📚 GCSE Chemistry Unit Test: Atomic Structure and Bonding | GCSE 化学单元测试：原子结构与化学键
This GCSE Chemistry unit test paper focuses on atomic structure, the periodic table, and chemical bonding. Each question is followed by a detailed answer and explanation to help you master the core concepts. Use this as a self-assessment or revision tool to build your confidence for the exam. Work through every question, check your answers, and learn from any mistakes.
本 GCSE 化学单元测试卷涵盖原子结构、周期表及化学键知识。每道题均附有详细答案与解析，助你掌握核心概念。可将此作为自我测评或复习工具，提升考试信心。请逐题练习，核对答案，从错误中学习。
1. Subatomic Particles | 亚原子粒子
Question: Which subatomic particle has a relative mass of approximately 1/1840 and a charge of –1?
A. Proton
B. Neutron
C. Electron
D. Nucleus
题目：哪种亚原子粒子的相对质量约为 1/1840，电荷为 –1？
A. 质子
B. 中子
C. 电子
D. 原子核
C. Electron. Electrons are tiny particles with a mass about 1/1840 of a proton or neutron. They carry a single negative charge (–1), while protons are positively charged (+1) and neutrons have no charge. The relative masses of protons and neutrons are both 1.
C. 电子。电子的质量极小，约为质子的 1/1840。电子带一个负电荷 (–1)；质子带正电荷 (+1)，中子不带电。质子与中子的相对质量均为 1。
2. Electron Configuration | 电子排布
Question: An atom of fluorine has atomic number 9. What is its electron configuration?
A. 2,8
B. 2,7
C. 2,8,1
D. 2,6
题目：氟原子的原子序数为 9。其电子排布是？
A. 2,8
B. 2,7
C. 2,8,1
D. 2,6
B. 2,7. Fluorine has 9 electrons. The first shell can hold a maximum of 2 electrons, leaving 7 electrons for the second shell. This gives the configuration 2,7. Fluorine is in Group 7 of the periodic table because it has 7 electrons in its outer shell.
B. 2,7。氟原子有 9 个电子。第一电子层最多容纳 2 个电子，剩余的 7 个电子进入第二层，因此排布为 2,7。氟位于周期表第 7 族，因其最外层电子数为 7。
3. Isotopes | 同位素
Question: Which statement about isotopes is correct?
A. They have the same number of neutrons.
B. They have the same number of protons but different numbers of neutrons.
C. They have the same mass number.
D. They have different chemical properties.
题目：下列关于同位素的说法哪项正确？
A. 它们的中子数相同。
B. 它们质子数相同，但中子数不同。
C. 它们的质量数相同。
D. 它们的化学性质不同。
B. Isotopes are atoms of the same element with the same number of protons but different numbers of neutrons. Therefore, they have different mass numbers but identical chemical properties because chemical behaviour is determined by the electron arrangement, which is unchanged.
B。同位素是同一元素中质子数相同、中子数不同的原子。因此它们的质量数不同，但化学性质完全相同，因为化学性质由电子排布决定，质子数不变则电子数不变。
4. Periodic Table Groups | 周期表族
Question: Chlorine is a halogen. To which group of the periodic table does chlorine belong?
A. Group 1
B. Group 2
C. Group 7
D. Group 0
题目：氯是一种卤素。氯在周期表中属于哪一族？
A. 第 1 族
B. 第 2 族
C. 第 7 族
D. 第 0 族
C. Group 7. Chlorine has 7 electrons in its outer shell, so it is placed in Group 7. The halogens all have 7 outer electrons and readily gain one electron to form –1 ions. They are non-metals with similar properties, such as high electronegativity.
C. 第 7 族。氯原子最外层有 7 个电子，因此位于第 7 族。卤素最外层均有 7 个电子，易获得一个电子形成 –1 离子。它们是非金属，性质相似，例如电负性高。
5. Ionic Bonding | 离子键
Question: Describe what happens to the electrons when a sodium atom reacts with a chlorine atom to form sodium chloride.
题目：钠原子与氯原子反应生成氯化钠时，电子发生了什么变化？
The sodium atom loses one electron from its outer shell to achieve a stable electron arrangement, forming a positively charged Na⁺ ion. The chlorine atom gains that electron, filling its outer shell and forming a negatively charged Cl⁻ ion. These oppositely charged ions are held together by strong electrostatic forces of attraction, which is the ionic bond.
