Year 10 Eduqas Science: Unit Test Mock Paper Analysis | 10年级Eduqas科学单元测试模拟卷解析

📚 Year 10 Eduqas Science: Unit Test Mock Paper Analysis | 10年级Eduqas科学单元测试模拟卷解析

This mock paper analysis covers key topics from Year 10 Eduqas GCSE Science, including biology, chemistry, and physics. Each question is broken down step by step to help you understand common mistakes and master exam technique.

这份模拟卷解析涵盖了10年级Eduqas GCSE科学的关键主题，包括生物、化学和物理。每道题目都逐步分解，帮助你理解常见错误并掌握考试技巧。

1. Density Calculation | 密度计算

A student finds the mass of a metal cube to be 96 g and its volume 12 cm³. Calculate the density of the metal. Include the correct unit.

一名学生测得一个金属立方体的质量为96克，体积为12立方厘米。计算该金属的密度，并写出正确的单位。

ituting the given values: 96 g ÷ 12 cm³ = 8 g/cm³. The unit is grams per cubic centimetre.

要计算密度，使用公式 密度 = 质量 / 体积。代入数值：96 g ÷ 12 cm³ = 8 g/cm³。单位是克每立方厘米。

Be careful: Eduqas sometimes provides mass in kilograms and volume in m³, expecting an answer in kg/m³. Always check the units before calculating.

注意：Eduqas 有时会给出以千克为单位的质量和以立方米为单位的体积，期望答案以 kg/m³ 表示。计算前务必检查单位。

A common mistake is forgetting to write the unit. Even if the numerical answer is correct, marks are lost without the appropriate unit such as g/cm³ or kg/m³.

一个常见错误是忘记写单位。即使数字答案正确，如果没有合适的单位（如 g/cm³ 或 kg/m³）也会失分。

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2. Heart Structure | 心脏结构

Label the diagram showing the right atrium, left ventricle, and aorta. Explain why the left ventricle has a thicker muscle wall than the right ventricle.

标注示意图中的右心房、左心室和主动脉。解释为什么左心室的肌壁比右心室的更厚。

The left ventricle pumps oxygenated blood to the whole body, facing high resistance in the systemic circulation. The right ventricle only pumps deoxygenated blood to the nearby lungs, which is a shorter circuit with lower resistance.

左心室将含氧血泵送至全身，面对体循环中的高阻力。右心室仅将缺氧血泵送至邻近的肺部，这是一个较短且阻力较低的循环回路。

Because the left ventricle must generate a much higher pressure to push blood through the aorta and around the entire body, its muscular wall is thicker. This extra muscle provides the force needed for systemic circulation.

由于左心室必须产生更高的压力，才能将血液推动通过主动脉并输往全身，因此其肌壁更厚。这额外的肌肉提供了体循环所需的力量。

When labelling the heart, remember that diagrams are usually drawn as if you are facing the person. So the left ventricle appears on the right side of the page. Confusing left and right is a very frequent error.

标注心脏时，请记住示意图通常是面对人体所绘。因此左心室出现在页面的右侧。混淆左右是一个非常常见的错误。

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3. Balancing Equations | 配平方程式

ation: __ Na + __ Cl₂ → __ NaCl. Then state the total number of atoms on the product side.

配平下列方程式：__ Na + __ Cl₂ → __ NaCl。然后写出生成物一侧的总原子数。

Start by counting atoms: on the left, there is one Na and two Cl (as Cl₂ is diatomic). To balance chlorine, place a coefficient 2 in front of NaCl, giving two Cl atoms on the right. Then balance sodium by placing a 2 in front of Na. The balanced equation is:

首先计算原子数：左边有一个 Na 和两个 Cl（因为 Cl₂ 是双原子分子）。为配平氯，在 NaCl 前添加系数 2，使右边有两个 Cl 原子。然后配平钠，在 Na 前添加 2。配平后的方程式为：

2Na + Cl₂ → 2NaCl

On the product side there are 2 Na atoms and 2 Cl atoms, giving a total of 4 atoms.

生成物一侧有 2 个 Na 原子和 2 个 Cl 原子，总共 4 个原子。

Never change the small subscript numbers inside a formula. Only put large numbers (coefficients) in front of substances. Changing subscripts alters the chemical identity.

切勿改变化学式中的小下标数字。只能在物质前面放置大的系数。改变下标会改变化学物质的特性。

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4. Energy Efficiency | 能量效率

An electric motor lifts a weight, using 200 J of electrical energy. It does 150 J of useful work. Calculate the efficiency as a percentage, and describe where the remaining energy is transferred.

一台电动机提升重物，使用了200焦耳的电能，做了150焦耳的有用功。计算效率（百分比），并描述剩余能量转移到了哪里。

Efficiency = (useful output energy / total input energy) × 100% = (150 J / 200 J) × 100% = 75%.

效率 = (有用输出能量 / 总输入能量) × 100% = (150 J / 200 J) × 100% = 75%。

The remaining 50 J is not destroyed; it is dissipated as thermal energy, heating the motor and the surroundings due to friction and electrical resistance. This energy is transferred to the thermal energy store of the environment.

剩余的50焦耳并没有被消灭；它因摩擦和电阻以热的形式耗散，加热了电动机和周围环境。这部分

Published by TutorHao | Year 10 Science Revision Series | aleveler.com

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