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Year 8 Cambridge Physics: Interdisciplinary Problem-Solving Practice | 剑桥8年级物理:跨学科综合题型训练

2026-07-18 02:12 · 本文部分内容由AI辅助创作

📚 Year 8 Cambridge Physics: Interdisciplinary Problem-Solving Practice | 剑桥8年级物理:跨学科综合题型训练

Cross-curricular questions in Year 8 Cambridge Physics test your ability to apply physics concepts in real-world contexts that involve mathematics, biology, chemistry, geography, and other subjects. This article provides guided practice with worked examples to help you build confidence and skills for these types of problems.

剑桥8年级物理中的跨学科题目考察你将物理概念应用于涉及数学、生物、化学、地理等学科的真实情境的能力。本文通过提供带解析的例题进行引导练习,帮助你建立信心并提升解答此类问题的技巧。


1. Introduction to Interdisciplinary Problem-Solving | 跨学科解题入门

Interdisciplinary questions require you to identify the relevant physics principle first, then apply knowledge from another subject such as using maths to calculate, or linking to biological structures. Always read the question carefully, underline key terms, and decide what the question is really asking.

跨学科题目要求你首先识别相关的物理原理,然后运用另一学科的知识——例如用数学进行计算,或联系生物结构。始终仔细读题,划出关键词,并判断问题到底在问什么。


2. Physics and Mathematics: Speed, Graphs and Equations | 物理与数学:速度、图表与方程

In Physics, we often use the formula for average speed: v = s ÷ t, where s is distance and t is time. Mathematics helps us interpret distance–time graphs and calculate gradients.

在物理中,我们常使用平均速度公式:v = s ÷ t,其中s为距离,t为时间。数学帮助我们解读距离-时间图并计算斜率。

Worked Example: A cyclist travels 300 metres in 50 seconds. Calculate the average speed.

例题:一位自行车手在50秒内行驶了300米。计算平均速度。

We use v = s ÷ t. Substitute: v = 300 m ÷ 50 s = 6 m/s. This straightforward calculation also shows that the line on a distance–time graph would have a gradient of 6 m/s.

使用 v = s ÷ t。代入:v = 300 m ÷ 50 s = 6 m/s。这一直接计算也表明距离-时间图上的线段斜率为6 m/s。

Another typical question gives a distance–time graph with two line segments: a straight line from (0,0) to (10 s, 200 m) and then a horizontal line from (10 s, 200 m) to (20 s, 200 m). Interpret the motion.

另一种典型题目给出距离-时间图,包含两段:一段从(0,0)到(10 s, 200 m)的直线,然后一段从(10 s, 200 m)到(20 s, 200 m)的水平线。解释运动情况。

al line means the object is stationary (distance not changing) for the next 10 seconds. This combines graph skills from maths with motion concepts.

第一段显示恒定速度为200 m ÷ 10 s = 20 m/s。水平线表示物体在接下来的10秒内静止(距离不变)。这结合了数学中的图形技巧与运动概念。


3. Physics and Biology: Light, Eyes, and Vision | 物理与生物:光、眼睛与视觉

The eye is a biological organ that uses a lens to focus light onto the retina. Short-sightedness (myopia) occurs when light focuses in front of the retina, which we correct with a diverging (concave) lens. This connects optics from physics with human biology.

眼睛是一个生物器官,利用晶状体将光聚焦在视网膜上。近视发生在光聚焦于视网膜之前时,我们用发散(凹)透镜进行矫正。这联系了物理中的光学与人体生物学。

Worked Example: A student cannot see distant objects clearly but can read a book. What type of lens is needed in her glasses? Explain why.

例题:一位学生看不清远处的物体,但能阅读书本。她的眼镜需要哪种透镜?解释原因。

She is short-sighted. The eye's lens system is too strong, so light rays meet before the retina. A concave lens diverges the rays slightly before they enter the eye, allowing the focus to fall on the retina. This shows physics principles applied to a biological problem.

她是近视。眼睛的晶状体系统过强,使得光线在视网膜前汇聚。凹透镜在光线进入眼睛前略微发散光束,使焦点落在视网膜上。这展示了应用于生物问题的物理原理。


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4. Physics and Chemistry: Energy in Chemical Reactions | 物理与化学:化学反应中的能量

In physics, we learn that energy can be stored as chemical energy and transferred as heat. Exothermic reactions, such as the oxidation of iron in a hand warmer, release thermal energy. This overlaps with chemistry topics on reactions.

在物理中,我们学习能量可以储存为化学能并以热量形式传递。放热反应,如暖手宝中铁的氧化,释放热能。这与化学中的反应主题重叠。

Worked Example: ses from 20 °C to 54 °C. The mass of the solution is 50 g. Calculate the energy released. (Specific heat capacity of solution ≈ 4.2 J/g°C)

例题:一个可重复使用的暖手宝含有过饱和乙酸钠溶液。当点击金属片时,它结晶,温度从20 °C升至54 °C。溶液质量为50 g。计算释放的能量。(溶液的比热容约为4.2 J/g°C)

We use the equation E = m c Δθ is mass, c is specific heat capacity, and Δθ is temperature change. Δθ = 54 − 20 = 34 °C. E = 50 g × 4.2 J/g°C × 34 °C = 7140 J. This interdisciplinary problem links physics (energy, heat) with chemistry (crystallisation).

我们使用公式 E = m c Δθ,其中m为质量,c为比热容,Δθ为温度变化。Δθ = 54 − 20 = 34 °C。E = 50 g × 4.2 J/g°C × 34 °C = 7140 J。这个跨学科问题将物理(能量、热量)与化学(结晶)联系起来。


5. Physics and Geography: Seismic Waves and Earth's Structure | 物理与地理:地震波与地球结构

Seismic waves from earthquakes provide evidence about the Earth's interior. P-waves (primary waves) are longitudinal and can travel through solids and liquids. S-waves (secondary waves) are transverse and only travel through solids. Geography uses this to infer the liquid outer core.

地震产生的地震波提供了地球内部的证据。P波(纵波)是纵波,可以在固体和液体中传播。S波(横波)是

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