📚 Year 10 AQA Psychology: Mock Unit Test Analysis | AQA 十年级心理学：单元测试模拟卷解析
This walkthrough breaks down a full AQA-style Year 10 psychology mock paper, covering Memory, Perception and Research Methods. Each question is answered with clear explanations, model responses and marking tips, helping you understand exactly what examiners are looking for and how to structure your own answers under timed conditions.
本解析带您逐题拆解一份完整的 AQA 风格的十年级心理学模拟卷，内容涵盖记忆、感知与研究方法。每道题都配有清晰的解释、范例答案和评分点拨，帮助你准确理解考官期望，并学会如何在限时条件下组织答案。
1. Multiple-Choice: Capacity of STM | 选择题：短期记忆的容量
A typical multiple-choice question asks: 'According to the multi-store model, what is the capacity of short-term memory?' The correct answer is 7±2 items. This is based on Miller's (1956) classic research, often called 'Miller's Magic Number'. Distractors such as '5 items' or 'unlimited' may be tempting, but you must recall that capacity is limited and specifically identified as 7±2 chunks of information.
一道典型的选择题是：“根据多存贮模型，短期记忆的容量是多少？”正确答案是 7±2 个项目。这基于米勒（1956）的经典研究，常被称为“米勒的神奇数字”。像“5 个项目”或“无限”这样的干扰项可能很诱人，但必须牢记容量是有限的，并且明确被确定为 7±2 个信息组块。
2. Short Answer: Encoding Differences | 简答题：编码差异
This 2-mark question states: 'Identify one difference between the way information is encoded in short-term memory and long-term memory.' A full-mark answer would be: 'Short-term memory encodes mainly acoustically (by sound), whereas long-term memory encodes mainly semantically (by meaning).' You could also provide an example, such as recalling a phone number by repeating it aloud (acoustic) versus remembering the gist of a story (semantic), but a clear contrast is sufficient for the marks.
这道 2 分题是：“指出信息在短期记忆与长期记忆中编码方式的区别。”满分的回答是：“短期记忆主要进行声学编码（基于声音），而长期记忆主要进行语义编码（基于意义）。”你也可以举例，比如通过反复出声重复号码来回忆（声学）与记住故事的概要（语义），但清晰的对比已经足够拿分。
3. 6-Marker: Describe and Evaluate the Multi-Store Model | 6分题：描述并评价多存贮模型
A 'describe and evaluate' question worth 6 marks expects two description points and two evaluation points, plus a brief conclusion. Description: The multi-store model (Atkinson & Shiffrin, 1968) proposes three separate stores – sensory register, short-term memory and long-term memory. Information flows linearly, first entering the sensory register where it is held briefly; with attention it passes to STM, and through rehearsal it transfers to LTM. Evaluation: A strength is supporting evidence from Peterson & Peterson, who found that STM duration is about 18-30 seconds without rehearsal. A limitation is that the model is oversimplified – it does not account for different types of LTM (e.g. episodic, semantic) and ignores the working memory model's idea of active processing. Therefore, while valid in its basic structure, the multi-store model is incomplete.
一道 6 分的“描述并评价”题要求写出两处描述点和两处评价点，外加简短结论。描述：多存贮模型（Atkinson & Shiffrin, 1968）提出三个独立的存贮库——感觉登记、短期记忆和长期记忆。信息线性流动，先进入感觉登记短暂保存；经注意后进入 STM，再通过复述转入 LTM。评价：一个优点是 Peterson 和 Peterson 的研究支持，他们发现无复述时 STM 时程约为 18-30 秒。一个局限是该模型过于简化——它没有解释 LTM 的不同类型（如情景、语义），也忽视了工作记忆模型中的主动加工观点。因此，虽然基本结构有效，多存贮模型仍不完整。
4. Perception: Linear Perspective as a Monocular Depth Cue | 感知：线条透视作为单眼深度线索
This question asks: 'Explain what is meant by a monocular depth cue, using linear perspective as an example.' A monocular depth cue is a visual signal that can be perceived with one eye and helps us judge distance and depth. Linear perspective occurs when parallel lines appear to converge as they recede into the distance, such as railway tracks meeting at a vanishing point. This cue tells the brain that objects along the converging lines are further away. In your answer, always state that the cue is monocular and connect the example to depth perception.
这道题问：“解释单眼深度线索的含义，并以线条透视为例。”单眼深度线索是能够用一只眼睛感知并帮助我们判断距离和深度的视觉信号。当平行线条向远处延伸时看起来会聚，例如铁轨在消失点交汇，这就是线条透视。该线索告诉大脑，沿汇聚线分布的物体距离更远。作答时，务必指明这是单眼线索，并将例子与深度知觉联系起来。
5. Comparing Gregory's Constructivist Theory and Gibson's Direct Theory | 比较格里高利的建构理论与吉布森的直接理论
You could be asked to outline a key difference between Gregory's and Gibson's theories of perception. Gregory argues that perception is constructivist – we actively interpret sensory data using past experience, expectations and context, which means perception can be influenced by inferences. Gibson, on the other hand, claims perception is direct – the environment provides all necessary information (optic array) and affordances, and no higher cognitive processing is needed. A good contrasting point is that Gregory's theory explains visual illusions because we apply incorrect inferences, whereas Gibson would argue we simply rely on the available depth cues without error under normal conditions.
