📚 Year 10 AQA Physics: Summer Bridging and Transition Course | Year 10 AQA 物理：暑期预习与衔接课程
This bridging course is designed to help you transition smoothly into Year 10 AQA Physics. It reviews the essential concepts from Year 9 and introduces the core topics you will encounter, building a solid foundation of scientific knowledge and mathematical skills. Each section explains key ideas in both English and Chinese, so you can strengthen your understanding and exam readiness over the summer.
本衔接课程旨在帮助你顺利过渡到 Year 10 AQA 物理课程。它回顾九年级所学的重要概念，并介绍你将接触的核心主题，为科学知识和数学技能打下坚实基础。每个部分均用英文和中文解释关键概念，让你在暑期巩固理解，为考试做好准备。
The course follows the AQA GCSE Physics specification structure: energy, electricity, particle model, atomic structure, forces, waves and magnetism. You do not need to master everything before September. The aim is to recognise the vocabulary, be confident with the equations, and arrive in class already familiar with the ideas your teacher will develop.
本课程依照 AQA GCSE 物理考纲结构编排：能量、电学、粒子模型、原子结构、力、波与磁。你无需在九月前掌握全部内容。目标只是熟悉术语、熟练运用公式，并在课堂上面对老师将要展开的知识点时已经不再陌生。
1. How to Use This Summer Bridging Course | 如何使用本暑期衔接课程
Work through one section per study session. Read the English paragraph first, then read the Chinese paragraph to check that you have understood the meaning. Do not simply memorise the Chinese translation - use it as a mirror for the English scientific language you will meet in the exam.
每次学习完成一个小节。先读英文段落，再读中文段落，检查自己是否真正理解含义。不要把中文当作背诵对象，而应把它当作一面镜子，映照你将在考试中遇到的英文学术语言。
Every section ends with practice suggestions or a worked example. You should keep a single exercise book for the whole summer, with a clear heading for each section, all working shown, and units written on every answer.
每个小节末尾都配有练习建议或例题解析。整个暑假请使用同一本练习本，每小节标明标题，写出完整过程，并且每一个答案都写单位。
You will need the following equipment:
你需要准备以下工具：
- A scientific calculator (the Casio FX-83GT or FX-85GT is ideal) | 科学计算器（Casio FX-83GT 或 FX-85GT 最为理想）
- A 30 cm ruler and a pencil for graphs | 30 厘米直尺与画图用铅笔
- Squared paper for distance-time and velocity-time graphs | 方格纸，用于位移-时间图与速度-时间图
- The AQA Physics equation sheet, printed and kept at the front of your book | 打印好的 AQA 物理公式表，夹在练习本首页
2. Energy Stores and Systems | 能量储存与系统
Energy is stored in different ways: kinetic, gravitational potential, elastic potential, thermal, chemical, nuclear, magnetic and electrostatic. You should be able to name each store and give a real example of an object that has energy in that store.
能量以不同形式储存：动能、重力势能、弹性势能、热能、化学能、核能、磁能和静电。你应能说出每一种储存形式，并举出一个真实物体储存该能量的例子。
A system is an object or group of objects, and we study how energy is transferred between them. When you define a system, you decide which objects are inside it and which are outside. Everything outside the system is called the surroundings.
系统是一个或一组物体，我们研究能量如何在它们之间传递。定义系统时，你要决定哪些物体在系统内部、哪些在外部。系统之外的一切称为环境。
Energy is transferred between stores through four pathways. These pathways are not stores themselves; they are the processes by which energy moves.
能量通过四条途径在储存之间传递。这些途径本身不是储存形式，而是能量移动的过程。
- Mechanically - by a force doing work, such as pushing a box | 机械做功——例如推箱子时力做功
- Electrically - by a current doing work, such as in a heater | 电做功——例如电流通过加热器做功
- By heating - from a hotter object to a colder one | 通过加热——从较热物体传向较冷物体
- By radiation - by waves, such as light or sound | 通过辐射——以波的形式，如光或声
A common exam mistake is to write "energy is lost". Energy is never lost; it is transferred to a store you have not identified, usually the thermal store of the surroundings.
