📚 Interdisciplinary Question Practice for SQA Year 10 Biology | SQA 十年级生物跨学科题型训练
In SQA Year 10 Biology, exam questions often require you to apply knowledge from other subjects, such as mathematics, chemistry and physics. This integrated approach tests your ability to link concepts and solve real-world problems. This article provides practice in tackling interdisciplinary question types commonly found in the SQA specification.
在 SQA 十年级生物中，考试题目常常要求你运用数学、化学和物理等学科的知识。这种综合题型考察你联系概念和解决实际问题的能力。本文将针对 SQA 考纲中常见的跨学科题型进行训练。
1. Unit Conversions and Magnification Calculations | 单位换算与放大倍数计算
ize ÷ Actual size. You must ensure both measurements are in the same unit. Common unit conversions are: 1 cm = 10 mm, 1 mm = 1000 µm, and 1 µ When using the formula, always convert all lengths to the same unit, such as micrometres (µm), before dividing.
许多生物图表和显微镜题目要求你计算放大倍数或实际大小。公式为：放大倍数 = 图像大小 ÷ 实际大小。你必须确保两个测量值使用相同的单位。常见的单位换算有：1 cm = 10 mm，1 mm = 1000 µm，1 µm = 1000 nm。使用公式时，务必先将所有长度转换为相同单位，例如微米 (µm)，然后再进行除法运算。
f a cell measures 50 mm across. The actual cell diameter is 0.05 mm. First convert both to µm: 50 mm = 50000 µm, 0.05 mm = 50 µ ion = 50000 ÷ 50 = ×1000. Alternatively, keep as mm: 50 ÷ 0.05 = ×1000. Always include the '×' sign and no units, as magnification is a ratio.
例如，一个细胞图像直径为 50 mm。细胞实际直径为 0.05 mm。首先将它们转换为 µm：50 mm = 50000 µm，0.05 mm = 50 µm。然后放大倍数 = 50000 ÷ 50 = ×1000。或者保持毫米单位：50 ÷ 0.05 = ×1000。结果要带上 '×' 符号，不加单位，因为放大倍数是一个比值。
Magnification = Image size ÷ Actual size
2. Surface Area to Volume Ratio and Diffusion | 表面积与体积比和扩散
ts volume increases faster than its surface area. For a cube of side length L, surface area is 6L² and volume is L³. The ratio is 6L² ÷ L³ = 6/L. Therefore, a larger organism has a smaller SA:V, which limits diffusion. This is why large organisms need transport systems.
细胞通过扩散进行物质交换，交换效率取决于表面积与体积之比 (SA:V)。随着立方体变大，其体积增长速度快于表面积。对于边长为 L 的立方体，表面积为 6L²，体积为 L³。比值为 6L² ÷ L³ = 6/L。因此，较大的生物体具有较小的 SA:V，从而限制了扩散。这就是为什么大型生物需要运输系统的原因。
When you are given dimensions, calculate SA and V separately and then find the ratio. Express the ratio in its simplest form, e.g. 3:1. An SQA question might ask you to explain why a small organism like a flatworm can rely on diffusion, while a human needs a circulatory system. Use the SA:V concept in your answer.
当给出尺寸时，分别计算表面积和体积，然后求比值。将比值表达为最简形式，例如 3:1。SQA 题目可能会让你解释为什么像涡虫这样的小型生物可以依赖扩散，而人类需要循环系统。在答案中运用 SA:V 概念。
3. pH, Enzymes and Chemical Reactions | pH值、酶与化学反应
Enzymes are proteins that catalyse biochemical reactions. Their activity is affected by pH, as changes in hydrogen ion concentration alter the enzyme's shape. Each enzyme has an optimum pH. For example, pepsin in the stomach works best at pH 2, while trypsin in the small intestine works at pH 8. You may be given data from an experiment measuring reaction rate at different pH values and asked to plot a graph or identify the optimum.
酶是催化生化反应的蛋白质。其活性受 pH 影响，因为氢离子浓度的变化会改变酶的形状。每种酶都有最适 pH。例如，胃中的胃蛋白酶在 pH 2 时活性最佳，小肠中的胰蛋白酶则在 pH 8 时发挥作用。你可能会得到在不同 pH 值下测量反应速率的实验数据，并被要求绘制图表或确定最适 pH。
product produced per unit time. Rate = Quantity of product ÷ Time. Apply this formula when
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