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Year 9 WJEC Biology: Quick Reference Handbook of Formulas and Theorems | Year 9 WJEC 生物:公式定理速查手册

2026-07-18 23:57 · 本文部分内容由AI辅助创作

📚 Year 9 WJEC Biology: Quick Reference Handbook of Formulas and Theorems | Year 9 WJEC 生物:公式定理速查手册

This quick-reference guide brings together the key formulae, equations, and theorems you will use throughout Year 9 WJEC Biology. Mastering these will help you solve numerical problems, predict experimental outcomes, and interpret data confidently in both coursework and examinations.

本速查指南汇集了 Year 9 WJEC 生物课程中使用的关键公式、方程和定理。掌握它们将帮助你解决数值问题、预测实验结果,并在课程作业和考试中自信地解读数据。

1. Microscopy and Magnification | 显微镜与放大率

Magnification = Image size / Actual size

放大率 = 图像大小 / 实际大小

Image size is the size of the specimen measured on the micrograph or drawing; actual size is its real-life size. Both must be in the same unit, usually millimetres (mm) or micrometres (µm).

图像大小是在显微照片或绘图上测得的标本尺寸;实际大小是它的真实尺寸。两者必须使用相同单位,通常为毫米(mm)或微米(µm)。

To rearrange the formula: Image size = Magnification × Actual size and Actual size = Image size / Magnification.

公式变形:图像大小 = 放大率 × 实际大小;实际大小 = 图像大小 / 放大率。

Common unit conversions essential for microscopy:

显微镜常用的单位换算:

Unit (单位)Equivalent (等值)
1 metre (m) / 1 米1000 millimetres (mm) / 1000 毫米
1 millimetre (mm) / 1 毫米1000 micrometres (µm) / 1000 微米
1 micrometre (µm) / 1 微米1000 nanometres (nm) / 1000 纳米

res 50 mm on a drawing and its actual size is 0.02 mm. Magnification = 50 / 0.02 = 2500 ×.

计算示例:一张图上细胞的长度为 50 mm,其实际大小为 0.02 mm。放大率 = 50 / 0.02 = 2500 倍。


2. Surface Area to Volume Ratio | 表面积与体积比

For a cube of side length L: Surface area = 6L² and Volume = L³.

对于边长为 L 的立方体:表面积 = 6L²,体积 = L³。

The surface area to volume ratio (SA:V) is 6L² / L³ = 6 / L. As an organism or cell grows larger, its SA:V decreases.

表面积与体积比 (SA:V) 为 6L² / L³ = 6 / L。随着生物体或细胞增大,其 SA:V 比值下降。

For a sphere: Surface area = 4πr², Volume = (4/3)πr³, so SA:V = 3/r.

对于球体:表面积 = 4πr²,体积 = (4/3)πr³,因此 SA:V = 3/r。

A high SA:V allows efficient diffusion of substances into and out of cells. This is why actively dividing cells are small and why larger organisms need specialised exchange surfaces (e.g., lungs, gills).

高 SA:V 有利于物质高效地进出细胞。这就是为什么活跃分裂的细胞体积都很小,以及为什么较大的生物体需要专门的交换表面(如肺、鳃)。


3. Rate of Reaction in Enzyme Experiments | 酶实验中的反应速率

The rate of an enzyme-catalysed reaction can be calculated as:

酶催化反应的速率可以通过以下方式计算:

Rate = Change in amount of product or substrate / Time taken

速率 = 产物或底物的变化量 / 所用时间

In many school experiments (e.g., amylase breaking down starch), the rate is measured as the reciprocal of the time taken for a visible change: Rate = 1 / time (s⁻¹). A shorter time indicates a faster rate.

在许多学校实验中(如淀粉酶分解淀粉),速率通过可视变化所需时间的倒数来衡量:速率 = 1 / 时间 (s⁻¹)。时间越短,表示速率越快。

Units depend on what is measured: if gas volume is collected, rate might be in cm³/s; if mass change is measured, rate could be g/min.

单位取决于测量对象:如果收集气体体积,速率单位可以是 cm³/s;如果测量质量变化,速率单位可以是 g/min。

Typical expected results: the rate increases with temperature up to an optimum, then falls rapidly as the enzyme denatures. A similar bell-shaped curve is seen for pH.

典型的预期结果:速率随温度升高而增加,直至最适温度,然后因酶变性而急剧下降。pH 的影响也呈现类似的钟形曲线。


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4. Percentage Change in Mass | 质量百分比变化

In osmosis experiments (e.g., placing potato cylinders in different sugar concentrations), the percentage change in mass quantifies water gain or loss:

在渗透实验中(例如将土豆条置于不同浓度的糖溶液中),质量百分比变化用于量化水分的得失:

Percentage change = (Final mass – Initial mass) / Initial mass × 100%

百分比变化 = (最终质量 – 初始质量) / 初始质量 × 100%

A positive value means mass was gained (water moved into the cells by osmosis). A negative value means mass was lost (water moved out). Plotting this against solute concentration helps identify the isotonic point where no net change occurs.

正值表示质量增加(水通过渗透进入细胞)。负值表示质量减少(水向外流出)。将该值对溶液浓度作图,有助于确定没有净变化的等渗点。


5. Photosynthesis Equations | 光合作用方程式

The overall word equation for photosynthesis:

光合作用的总文字方程式:

carbon dioxide + water → glucose + oxygen

二氧化碳 + 水 → 葡萄糖 + 氧气

The balanced symbol equation, showing that the reaction requires light energy and chlorophyll:

配平的符号方程式,表明该反应需要光能和叶绿素:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Photosynthesis is an endothermic reaction; it takes in energy from sunlight. The rate can be limited by light intensity, carbon dioxide concentration, and temperature.

光合作用是吸热反应;它吸收来自阳光的能量。其速率可能受光照强度、二氧化碳浓度和温度的限制。


6. Respiration Equations | 呼吸作用方程式

Aerobic respiration requires oxygen and releases a large amount of energy:

有氧呼吸需要氧气,并释放大量能量:

glucose + oxygen → carbon dioxide + water (+ energy)

葡萄糖 + 氧气 → 二氧化碳 + 水 (+ 能量)

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Anaerobic respiration in animals produces lactic acid and relatively little energy:

动物的无氧呼吸产生乳酸和相对较少的能量:

glucose → lactic acid (+ energy)

葡萄糖 → 乳酸 (+ 能量)

Published by TutorHao | Year 9 Biology Revision Series | aleveler.com

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