考试中常见的错误是写"能量消失了"。能量从不消失，它只是转移到了你没有识别的储存中，通常是环境的热能。
3. Conservation of Energy and Dissipation | 能量守恒与耗散
The principle of conservation of energy states that energy can never be created or destroyed; it can only be transferred usefully, stored or dissipated (often as thermal energy). This is one of the most powerful ideas in physics because it allows you to calculate answers without knowing the details of every force involved.
能量守恒定律指出能量不能被创造或消灭；它只能被有效转移、储存或耗散（通常以热能形式耗散）。这是物理学中最有力的思想之一，因为它让你无需了解每一个力的细节也能完成计算。
A closed system is one in which no energy can enter or leave. In a closed system, the total energy in all the stores remains constant. A pendulum swinging in a vacuum is the classic example: the gravitational potential store and the kinetic store swap energy back and forth with no overall change.
封闭系统是指能量不能进出系统。在封闭系统中，所有储存中的总能量保持不变。真空中的单摆是经典例子：重力势能储存与动能储存来回转换，总量不变。
Dissipation means energy spreading out into the surroundings, usually into the thermal store, so that it becomes harder to use. Friction between moving surfaces, air resistance on a falling object and electrical resistance in wires all cause dissipation.
耗散指能量扩散到环境中，通常进入热能储存，使其变得更难利用。运动表面之间的摩擦、下落物体受到的空气阻力、导线中的电阻都会造成耗散。
Because energy is always dissipated, no machine is 100 per cent efficient. A falling ball bounces to a lower height each time; a mobile phone becomes warm while charging. Both observations are direct evidence of dissipation.
由于能量总会耗散，没有机器能达到 100% 的效率。下落的球每次弹起高度都会降低；手机充电时会发热。这两种现象都是耗散的直接证据。
Engineers reduce unwanted transfers by lubricating moving parts, insulating hot pipes, using streamlined shapes on vehicles and using low-resistance wires. In the exam you may be asked to suggest one such method and explain why it works.
工程师通过给运动部件加润滑油、给热管加保温层、让车辆外形流线化、使用低电阻导线来减少不必要的能量传递。考试中可能要求你提出一种方法并解释其原理。
4. Kinetic Energy and Gravitational Potential Energy | 动能与重力势能
Moving objects possess kinetic energy (Ek ms and v is the speed in metres per second. Because the speed is squared, doubling the speed multiplies the kinetic energy by four.
运动物体具有动能（Ek = ½ m v²），其中 m 是质量，单位为千克，v 是速率，单位为米每秒。由于速率是平方项，速率加倍会使动能变为原来的四倍。
Ek = ½ m v²
ts mass, the gravitational field strength g (≈ 9.8 N/kg on Earth) and the change in height ∆h, as ∆Ep = m g ∆h.
物体获得的重力势能取决于其质量、引力场强度 g（地球约为 9.8 N/kg）以及高度变化 ∆h，公式为 ∆Ep = m g ∆h。
∆Ep = m g ∆h
Note carefully that g is measured in newtons per kilogram (N/kg), which is numerically the same as metres per second squared (m/s²). AQA accepts either unit, but you must be consistent within a calculation.
请注意，g 的单位是牛顿每千克（N/kg），其数值与米每二次方秒（m/s²）相同。AQA 接受两种单位，但在同一次计算中必须保持一致。
Here is a worked example. A 0.5 kg ball is thrown upwards at 8 m/s. Its kinetic energy is Ek × 8² = 16 J. If all of this becomes gravitational potential energy, then 16 = 0.5 × 9.8 × ∆h, so ∆h ≈ 3.3 m.
例题：一个 0.5 kg 的球以 8 m/s 向上抛出。其动能为 Ek = ½ × 0.5 × 8² = 16 J。若这些能量全部转化为重力势能，则 16 = 0.5 × 9.8 × ∆h，解得 ∆h ≈ 3.3 m。
In reality the ball rises slightly less than this because some energy is dissipated by air resistance. Exam questions often ask you to explain that discrepancy in terms of the thermal store of the surroundings.
