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Acids and Bases: Key Concepts | 酸与碱:考点精讲

2026-07-12 17:58 · 本文部分内容由AI辅助创作

📚 Acids and Bases: Key Concepts | 酸与碱:考点精讲

Understanding acids and bases is fundamental to IB and Edexcel chemistry. This article covers the key definitions, theories, and calculations required for exam success, from Arrhenius to Brønsted-Lowry, pH and pOH, strong and weak acids, and buffer solutions.

理解酸与碱是IB和Edexcel化学的基础。本文涵盖了考试成功所需的关键定义、理论和计算,从阿伦尼乌斯到布朗斯特-劳里理论、pH和pOH、强酸和弱酸,以及缓冲溶液。

1. Arrhenius Theory | 阿伦尼乌斯理论

For example, HCl dissociates as HCl → H⁺ + Cl⁻, and NaOH dissociates as NaOH → Na⁺ + OH⁻.

阿伦尼乌斯定义指出,酸是在水中解离产生氢离子(H⁺)的物质,而碱则解离产生氢氧根离子(OH⁻)。例如,HCl解离为HCl → H⁺ + Cl⁻,NaOH解离为NaOH → Na⁺ + OH⁻。

This theory is limited because it only applies to aqueous solutions and cannot explain the basicity of substances like ammonia (NH₃) that do not contain OH⁻.

该理论的局限性在于它仅适用于水溶液,并且无法解释不含OH⁻的物质(例如氨NH₃)的碱性。


2. Brønsted-Lowry Theory | 布朗斯特-劳里理论

The Brønsted-Lowry theory defines an acid as a proton (H⁺) donor and a base as a proton acceptor. This broader definition includes substances like ammonia: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, where NH₃ accepts a proton from water.

布朗斯特-劳里理论将酸定义为质子(H⁺)供体,将碱定义为质子受体。这一定义更广泛,包含氨等物质:NH₃ + H₂O ⇌ NH₄⁺ + OH⁻,其中NH₃从水中接受一个质子。

Conjugate acid-base pairs are formed when an acid donates a proton, leaving its conjugate base, and a base accepts a proton, forming its conjugate acid. For the reaction HA + B ⇌ A⁻ + BH⁺, HA and A⁻ are a conjugate pair, while B and BH⁺ are another.

共轭酸碱对是指酸提供质子后形成其共轭碱,碱接受质子后形成其共轭酸。对于反应HA + B ⇌ A⁻ + BH⁺,HA和A⁻是共轭对,而B和BH⁺是另一对。


3. Lewis Theory | 路易斯理论

路易斯理论进一步扩展了定义:酸是电子对受体,碱是电子对供体。这解释了不涉及质子的反应,例如BF₃ + NH₃ → F₃B-NH₃,其中BF₃接受来自NH₃的电子对。

This theory is particularly useful in organic and coordination chemistry, but for most acid-base problems in IB and Edexcel, the Brønsted-Lowry theory is sufficient.

该理论在有机和配位化学中特别有用,但对于IB和Edexcel中的大多数酸碱问题,布朗斯特-劳里理论已足够。


4. Strong and Weak Acids and Bases | 强酸与弱酸、强碱与弱碱

H⁺ + Cl⁻. Weak acids, like CH₃COOH, partially dissociate, establishing an equilibrium: CH₃COOH ⇌ H⁺ + CH₃COO⁻.

强酸在水中完全解离,例如HCl、H₂SO₄(第一步解离)和HNO₃。其解离基本上是单向的:HCl → H⁺ + Cl⁻。弱酸,如CH₃COOH,部分解离,建立平衡:CH₃COOH ⇌ H⁺ + CH₃COO⁻。

Similarly, strong bases like NaOH and KOH fully dissociate to give OH⁻, while weak bases like NH₃ only partially react with water to produce OH⁻.

类似地,强碱如NaOH和KOH完全解离产生OH⁻,而弱碱如NH₃仅部分与水反应生成OH⁻。


5. pH and pOH Calculations | pH与pOH计算

pH + pOH = 14. For a strong monoprotic acid of concentration c, [H⁺] = c, so pH = -log₁₀c.

pH定义为pH = -log₁₀[H⁺],pOH = -log₁₀[OH⁻]。在25°C的水中,pH + pOH = 14。对于浓度为c的强一元酸,[H⁺] = c,因此pH = -log₁₀c。

A⁻] / [HA]. For a weak acid of initial concentration c and very small dissociation, [H⁺] ≈ √Kₐc. Then pH = -log₁₀[H⁺].

