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Case Study Practice for Year 9 OCR Biology | 案例分析实战演练:Year 9 OCR 生物

2026-07-18 11:52 · 本文部分内容由AI辅助创作

📚 Case Study Practice for Year 9 OCR Biology | 案例分析实战演练:Year 9 OCR 生物

Case studies are a powerful way to bridge the gap between theory and real-world investigation. In Year 9 OCR Biology, you are expected not only to recall scientific facts but also to analyse data, interpret graphs, and evaluate experimental designs. This article presents a series of practical case studies covering key topics: ecosystems, natural selection, enzyme action, osmosis, photosynthesis, inheritance, and microscopy. Each case study provides background information, sample data, and guided questions to help you develop the analytical skills required for your assessments.

案例分析是连接理论与现实研究的一座有力桥梁。在 Year 9 OCR 生物课程中,你不仅要记忆科学事实,还需要分析数据、解读图表并评估实验设计。本文围绕生态系统、自然选择、酶的作用、渗透作用、光合作用、遗传和显微镜观察等关键主题,呈现了一系列实战案例。每个案例都提供了背景信息、示例数据和引导性问题,帮助你培养评估所需的各项分析技能。


1. Introduction to Biology Case Studies | 生物学案例研究简介

A case study in biology is a detailed examination of a real or simulated situation that allows you to apply scientific concepts. You might be asked to identify variables, suggest improvements to a method, calculate rates, or explain unexpected results. Success depends on reading the information carefully, linking the evidence to biological principles, and using precise scientific language.

生物学案例研究是对真实或模拟情境的细致剖析,它让你有机会应用科学概念。你可能会被要求识别变量、建议方法的改进、计算速率或解释意外结果。成功的关键在于仔细阅读信息,将证据与生物学原理联系起来,并使用准确的科学语言。

Throughout this article, you will encounter data tables, graphs, and descriptions of experiments. Treat each case as if you were the scientist: ask yourself what the data shows, whether the conclusion is valid, and what you would do next.

在整篇文章中,你将遇到数据表、图表和实验描述。请把每个案例都当作自己是科学家来对待:问问自己数据显示了什么,结论是否有效,以及下一步该怎么做。


2. Case Study 1: Investigating a Pond Ecosystem | 案例1:池塘生态系统调查

A group of Year 9 students sampled a local pond to study the distribution of aquatic invertebrates. They recorded the number of mayfly nymphs, freshwater shrimps, and water lice at three different distances from the bank: 0.5 m, 2.0 m, and 4.0 m. The water depth increased with distance. The results are shown in the table below.

一组 Year 9 学生对当地池塘进行采样,研究水生无脊椎动物的分布。他们分别在距岸边 0.5 m、2.0 m 和 4.0 m 处记录了蜉蝣稚虫、淡水虾和栉水虱的数量。水深随距离增加而增加。结果如下表所示。

Distance (m)Mayfly nymphsFreshwater shrimpsWater lice
0.52158
2.01293
4.02231

Mayfly nymphs are known to require high levels of dissolved oxygen, whilst water lice can tolerate low oxygen conditions. Based on this information, the students concluded that oxygen concentration decreases towards the bank. Explain whether the data supports this conclusion. What could the students do to measure abiotic factors directly?

已知蜉蝣稚虫需要高浓度的溶解氧,而栉水虱能够耐受低氧环境。根据这一信息,学生们得出“岸边的氧气浓度较低”的结论。请解释数据是否支持这一结论。学生们还可以怎样直接测量非生物因素?


3. Case Study 2: The Peppered Moth – Natural Selection in Action | 案例2:桦尺蛾——自然选择在行动

The peppered moth (Biston betularia) exists in two main forms: a pale, speckled variety and a dark, melanic form. Before the Industrial Revolution, tree trunks were covered with light-coloured lichens, and the pale moths were well camouflaged. As pollution killed the lichens and darkened the bark with soot, the dark moths became better hidden from predators. Data collected in Manchester showed that in 1848, only 2% of moths were dark; by 1895, this had risen to 95%.