钠原子失去最外层的一个电子，达到稳定电子排布，形成带正电荷的 Na⁺ 离子。氯原子获得该电子，填满最外层，形成带负电荷的 Cl⁻ 离子。带相反电荷的离子通过强大的静电吸引力结合在一起，即为离子键。
6. Covalent Bonding | 共价键
Question: How many covalent bonds are there in a molecule of water (H₂O), and what does each bond represent?
题目：水分子 (H₂O) 中有多少个共价键？每个键代表什么？
There are two covalent bonds in a water molecule. Each bond is a shared pair of electrons between an oxygen atom and a hydrogen atom. The oxygen shares one electron with each hydrogen, and each hydrogen shares its only electron with the oxygen, giving all atoms a filled outer shell.
水分子中有两个共价键。每个共价键是氧原子与氢原子之间的一对共用电子。氧与每个氢各共享一个电子，每个氢也把唯一的电子与氧共享，使所有原子都达到满外层结构。
7. Giant Covalent Structures | 巨型共价结构
Question: Explain why diamond has a very high melting point.
题目：解释为什么金刚石具有极高的熔点。
Diamond has a giant covalent structure. Every carbon atom is covalently bonded to four other carbon atoms in a tetrahedral arrangement. These strong covalent bonds extend throughout the entire structure. A huge amount of thermal energy is required to break these bonds, so diamond has a very high melting point (about 3550°C).
金刚石具有巨型共价结构。每个碳原子以共价键与另外四个碳原子键合，形成四面体排列。强烈的共价键贯穿整个结构。破坏这些键需要极大的热能，因此金刚石熔点极高（约 3550°C）。
8. Metallic Bonding | 金属键
Question: Describe the bonding in a piece of pure copper and explain why copper can conduct electricity.
题目：描述纯铜中的键合方式，并解释铜为什么能导电。
Metallic bonding consists of a regular lattice of positive metal ions surrounded by a 'sea' of delocalised electrons. In copper, Cu²⁺ ions are held together by electrostatic attraction to these free electrons. Copper conducts electricity because the delocalised electrons are free to move throughout the structure carrying charge when a voltage is applied.
金属键由规则排列的正金属离子和弥漫其间的“自由电子海”组成。在铜中，Cu²⁺ 离子通过静电吸引力与自由电子结合。铜能导电是因为离域的电子可在整个结构中自由移动，当施加电压时便携带电荷流动。
9. Formula Mass Calculation | 相对式量计算
Question: a : Calculate the relative formula mass (Mᵣ) of calcium carbonate, CaCO₃. (Relative atomic masses: Ca = 40, C = 12, O = 16)
题目：计算碳酸钙 (CaCO₃) 的相对式量 (Mᵣ)。（相对原子质量：Ca = 40，C = 12，O = 16）
+ 12 + (3 × 16) = 40 + 12 + 48 = 100. There are no units because it is a relative measure.
100。CaCO₃ 的 Mᵣ = Ar(Ca) + Ar(C) + 3 × Ar(O) = 40 + 12 + (3 × 16) = 40 + 12 + 48 = 100。相对量没有单位。
10. Balancing Chemical Equations | 化学方程式配平
Question: Balance the following equation: __ Fe + __ Cl₂ → __ FeCl₃
题目：配平下列方程式：__ Fe + __ Cl₂ → __ FeCl₃
2 Fe + 3 Cl₂ → 2 FeCl₃
Start by balancing the iron atoms: FeCl₃ has one Fe, Fe is already one. But chlorine: FeCl₃ has 3 Cl atoms, while Cl₂ has 2. To balance, we need a total of 6 Cl on each side, so put 2 FeCl₃ (giving 6 Cl) and 3 Cl₂ (also 6 Cl). Then adjust Fe to 2. Coefficients are 2, 3, 2.
2 Fe + 3 Cl₂ → 2 FeCl₃
先配平铁原子：FeCl₃ 有 1 个 Fe，Fe 也是 1。但氯原子：FeCl₃ 有 3 个 Cl，Cl₂ 有 2 个。为使两边 Cl 数为 6，在 FeCl₃ 前写 2（共 6 个 Cl），在 Cl₂ 前写 3（也是 6 个 Cl），最后调平铁为 2。配平系数为 2, 3, 2。
Published by TutorHao | Chemistry Revision Series | alevel
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