对于弱酸,使用酸解离常数Kₐ:Kₐ = [H⁺][A⁻] / [HA]。对于初始浓度为c且解离度很小的弱酸,[H⁺] ≈ √Kₐc。然后pH = -log₁₀[H⁺]。


6. The Ionic Product of Water, Kₑ | 水的离子积 Kₑ

Water undergoes autoionization: 2H₂O ⇌ This value changes with temperature; at higher temperatures Kₑ increases, making neutral pH different from 7.

水发生自耦解离:2H₂O ⇌ H₃O⁺ + OH⁻。平衡常数Kₑ = [H⁺][OH⁻] = 1.0 × 10⁻¹⁴(25°C)。该值随温度变化;较高温度下Kₑ增大,使得中性pH不等于7。

This concept is essential when calculating the pH of very dilute solutions or strong bases, where the contribution of H⁺ from water cannot be ignored.

这一概念在计算极稀溶液或强碱的pH时至关重要,此时不能忽略来自水的H⁺贡献。


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7. Acid-Base Titrations and pH Curves | 酸碱滴定与pH曲线

Titration curves plot pH against the volume of titrant added. For a strong acid-strong base titration, the equivalence point is at pH 7. For a weak acid-strong base titration, the equivalence point is above pH 7 due to the formation of the conjugate base.

滴定曲线描绘了pH随滴定剂加入体积的变化。强酸-强碱滴定的等当点在pH 7。弱酸-强碱滴定的等当点高于7,由于生成了共轭碱。

The buffer region occurs where the pH changes slowly, typically around the half-equivalence point for weak acid or weak base titrations. Indicators with appropriate pKₐ values are chosen so their colour change coincides with the steep part of the curve.

缓冲区域出现在pH变化缓慢的地方,通常在弱酸或弱碱滴定的半等当点附近。选择具有适当pKₐ值的指示剂,使其颜色变化与曲线的陡峭部分重合。


8. Buffer Solutions | 缓冲溶液

A buffer solution resists changes in pH upon addition of small amounts of acid or base. It consists of a weak acid and its conjugate base (e.g., CH₃COOH/CH₃COO⁻) or a weak base and its conjugate acid (e.g., NH₃/NH₄⁺).

缓冲溶液能抵抗因少量酸或碱加入而引起的pH变化。它由弱酸及其共轭碱(例如CH₃COOH/CH₃COO⁻)或弱碱及其共轭酸(例如NH₃/NH₄⁺)组成。

[A⁻] is the concentration of conjugate base and [HA] is the concentration of the weak acid.

亨德森-哈塞尔巴尔赫方程用于计算缓冲液的pH:pH = pKₐ + log₁₀([A⁻]/[HA]),其中[A⁻]是共轭碱浓度,[HA]是弱酸浓度。

Buffers are crucial in biological systems, such as maintaining blood pH around 7.4 using the carbonic acid/bicarbonate system.

缓冲液在生物系统中至关重要,例如利用碳酸/碳酸氢盐系统维持血液pH约7.4。


9. Acid Deposition and Environmental Context | 酸沉降与环境背景

Acid deposition, including acid rain, is caused by SO₂ and NOₓ emissions reacting with water in the atmosphere to form H₂SO₄ and HNO₃. This links to acid-base chemistry through the formation of acidic solutions and their impact on ecosystems.

酸沉降,包括酸雨,是由SO₂和NOₓ排放与大气中的水反应生成H₂SO₄和HNO₃引起的。这通过酸性溶液的形成及其对生态系统的影响与酸碱化学联系起来。

O₂ + O₂ + 2H₂O → 2H₂SO₄, or the neutralization of acidified lakes using limestone (CaCO₃).

考试可能涉及相关方程式:例如,2SO₂ + O₂ + 2H₂O → 2H₂SO₄,或使用石灰石(CaCO₃)中和酸化湖泊。


10. Common Exam Pitfalls and Tips | 常见考试陷阱与提示

Students often confuse strength and concentration; a strong acid is fully dissociated regardless of its concentration, while a weak acid is only partially dissociated even at high concentration. Be careful when calculating pH for diprotic acids like H₂SO₄, as the second dissociation may be partial.

学生常混淆强度与浓度;强酸无论浓度如何都完全解离,而弱酸即使高浓度也仅部分解离。计算二元酸如H₂SO₄的pH时要小心,因为第二步解离可能不完全。

C. In buffer calculations, ensure you use equilibrium concentrations, not initial amounts.

使用Kₑ = 1.0 × 10⁻¹⁴时务必核对温度,记住pH + pOH = 14仅在25°C成立。在缓冲计算中,确保使用平衡浓度而非初始量。

should be within ±1 of the equivalence point pH, and the colour change should be distinct.

指示剂选择方面,指示剂的pKₐ应在等当点pH的±1范围内,且颜色变化应明显。


Published by TutorHao | IB Edexcel Chemistry Revision Series | aleveler.com

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