桦尺蛾有两种主要形态:一种浅色斑点型,一种深色黑化型。工业革命前,树干上长满浅色地衣,浅色蛾子伪装良好。随着污染杀死地衣并使树皮被煤烟熏黑,深色蛾子更不易被捕食者发现。在曼彻斯特收集的数据显示,1848 年仅有 2% 的蛾子是深色的;到 1895 年,这一比例上升到 95%。

Identify the selection pressure in this case study. Explain why the frequency of the dark allele increased over time. If air quality improves and lichens return, predict what might happen to the moth population.

请指出本案例中的选择压力。解释为什么深色等位基因的频率会随时间增加。如果空气质量改善、地衣重新出现,预测蛾类种群可能发生什么变化。


4. Case Study 3: Enzyme Action – Catalase and Hydrogen Peroxide | 案例3:酶的作用——过氧化氢酶与过氧化氢

Catalase is an enzyme found in many living tissues, including potato and liver. It speeds up the breakdown of hydrogen peroxide into water and oxygen. The reaction can be written as:

过氧化氢酶是一种存在于许多生物组织(包括土豆和肝脏)中的酶。它能加速过氧化氢分解为水和氧气。反应可表示为:

2H₂O₂ → 2H₂O + O₂

Students investigated how temperature affects catalase activity. They placed potato discs in hydrogen peroxide solution at 0°C, 20°C, 40°C, and 60°C and measured the volume of oxygen produced in one minute. Results are shown below.

学生们研究了温度如何影响过氧化氢酶的活性。他们将土豆圆片放入不同温度(0°C、20°C、40°C 和 60°C)的过氧化氢溶液中,测量一分钟内产生的氧气体积。结果如下。

Temperature (°C)Oxygen produced (cm³)
04
2015
4028
602

Explain the pattern in the data using your knowledge of enzyme structure and denaturation. Suggest why there is very little oxygen produced at 60°C.

运用你对酶结构和变性的知识,解释数据中的规律。并说明为什么在 60°C 时产生的氧气极少。


5. Case Study 4: Osmosis in Potato Strips | 案例4:土豆条中的渗透作用

Osmosis is the net movement of water molecules from a region of higher water potential to a region of lower water potential through a partially permeable membrane. A student wanted to find the concentration of sugar solution that produces no net water movement in potato tissue. They weighed strips of potato, placed them in different sugar solutions for 30 minutes, reweighed them, and calculated the percentage change in mass.

渗透作用是水分子通过部分透性膜从水势较高的区域向水势较低的区域的净移动。一名学生想找到使土豆组织不发生净水分移动的糖溶液浓度。他们称量了土豆条,将其放入不同浓度的糖溶液中 30 分钟,再次称重,并计算质量变化百分比。

Percentage change = (Final mass − Initial mass) ÷ Initial mass × 100%

Sugar conc. (mol/dm³)Initial mass (g)Final mass (g)Change (%)
0.03.23.5+9.4
0.23.13.2+3.2
0.43.33.1−6.1
0.63.02.7−10.0

Plot the percentage change against concentration and estimate the concentration where the line crosses zero. Explain what this value represents in terms of the water potential of potato cells.

请绘制质量变化百分比与浓度的关系图,并估算曲线过零点的浓度。解释该数值在土豆细胞水势方面代表什么意义。


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6. Case Study 5: Photosynthesis and Light Intensity | 案例5:光合作用与光强度

Photosynthesis is the process by which plants use light energy to convert carbon dioxide and water into glucose and oxygen. The overall equation is:

光合作用是植物利用光能将二氧化碳和水转化为葡萄糖和氧气的过程。总方程式为:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

A student used pondweed to investigate the effect of light intensity on the rate of photosynthesis. They counted the number of oxygen bubbles produced per minute when a lamp was placed at distances of 10 cm, 20 cm, 30 cm, and 40 cm from the plant. Light intensity is inversely proportional to the square of the distance (I ∝ 1/d²).

一名学生利用水藻研究光强度对光合作用速率的影响。他们将灯分别置于距植株 10 cm、20 cm、30 cm 和 40 cm 处,统计每分钟产生的氧气气泡数。光强度与距离的平方成反比 (I ∝ 1/d²)。

Distance (cm)Bubbles per minute
1045
2028
3015
408

Use the data to describe the relationship between distance and photosynthesis rate. Suggest why the number of bubbles does not simply halve when the distance doubles. What control variables should be kept constant in this experiment?

利用数据描述距离与光合作用速率之间的关系。解释为什么当距离加倍时,气泡数并不会简单地减半。本实验中应控制哪些控制变量保持不变?


