year 10 工程 Revision Series | aleveler.com

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