你可能会被要求概述格里高利与吉布森感知理论的一个主要区别。格里高利主张感知是建构性的——我们通过过去经验、预期和情境主动解释感觉数据，这意味着感知可能受到推理影响。吉布森则声称感知是直接的——环境提供了所有必要信息（光阵列）和可供性，无需高级认知加工。一个很好的对比点是：格里高利的理论解释视觉错觉，因为我们运用了错误的推理；而吉布森会认为在正常条件下，我们仅仅依赖可用的深度线索且不会犯错。
6. Ponzo Illusion: Misapplied Size Constancy | 蓬佐错觉：误用大小恒常性
The Ponzo illusion features two identical horizontal lines drawn across converging vertical lines (like a road disappearing into the distance). The top line appears longer even though they are the same length. According to Gregory's misapplied size constancy explanation, our perceptual system automatically assumes the top line is farther away because of the depth cues created by the converging lines. To maintain size constancy, the brain scales up the perceived size of the object seen as more distant, making the top line look larger. Always make sure to highlight that the retinal image of both lines is identical, so the illusion is created by top-down processing.
蓬佐错觉呈现两条等长的水平线横跨在汇聚的垂直线条上（如同向远方延伸的道路）。尽管两条线长度相同，上方线条看起来更长。根据格里高利的误用大小恒常性解释，我们的知觉系统因汇聚线产生的深度线索，自动假定上方线条更远。为了保持大小恒常，大脑会放大较远物体的知觉尺寸，从而使上方线条看起来更大。务必强调两条线的视网膜像相同，因此错觉是由自上而下的加工所导致的。
7. Research Methods: Identifying Independent and Dependent Variables | 研究方法：识别自变量与因变量
A scenario-based question may describe an experiment where participants learn a word list either in silence or while listening to music, and the number of words recalled is measured. The independent variable (IV) is the variable manipulated by the researcher – here it is the presence or absence of music (or the two learning conditions). The dependent variable (DV) is what is measured – the number of words recalled correctly. When answering, you must operationalise the variables clearly: 'The IV is whether participants studied in silence or with music; the DV is the score on a recall test out of 20 words.' This precision scores the marks.
情景题可能描述一个实验：参与者在安静或听音乐条件下学习词表，然后测量回忆的词数。自变量（IV）是研究者操纵的变量——这里是是否有音乐（或两种学习条件）。因变量（DV）是测量的东西——正确回忆的词数。回答时，必须清晰地将变量操作化：“IV 是参与者在安静还是音乐条件下学习；DV 是在 20 个词的回忆测试中的得分。”这种精确性能拿到分数。
8. Experimental Design: Evaluating Repeated Measures | 实验设计：评价重复测量设计
When a question asks about strengths and weaknesses of the repeated measures design, address both. In this design, the same participants take part in all conditions of the experiment. A major strength is that participant variables (e.g. memory ability) are controlled because each person acts as their own control, which increases internal validity. A limitation is order effects – performance in the second condition may improve due to practice or decline due to fatigue, potentially confounding the results. Counterbalancing can control for order effects, but it is not always fully effective. Remember to link the evaluation directly to the design.
如果题目要求说明重复测量设计的优缺点，需要两方面都谈。在这种设计中，同一批参与者接受实验的所有条件。一个主要优点是参与者变量（如记忆力差异）得到控制，因为每人作为自身的对照，这提高了内部效度。一个局限是顺序效应——由于练习或疲劳，第二个条件中的表现可能更好或更差，这可能混淆实验结果。平衡法可以控制顺序效应，但并非总是完全有效。记得将评价直接与设计联系起来。
9. Extended Writing: Discuss the Reliability of Eyewitness Testimony | 扩展写作：讨论目击证词的可靠性
This 9-mark question requires a balanced discussion. Start by outlining factors that reduce reliability: leading questions (Loftus & Palmer, 1974) can alter memory – participants who heard 'smashed' estimated higher speeds than those who heard 'hit'. Post-event discussion (Gabbert et al., 2003) can lead to memory conformity, where witnesses' accounts merge. However, you must also discuss evidence suggesting EWT can be reliable under the right conditions – for example, the cognitive interview has been shown to enhance recall of correct details. Evaluate by mentioning that much of the research lacks ecological validity due to artificial lab settings, and individual differences (e.g. age, anxiety) affect accuracy. Conclude that EWT can be fragile and malleable, but specific techniques can improve its reliability.
这道 9 分题需要均衡的讨论。开头概述降低可靠性的因素：引导性问题（Loftus & Palmer, 1974）可改变记忆——听到“ smashed ”的参与者比听到“ hit ”的估计出更高的速度。事后讨论（Gabbert et al., 2003）会导致记忆从众，使证人的叙述混合。然而，你也必须讨论表明 EWT 在合适条件下可以可靠的证据——例如，认知访谈已被证明能提高正确细节的回忆。评价时可提到，许多研究因实验室的人为设置而缺乏生态效度，且个体差异（如年龄、焦虑）影响准确性。结论是 EWT 可能脆弱且可塑，但特定技术能改善其可靠性。
10. Data Analysis: Calculating Mean and Range | 数据分析：计算平均值与极差
divide by the number of scores (5), giving a mean of 16. The range is the difference between the highest and lowest scores: 18 – on mistake is to give the highest and lowest numbers rather than the difference, so always subtract.
给出了一个小数据集：条件 A 的回忆得分为 14、17、15、16、18。计算平均值时，将所有分数相加（14+17+15+16+18 = 80）除以分数个数（5），得到平均值为 16。极差是最高分与最低分的差值：18 – 14 = 4。作答时要清晰展示计算过程，并记住极差是分散度的简单度量，只考虑了极端值。常见的错误是写出最高和最低数值而非差值，所以一定要做减法。
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