实际上球上升的高度会略低于该值，因为部分能量被空气阻力耗散。考试题经常要求你从环境热能储存的角度解释这一差异。
5. Elastic Potential, Thermal, Chemical and Other Stores | 弹性势能、热能、化学能及其他储存
An object that is stretched or compressed stores elastic potential energy. For a spring that obeys Hooke's law, Ee in N/m and e is the extension in metres. This equation only applies up to the limit of proportionality.
被拉伸或压缩的物体会储存弹性势能。对于遵守胡克定律的弹簧，Ee = ½ k e²，其中 k 为劲度系数，单位为 N/m，e 为伸长量，单位为米。该公式只在不超过比例极限时成立。
Ee = ½ k e²
A thermal store is really the total kinetic energy and potential energy of the particles inside an object. Heating a substance increases the average kinetic energy of its particles; this is what we measure as a rise in temperature.
热能储存实际上是物体内部所有粒子的动能与势能之和。加热物质会提高粒子的平均动能，这正是我们测量到的温度升高。
Chemical stores include food, fuel, batteries and the molecules in your muscles. Nuclear stores include the energy released in fission and fusion. Magnetic and electrostatic stores are smaller but appear in questions about magnets, charged rods and capacitors.
化学能储存包括食物、燃料、电池以及肌肉中的分子。核能储存包括裂变与聚变释放的能量。磁能与静电储存规模较小，但会出现在关于磁铁、带电棒和电容器的题目中。
| Store | 储存 | Example | 例子 |
| Kinetic 动能 | A cyclist moving at 6 m/s | 以 6 m/s 骑行的自行车 |
| Gravitational potential 重力势能 | A book on a shelf | 书架上的书 |
| Elastic potential 弹性势能 | A drawn bowstring | 拉开的弓弦 |
| Thermal 热能 | A cup of hot tea | 一杯热茶 |
| Chemical 化学能 | A charged phone battery | 充好电的手机电池 |
| Nuclear 核能 | Uranium fuel in a reactor | 反应堆中的铀燃料 |
| Magnetic 磁能 | Two repelling magnets held together | 被压在一起互相排斥的两块磁铁 |
| Electrostatic 静电 | Two like charges pushed together | 被推近的同种电荷 |
6. Work Done, Force and Power | 做功、力与功率
is the force in newtons and s is the distance moved along the line of the force in metres.
做功不过是力传递能量的另一种说法。当力使物体移动一段距离时，做功为 W = F s，其中 F 是力，单位为牛顿，s 是沿力方向移动的距离，单位为米。
W = F s 1 J = 1 N m
If the force is applied at an angle, only the component of the force in the direction of motion does work. If the object does not move, no work is done, no matter how large the force is. This is why holding a heavy bag still for ten minutes transfers no energy, even though your muscles feel tired.
若力的方向与运动方向成一定角度，只有沿运动方向的分力做功。若物体没有移动，无论力多大都不做功。这就是为什么你把沉重的包静止提十分钟并不传递能量，尽管肌肉感到疲劳。
ed in joules and t is the time in seconds. The unit of power is the watt, and 1 W = 1 J/s.
能量传递的速率称为功率：P = E / t，其中 E 是传递的能量，单位为焦耳，t 是时间，单位为秒。功率的单位是瓦特，1 W = 1 J/s。
P = E / t P = W / t
udent lifts a 4 kg box 1.5 m onto a shelf in 2 s. The work done against gravity is W = m g ∆ the useful output is less than the total energy the student transfers, because the student's muscles also warm up.
例题：一名学生用 2 s 把 4 kg 的箱子抬高 1.5 m 放上书架。克服重力做功 W = m g ∆h = 4 × 9.8 × 1.5 = 58.8 J。功率为 58.8 ÷ 2 = 29.4 W。注意有效输出小于学生传递的总能量，因为学生的肌肉也在发热。
7. Efficiency and Sankey Diagrams | 效率与能流图
Efficiency can be expressed as useful output energy transfer divided by total input energy transfer; it is always less than 1 (or 100%) due to dissipative forces. Efficiency has no unit, because it is a ratio of two energies.
