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Year 11 AQA Further Maths: Quick Reference Formula & Theorem Handbook | 公式定理速查手册

2026-07-20 09:42 · 本文部分内容由AI辅助创作

📚 Year 11 AQA Further Maths: Quick Reference Formula & Theorem Handbook | 公式定理速查手册

This quick reference handbook has been carefully compiled to cover the essential formulas, theorems and key results required for the AQA Level 2 Certificate in Further Mathematics. Use it to consolidate your knowledge, check rules during revision and ensure you are fully prepared for both calculator and non-calculator papers.

这份速查手册精心整理了 AQA 进阶数学(二级证书)考试中必备的公式、定理与关键结论。可用于巩固知识、复习核对,确保你在计算器与非计算器考试中都能从容应对。

1. Algebra and Binomial Expansion | 代数与二项式展开

f f(a) = 0. The Remainder Theorem: when f(x) is divided by (x - a), the remainder is f(a).

因式定理:多项式 f(x) 有因式 (x - a) 当且仅当 f(a) = 0。余数定理:f(x) 除以 (x - a) 的余数为 f(a)。

Binomial expansion for positive integer n uses the binomial coefficients ⁿCᵣ, often read from Pascal's triangle. The general term is given by ⁿCᵣ aⁿ⁻ʳ bʳ.

正整数 n 的二项式展开使用二项式系数 ⁿCᵣ,常通过帕斯卡三角形读取。一般项为 ⁿCᵣ aⁿ⁻ʳ bʳ。

(a + b)ⁿ = ⁿC₀ aⁿ + ⁿC₁ aⁿ⁻¹ b + ⁿC₂ aⁿ⁻² b² + ... + ⁿCₙ bⁿ

where ⁿCᵣ = n! / (r! (n - r)!). The coefficient ⁿCᵣ can also be obtained from Pascal's triangle.

其中 ⁿCᵣ = n! / (r! (n - r)!)。系数 ⁿCᵣ 也可从帕斯卡三角形获得。


2. Quadratics and the Discriminant | 二次方程与判别式

c = 0. Its solutions can be found by completing the square or using the quadratic formula:

一般二次方程:ax² + bx + c = 0。可通过配方法或二次公式求解:

x = (-b ± √b² - 4ac) / (2a)

es two distinct real roots, Δ = 0 gives one repeated real root, Δ < 0 gives no real roots.

判别式 Δ = b² - 4ac 决定根的性质:Δ > 0 有两个不等实根,Δ = 0 有一个重根,Δ < 0 无实根。

ompleting the square: x² + bx = (x + b/2)² - (b/2)². For ax² + bx + c, factor out a first.

配方法:x² + bx = (x + b/2)² - (b/2)²。对于 ax² + bx + c,先提取 a。


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3. Inequalities | 不等式

Solving linear inequalities: perform operations as with equations, but reverse the inequality sign when multiplying or dividing by a negative number.

解线性不等式:操作同方程,但乘以或除以负数时需反转不等号方向。

For quadratic inequalities, sketch the graph to identify regions where f(x) > 0 or < 0. Always express final answers using set notation or interval notation as required.

对于二次不等式,画出函数图像以确定 f(x) > 0 或 < 0 的区域。最终答案通常用集合符号或区间表示。

Remember to use open or closed circles on the number line corresponding to strict or inclusive inequalities.

注意在数轴上,严格不等号用空心圆圈,包含等号用实心圆点。


4. Functions and Transformations | 函数与图像变换

Composite function: (f ∘ g)(x) = f(g(x)). The order matters: apply g first, then f.

复合函数:(f ∘ g)(x) = f(g(x))。注意顺序:先作用 g,再作用 f。

nd y in y = f(x) and solve for y. The graph of f⁻¹ is a reflection of f in the line y = x.

反函数 f⁻¹(x):交换 y = f(x) 中的 x 和 y 并解出 y。f⁻¹ 的图像是 f 关于直线 y = x 的反射。

; y = f(ax) is horizontal stretch factor 1/a; y = -f(x) reflects in x-axis; y = f(-x) reflects in y-axis.

y = f(x) 的图像变换:y = f(x) + a 垂直平移 a;y = f(x + a) 水平平移 -a;y = a f(x) 垂直拉伸 a 倍;y = f(ax) 水平拉伸 1/a 倍;y = -f(x) 关于 x 轴反射;y = f(-x) 关于 y 轴反射。


5. Coordinate Geometry: Straight Lines and Circles | 坐标几何:直线与圆

: y = mx + c, where m is gradient, c is y-intercept. Alternative form: y - y₁ = m(x - x₁).

直线方程:y = mx + c,m 为斜率,c 为 y 截距。也可用点斜式:y - y₁ = m(x - x₁)。

f (x₁, y₁) and (x₂, y₂): ((x₁ + x₂)/2, (y₁ + y₂)/2). Distance: √((x₂ - x₁)² + (y₂ - y₁)²).

两点中点:((x₁+x₂)/2, (y₁+y₂)/2)。距离公式:√((x₂ - x₁)² + (y₂ - y₁)²)。

(y - b)² = r². The general form x² + y² + 2gx + 2fy + c = 0 has centre (-g, -f) and radius √g² + f² - c.

圆心 (a, b) 半径 r 的圆方程:(x - a)² + (y - b)² = r²。一般式 x² + y² + 2gx + 2fy + c = 0 的圆心为 (-g, -f),半径为 √g² + f² - c。


6. Trigonometry | 三角学

ues for 0°, 30°, 45°, 60°, 90° must be memorised. For example, sin 30° = 1/2, cos 45° = 1/

Published by TutorHao | Year 11 进阶数学 Revision Series | aleveler.com

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