7. Case Study 6: Inheritance of Cystic Fibrosis | 案例6:囊性纤维化的遗传

Cystic fibrosis (CF) is an inherited disorder caused by a recessive allele (f). The normal allele (F) is dominant. A couple are both carriers of the CF allele, meaning they each have the genotype Ff. They want to know the probability of having a child with cystic fibrosis.

囊性纤维化是由隐性等位基因 (f) 引起的一种遗传病。正常等位基因 (F) 为显性。一对夫妇都是 CF 等位基因的携带者,意味着他们的基因型均为 Ff。他们想知道生育一个患囊性纤维化孩子的概率。

Draw a Punnett square to show the possible genotypes of their offspring. Give the phenotypic ratio of normal to affected children. If the couple's first child does not have CF, does that change the risk for the second child? Explain your answer.

请绘制庞纳特方格,显示他们后代可能的基因型。给出正常与患病子女的表型比。如果夫妇的第一个孩子没有 CF,这会不会改变第二个孩子的患病风险?请解释你的答案。


8. Case Study 7: Microscopy and Cell Size Measurement | 案例7:显微镜观察与细胞大小测量

yepiece graticule calibrated with a stage micrometer. They found that 40 graticule units corresponded to 200 µm on the stage micrometer. One cell measured 4 graticule units in length.

学生们制作了洋葱表皮细胞的玻片标本,并使用带有 ×10 目镜和 ×40 物镜的光学显微镜进行观察。他们使用了经镜台测微尺标定的目镜测微尺。发现 40 个测微尺单位对应镜台测微尺上的 200 µm。测得一个细胞长度为 4 个测微尺单位。

Calculate the actual length of one onion cell in micrometres. What is the total magnification used? Explain why staining the cells with iodine solution helps to make certain structures more visible.

计算一个洋葱细胞的实际长度(以微米为单位)。使用的总放大倍数是多少?解释为什么用碘液染色能使某些结构更容易观察。


9. Key Skills for Tackling Case Studies | 应对案例研究的关键技能

Approaching a biology case study systematically increases your chance of scoring full marks. First, identify the independent, dependent, and control variables whenever an experiment is described. Second, when looking at data tables, look for trends, anomalies, and relationships – do not just restate the numbers. Third, when asked to 'evaluate', discuss both strengths and limitations of the method and suggest realistic improvements. Finally, always link your answers back to biological theory, using terms such as 'active site', 'water potential', 'natural selection', or 'recessive allele' where appropriate.

系统性地处理生物学案例研究可提高你获得满分的几率。首先,每当实验描述出现时,确认自变量、因变量和控制变量。其次,查看数据表时要寻找趋势、异常值和关系——不要仅仅重复数字。第三,当被要求“评价”时,既要讨论方法的优点,也要讨论局限性,并提出切合实际的改进建议。最后,务必将答案与生物学理论联系起来,在合适的地方使用诸如“活性位点”、“水势”、“自然选择”或“隐性等位基因”等术语。

Another common requirement is graph drawing. Always label axes with quantity and unit, choose a sensible scale, and use a sharp pencil to plot points precisely. If you are asked to draw a line of best fit, decide whether it should be straight or curved based on the underlying biological principle.

另一个常见的要求是绘制图表。务必为坐标轴标注量和单位,选择合适的比例,并用削尖的铅笔精确描点。如果要求绘制最佳拟合线,请根据背后的生物学原理决定它应为直线还是曲线。


10. Conclusion: Applying Knowledge to Real-World Scenarios | 结论:将知识应用于现实情境

The case studies in this article reflect the style of questions you will meet in Year 9 OCR Biology assessments and beyond. They are designed to test not just what you know, but how well you can use that knowledge to interpret unfamiliar situations. Practise regularly by exploring data from news articles, laboratory investigations, or ecological surveys. The more you engage with real examples, the more confident you will become in spotting patterns, critiquing methods, and proposing valid scientific explanations.

本文中的案例研究反映了你在 Year 9 OCR 生物考试及以后会遇到的问题风格。它们不仅测试你知道了什么,更测试你如何运用这些知识来解读陌生情境。通过分析新闻文章、实验室探究或生态调查中的数据来定期练习。你接触的实例越多,你在识别规律、评判方法并提出合理解释方面就会越自信。

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