效率可表示为有效输出能量传递除以总输入能量传递；由于耗散力的存在，它总是小于 1（或 100%）。效率没有单位，因为它是两个能量的比值。
efficiency = useful output ÷ total input
÷ 500 = 0.7, or 70 per cent. The remaining 150 J is dissipated, usually into the thermal store of the motor and the surroundings.
把效率化为百分数需乘以 100。一台接收 500 J、输出 350 J 有用动能的电动机，效率为 350 ÷ 500 = 0.7，即 70%。其余 150 J 被耗散，通常进入电动机及环境的热能储存。
A Sankey diagram shows the same information visually. The width of each arrow is proportional to the amount of energy it represents. The input arrow enters on the left, the useful output arrow continues straight ahead, and the wasted arrows branch off downwards or upwards.
能流图（桑基图）以图形方式表达同样的信息。每个箭头的宽度与它所代表的能量成正比。输入箭头从左侧进入，有效输出箭头笔直向前，损耗箭头向下或向上分支。
Examiners often ask you to calculate efficiency from a Sankey diagram rather than from numbers written in a table. Measure or read the widths carefully, and remember that the useful arrow plus all wasted arrows must equal the input arrow.
考官常要求你从能流图而非表格数据中计算效率。请仔细测量或读取箭头宽度，并记住：有效箭头加上所有损耗箭头之和必须等于输入箭头。
If a question asks how to improve efficiency, the answer is always to reduce dissipation: lubricate moving parts, reduce air resistance, insulate hot objects, or use a more efficient component.
如果题目问如何提高效率，答案总是减少耗散：给运动部件润滑、减小空气阻力、给高温物体保温，或换用效率更高的部件。
8. Specific Heat Capacity and Heating | 比热容与热传递
sured in joules per kilogram per degree Celsius (J/kg°C). The equation you need is E = m c ∆θ.
比热容是把 1 kg 某物质的温度升高 1 °C 所需的能量，单位为焦耳每千克每摄氏度（J/kg°C）。所需公式为 E = m c ∆θ。
E = m c ∆θ
Water has a very high specific heat capacity of about 4200 J/kg°C, which is why it is used in central heating systems and why coastal cities have milder winters than inland cities.
水的比热容非常高，约为 4200 J/kg°C，这正是它被用于中央供暖系统的原因，也是沿海城市冬季比内陆城市更温和的原因。
The required practical for this topic involves heating a metal block with an electric heater and measuring the temperature rise. You must control the variables carefully: use the same mass of metal, the same starting temperature and the same heater power each time.
本主题的必做实验是用电加热器加热金属块并测量温升。你必须仔细控制变量：每次使用相同质量的金属、相同的初始温度和相同的加热功率。
Sources of error include energy escaping to the surroundings, a thermometer that does not reach the centre of the block, and heat lost from the heater itself. Repeating the experiment and taking a mean reduces random error but not systematic error.
误差来源包括能量散失到环境、温度计未能深入金属块中心、加热器自身的热损失。重复实验并取平均值可减小随机误差，但无法消除系统误差。
9. Electricity Foundations | 电学基础
ulombs, I is current in amperes and t is time in seconds. One ampere is one coulomb per second.
电流是电荷流动的速率：Q = I t，其中 Q 是电荷，单位为库仑，I 是电流，单位为安培，t 是时间，单位为秒。1 安培等于每秒 1 库仑。
potential difference of 1 volt means that 1 joule of energy is transferred for every 1 coulomb of charge that passes.
电位差是每单位电荷传递的能量：V = W / Q。1 伏特的电位差意味着每通过 1 库仑电荷就传递 1 焦耳能量。
; V = W / Q V = I R P = V I
In a series circuit the current is the same everywhere, the potential differences add up to the supply voltage, and the total resistance is the sum of the individual resistances. In a parallel circuit the potential difference across each branch is the same, and the currents in the branches add up to the current from the supply.
在串联电路中，各处电流相同，各电位差之和等于电源电压，总电阻等于各电阻之和。在并联电路中，各支路两端的电位差相同，各支路电流之和等于电源输出的电流。
tant temperature, so its current-potential difference graph is a straight line through the origin. A filament lamp does not, because its resistance increases as it gets hotter; its
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