📚 Year 9 AQA Physics: Cross-disciplinary Integrated Question Training | Year 9 AQA 物理：跨学科综合题型训练
In Year 9 AQA Physics, you will encounter exam questions that blend physics concepts with other subjects such as Maths, Biology, Chemistry, Geography, and Technology. Mastering cross-disciplinary problems not only deepens your understanding but also prepares you for the demands of the GCSE course. This article provides targeted practice with integrated questions, each combining physics with another discipline. Work through the examples, apply your skills, and build confidence for your assessments.
在 Year 9 AQA 物理中，你会遇到将物理概念与数学、生物、化学、地理和技术等其他学科相结合的考题。掌握跨学科问题不仅加深你对知识的理解，还能为应对 GCSE 课程的要求做好准备。本文提供针对性的综合题型训练，每道题都将物理与另一门学科融合。通过练习这些例题，运用你的技能，为考试树立信心。
1. Physics & Maths: Speed and Distance-Time Graphs | 物理与数学：速度和距离-时间图
Speed is a fundamental concept in physics, but it relies heavily on mathematical skills. You need to be able to calculate speed, distance, and time, convert units, and interpret distance-time graphs. The gradient of a distance-time graph equals speed.
速度是物理中的基础概念，但高度依赖数学技能。你需要能够计算速度、路程和时间，进行单位换算，并解释距离-时间图。距离-时间图的斜率等于速度。
Example: A bus travels 150 km in 2 hours. Calculate its average speed in km/h, then convert to m/s. Sketch a distance-time graph for the journey and explain how you would determine speed from the graph.
例题：一辆公交车 2 小时行驶了 150 km。计算它的平均速度（以 km/h 为单位），并换算成 m/s。画出此次行程的距离-时间图，并解释如何从图中确定速度。
Step 1: Average speed = total distance ÷ total time = 150 km ÷ 2 h = 75 km/h.
步骤 1：平均速度 = 总路程 ÷ 总时间 = 150 km ÷ 2 h = 75 km/h。
000 m and 1 h = 3600 s. So 75 km/h = 75 × 1000 m ÷ 3600 s = 20.8 m/s (to 1 decimal place).
步骤 2：将 75 km/h 换算成 m/s，注意 1 km = 1000 m，1 h = 3600 s。因此 75 km/h = 75 × 1000 m ÷ 3600 s = 20.8 m/s（保留一位小数）。
= 75 km/h, which matches the calculated average speed. A steeper line means higher speed.
步骤 3：距离-时间图显示从 (0,0) 到 (2 h, 150 km) 的一条直线。斜率 = 纵轴变化 ÷ 横轴变化 = 150 km ÷ 2 h = 75 km/h，与计算的平均速度一致。线越陡，表示速度越快。
2. Physics & Geography: Energy Resources and Power Generation | 物理与地理：能源资源与发电
Physics helps us understand electricity generation, while geography explains where energy resources are found and how suitable they are. Wind power questions often combine turbine physics with capacity factor data.
物理帮助我们理解发电原理，而地理则解释能源资源的位置及其适用性。风能问题常将涡轮机物理与容量因子数据相结合。
Example: A wind turbine has a rated power of 2 MW. Its capacity factor is 30% due to variable wind. Calculate the energy generated in one full day (24 hours) in MWh. If this turbine supplies 400 homes, estimate the daily energy consumption per home.
例题：一台风力涡轮机的额定功率为 2 MW。由于风速变化，其容量
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