← 返回资讯屏轩教育 · 行业资讯

Year 9 AQA Further Mathematics: Unit Test Mock Paper Analysis | 九年级 AQA 进阶数学:单元测试模拟卷解析

2026-07-18 09:04 · 本文部分内容由AI辅助创作

📚 Year 9 AQA Further Mathematics: Unit Test Mock Paper Analysis | 九年级 AQA 进阶数学:单元测试模拟卷解析

This article provides a detailed walkthrough of a mock unit test for Year 9 AQA Further Mathematics. We break down each question type, offering step-by-step solutions and key revision notes to strengthen your understanding of core topics.

本文针对九年级 AQA 进阶数学单元测试模拟卷进行详细解析,逐一拆解各类题型,给出分步解答和关键复习笔记,帮助你巩固核心知识点。


1. Simplifying Algebraic Expressions | 代数表达式化简

Example Question: Simplify 5x + 3y – 2x + 7y.

例题:化简表达式 5x + 3y – 2x + 7y。

Identify like terms: the x terms are 5x and –2x; the y terms are 3y and 7y. Combine them.

识别同类项:x 项为 5x 和 –2x;y 项为 3y 和 7y。将它们合并。

5x – 2x = 3x, 3y + 7y = 10y. Therefore, the simplified expression is 3x + 10y.

5x – 2x = 3x,3y + 7y = 10y。因此化简结果为 3x + 10y。

Always reorder terms carefully and watch the signs in front of each term.

务必仔细观察每一项前面的符号,并仔细重新排列项。


2. Expanding and Factorising | 展开与因式分解

Example 1 (Expand): Expand and simplify 3(x + 4) – 2(x – 1).

例题1(展开):展开并化简 3(x + 4) – 2(x – 1)。

Distribute: 3x + 12 – 2x + 2. Then combine like terms: (3x – 2x) + (12 + 2) = x + 14.

分配:3x + 12 – 2x + 2。然后合并同类项:(3x – 2x) + (12 + 2) = x + 14。

Example 2 (Factorise): Factorise x² + 5x + 6.

例题2(因式分解):因式分解 x² + 5x + 6。

Find two numbers that multiply to 6 and add to 5: they are 2 and 3. So the factorised form is (x + 2)(x + 3).

找出两个相乘得6、相加得5的数:2和3。因此分解结果为 (x + 2)(x + 3)。

Always check by expanding the brackets to confirm the original expression.

务必通过展开括号检验是否能还原为原表达式。


3. Solving Linear Equations | 解线性方程

Example: Solve 2(3x – 1) = 4x + 10.

例题:解方程 2(3x – 1) = 4x + 10。

Expand the bracket: 6x – 2 = 4x + 10. Subtract 4x from both sides: 2x – 2 = 10. Add 2: 2x = 12. Divide by 2: x = 6.

展开括号:6x – 2 = 4x + 10。两边减去4x:2x – 2 = 10。加2:2x = 12。除以2:x = 6。

Check by substituting x = 6 back into the original equation: left side 2(18–1)=34, right side 24+10=34. Correct.

将 x=6 代入原方程检验:左边 2(18–1)=34,右边 24+10=34。正确。


广告 / Sponsored

4. Solving Inequalities | 解不等式

Example: Solve 3x – 7 < 5 and illustrate the solution on a number line.

例题:解不等式 3x – 7 < 5 并在数轴上表示解集。

Add 7 to both sides: 3x < 12. Divide by 3: x < 4.

两边加7:3x < 12。除以3:x < 4。

On a number line, draw an open circle at 4 and shade to the left. Remember: if multiplying or dividing by a negative number, reverse the inequality sign.

在数轴上,在4处画空心圆并向左涂色。记住:乘以或除以负数时,不等号方向要改变。


5. Simultaneous Equations | 联立方程组

Example: Solve the simultaneous equations: 2x + y = 7, x – y = 2.

例题:解联立方程组:2x + y = 7,x – y = 2。

Add the two equations to eliminate y: (2x + y) + (x – y) = 7 + 2 → 3x = 9, so x = 3.

将两式相加消去 y:(2x + y) + (x – y) = 7 + 2 → 3x = 9,所以 x = 3。

Substitute x = 3 into x – y = 2: 3 – y = 2 → y = 1. Thus the solution is x = 3, y = 1.

将 x=3 代入 x – y = 2:3 – y = 2 → y = 1。因此解为 x = 3, y = 1。


6. Sequences and the nth Term | 数列与第n项

Example: Find the nth term of the arithmetic sequence: 4, 9, 14, 19, …

例题:求等差数列 4, 9, 14, 19, … 的第n项公式。

The difference between terms is +5, so the coefficient of n is 5. The nth term is 5n – 1 (since 5(1) – 1 = 4).

项之间的差为 +5,因此 n 的系数为 5。第n项公式为 5n – 1(因为 5×1 – 1 = 4)。

Use the formula to find the 10th term: 5(10) – 1 = 49.

用此公式求第10项:5×10 – 1 = 49。


7. Equation of a Straight Line |

Published by TutorHao | Year 9 进阶数学 Revision Series | aleveler.com

广告 / Sponsored
ALevel国际高中数学课程 剑桥牛津培生 CAIE Edexcel AQA国际考试局 课本练习册复习指南 英文教材进…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥69.8

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao