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Year 8 Edexcel Maths: Interdisciplinary Problem-Solving Practice | 跨学科综合题型训练

2026-07-17 07:27 · 本文部分内容由AI辅助创作

📚 Year 8 Edexcel Maths: Interdisciplinary Problem-Solving Practice | 跨学科综合题型训练

In Year 8 Edexcel Maths, many exam questions are set in real-life contexts that link to other subjects like science, geography, business and design. These interdisciplinary problems test your ability to transfer your mathematical skills across different areas. This article will guide you through typical question types and strategies, with paired English and Chinese explanations to support both international and bilingual learners.

在八年级爱德思数学中,许多考题设定在现实情境中,与科学、地理、商业和设计等其他学科相关联。这些跨学科问题考查你将数学技能迁移到不同领域的能力。本文将带你了解典型的题型和策略,并配有中英文双语讲解,为国际学生和双语学习者提供支持。


1. Understanding Interdisciplinary Problems | 理解跨学科问题

Interdisciplinary questions often contain extra information from another subject, but the core task always asks you to perform a mathematical operation. Your first step should be to read the question carefully, underline the numerical facts and identify exactly what you are being asked to find. Check if any units need converting and decide which operation or formula to use.

跨学科问题通常包含来自其他学科的额外信息,但核心任务总是要求你进行数学运算。你的第一步应该是仔细阅读问题,在数字事实下划线,并明确题目要求你求的是什么。检查是否需要转换单位,并决定使用哪种运算或公式。

Always keep your working neat and label your answer with the correct units. Interdisciplinary questions are an excellent way to see how maths connects to the world around you.

始终保持解题步骤整洁,并用正确的单位标注答案。跨学科问题是让你看到数学如何与周围世界连接的绝佳方式。


2. Speed, Distance and Time (Science) | 速度、距离与时间(科学)

In physics and everyday travel, the relationship between speed, distance and time is fundamental. Remember the formula triangle or the equation:

在物理学和日常出行中,速度、距离和时间之间的关系是基础。请记住公式三角形或等式:

Distance = Speed × Time

距离 = 速度 × 时间

Example: A cyclist travels at a constant speed of 14 km/h for 2 hours and 30 minutes. Calculate the distance covered.

例题:一名自行车手以14公里/小时的恒定速度行驶了2小时30分钟。计算所覆盖的距离。

0.5 hours, so total time = 2.5 hours. Then apply the formula: Distance = 14 × 2.5 = 35 km.

首先,将时间转换为小时:30分钟 = 30 ÷ 60 = 0.5小时,因此总时间 = 2.5小时。然后套用公式:距离 = 14 × 2.5 = 35公里。

Always check that the units of speed and time match — if speed is in km/h, time must be in hours.

始终检查速度和时间单位是否匹配——如果速度是公里/小时,时间必须是小时。


3. Scale Drawings and Maps (Geography) | 比例尺绘图与地图(地理)

Maps use a scale to represent real distances. A scale such as 1 : 25000 means that 1 cm on the map represents 25000 cm in real life. To find the actual distance, multiply the map distance by the scale factor and then convert to more sensible units like metres or kilometres.

地图使用比例尺来表示实际距离。例如1:25000的比例尺意味着地图上1厘米代表实际中的25000厘米。要求实际距离,只需将地图距离乘以比例因子,然后转换为更合适的单位,如米或公里。

Example: On a map with scale 1 : 50000, two towns are 8 cm apart. What is the real distance in kilometres?

例题:在一张比例尺为1:50000的地图上,两个城镇相距8厘米。实际距离是多少公里?

8 × 50000 = 400000 cm. Convert to km: 400000 ÷ 100000 = 4 km. So the towns are 4 km apart.

实际距离(厘米)= 8 × 50000 = 400000厘米。转换为公里:400000 ÷ 100000 = 4公里。因此两镇相距4公里。


4. Data Handling in Experiments (Science) | 实验中的数据处理(科学)

When conducting experiments, you often collect measurements and need to calculate averages or draw graphs. For example, a student measured the growth of a plant over 15 days. The heights recorded were: Day 0: 2 cm, Day 5: 4 cm, Day 10: 7 cm, Day 15: 13 cm. The mean growth per day can be found by dividing the total growth by the number of days.

进行实验时,你经常收集测量数据,并需要计算平均值或绘制图表。例如,一名学生测量了植物在15天内的生长情况。记录的高度为:第0天:2厘米,第5天:4厘米,第10天:7厘米,第15天:13厘米。可以通过总生长量除以天数来求出每日平均生长量。

.73 cm/day. You might also be asked to plot a line graph or identify the day when growth was fastest. Always read data carefully from tables and graphs.

总生长量 = 13 - 2 = 11厘米。天数 = 15。平均每日生长量 = 11 ÷ 15 ≈ 0.73厘米/天。你可能会被要求绘制折线图,或者找出生长最快的是哪一天。务必仔细从表格和图表中读取数据。


5. Profit and Loss (Business Studies / Economics) | 利润与亏损(商业/经济)

Understanding profit and loss is a key financial maths skill. Profit is the difference between the selling price and the cost price. The percentage profit is always based on the cost price.

理解利润和亏损是一项关键的金融数学技能。利润是销售价格与成本价格之间的差额。利润率始终基于成本价格计算。

Example: A shop buys a jacket for £40 and sells it for £52. Calculate the profit and the percentage profit.

例题:一家商店以40英镑购进一件夹克,并以52英镑售出。计算利润和利润率。

Profit = £52 - £40 = £12. Percentage profit = (Profit ÷ Cost price) × 100 = (12 ÷ 40) × 100 = 30%. So the shop makes a 30% profit on the jacket.

利润 = 52 - 40 = 12英镑。利润率 = (利润 ÷ 成本价) × 100 = (12 ÷ 40) × 100 = 30%。因此该商店在这件夹克上获得30%的利润。

Always check what the question asks for — sometimes it requires the selling price when a target profit percentage is given.

始终检查题目要求——有时题目会给出目标利润率,让你求售价。


6. Area and Perimeter in Design (Art & Design Technology) | 设计中的面积与周长(艺术与设计技术)

Designing a garden, a room or a piece of furniture often involves calculating areas and perimeters of composite shapes. You may need to subtract the area of one shape from another.

设计花园、房间或家具时,通常需要计算复合图形的面积和周长。你可能需要从一个形状的面积中减去另一个形状的面积。

Example: A rectangular lawn measures 15 m by 10 m. A square flower bed of side 3 m is placed in the middle. Find the area of grass that remains.

例题:一块矩形草坪尺寸为15米 × 10米。中间放置一个边长为3米的正方形花坛。求剩余草坪的面积。

= 3 × 3 = 9 m². Remaining grass area = 150 - 9 = 141 m². Remember to include the unit m².

草坪面积 = 15 × 10 = 150 m²。花坛面积 = 3 × 3 = 9 m²。剩余草坪面积 = 150 - 9 = 141 m²。记得带上单位m²。


7. Ratio and Proportion in Recipes (Food Technology) | 食谱中的比与比例(食品技术)

Scaling recipes up or down is a direct application of ratio and proportion. The quantities of ingredients must be multiplied or divided by the same factor to keep the taste and texture correct.

按比例增减食谱配方是比和比例的直接应用。配料的数量必须乘以或除以相同的倍数,以保持味道和质感正确。

Example: A biscuit recipe uses 250 g of flour to make 20 biscuits. How much flour is needed to make 50 biscuits?

例题:一份饼干食谱使用250克面粉制作20块饼干。制作50块饼干需要多少克面粉?

rnatively, use the multiplier 50/20 = 2.5, so 250 × 2.5 = 625 g. Both methods are correct.

首先求出每块饼干所需面粉:250 ÷ 20 = 12.5克。然后相乘:12.5 × 50 = 625克。或者使用倍数50/20=2.5,因此250 × 2.5 = 625克。两种方法都正确。


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8. Interpreting Graphs Across Subjects | 跨学科图表解读

Graphs appear in almost every subject, from science to geography to business. You need to be able to read bar charts, line graphs and pie charts, and extract information to answer questions.

图表几乎出现在每一门学科中,从科学到地理再到商业。你需要能够阅读条形图、折线图和饼状图,并提取信息来回答问题。

The table below shows the number of students in two Year 8 classes who achieved marks in different ranges on a science test.

下表显示两个八年级班级在科学测试中获得不同分数段的学生人数。

Marks rangeClass 8A frequencyClass 8B frequency
0-2021
21-4054
41-60810
61-80107
81-10058

Question: Which class had more students scoring between 61 and 80 marks?

问题:哪个班级在61至80分数段的学生更多?

Class 8A had 10 students, while Class 8B had 7. So Class 8A had more students in that range. You can also be asked to calculate the total number of students in a class or the percentage achieving a certain grade. Always refer to the correct row or column.

8A班有10人,而8B班有7人。因此8A班在该分数段的学生更多。你也可能被要求计算一个班级的总人数,或者达到某个等级的学生所占的百分比。始终参照正确的行或列。


9. Currency Conversions (Geography / Economics) | 货币换算(地理/经济)

When travelling or comparing prices internationally, you need to convert between currencies using a given exchange rate. To convert from the base currency, multiply; to convert back, divide.

在旅行或进行国际价格比较时,你需要使用给定的汇率进行货币换算。从基础货币换算时乘以汇率;换算回基础货币时除以汇率。

Example: The exchange rate is £1 = $1.30. A student exchanges £150 for a trip. How many dollars does she receive?

例题:汇率为£1 = $1.30。一名学生为旅行兑换了150英镑。她收到多少美元?

Amount in dollars = 150 × 1.30 = $195. If she later converts $260 back to pounds, the calculation would be 260 ÷ 1.30 = £ rate given in the question, and round money answers to two decimal places where necessary.

美元金额 = 150 × 1.30 = 195美元。如果她后来将260美元兑换回英镑,计算为260 ÷ 1.30 = 200英镑。始终使用题目给出的汇率,并在必要时将货币答案四舍五入到两位小数。


10. Probability in Games and Science | 游戏与科学中的概率

and risk assessment. The probability of an event = number of favourable outcomes / total number of possible outcomes.

概率衡量一个事件发生的可能性,用分数、小数或百分比表示。它用于概率游戏、遗传学和风险评估。事件的概率 = 有利结果的数量 / 可能结果的总数。

Example: A bag contains 6 red counters, 4 blue counters and 2 green counters. One counter is taken at random. What is the probability it is not blue?

例题:一个袋子里有6个红色计数器、4个蓝色计数器和2个绿色计数器。随机取出一个计数器。它不是蓝色的概率是多少?

mately 0.667. The probability that it is blue is 4/12 = 1/3, and these two probabilities add to 1, as expected.

总计数器数 = 6 + 4 + 2 = 12。非蓝色计数器 = 6红 + 2绿 = 8。概率 = 8/12 = 2/3。你也可以说概率是2/3或约等于0.667。取到蓝色的概率是4/12 = 1/3,这两个概率之和为1,符合预期。


11. Averages in Sports (Physical Education) | 体育中的平均数(体育)

Sports statistics often use the mean, median and mode to analyse performance. The mean is the sum of values divided by the number of values. The median is the middle value when data is ordered.

体育统计中经常使用平均数、中位数和众数来分析表现。平均数是一组数值的总和除以数值的个数。中位数是将数据排序后位于中间的值。

Example: A basketball player scored the following points in five matches: 14, 22, 18, 14, 12. Find the mean and median scores.

例题:一名篮球运动员在五场比赛中的得分如下:14, 22, 18, 14, 12。求平均得分和中位数。

points. To find the median, order the data: 12, 14, 14, 18, 22. The middle value is 14, so the median is 14 points.

平均数 = (14 + 22 + 18 + 14 + 12) ÷ 5 = 80 ÷ 5 = 16分。求中位数时,将数据排序:12, 14, 14, 18, 22。中间的值是14,因此中位数是14分。

Notice the mode is also 14, as it appears most often. Understanding which average to use depends on the context — the mean can be affected by very high or low scores, while the median gives a better picture of typical performance in some cases.

注意众数也是14,因为它出现次数最多。理解该用哪种平均数取决于情境——平均数可能会受到极高或极低分数的影响,而中位数在某些情况下更能反映典型表现。


12. Revision Tips for Interdisciplinary Problems | 跨学科问题的复习技巧

To succeed with interdisciplinary maths questions, practise extracting only the numerical information you need. Build confidence by working through mixed problems from past papers or revision guides. Here are some key strategies:

要成功解决跨学科数学问题,需要练习只提取你需要的数字信息。通过做真题或复习指南中的混合题来建立信心。以下是一些关键策略:

With regular practice, you will find that interdisciplinary questions become an enjoyable puzzle where your maths skills unlock answers in many different worlds.

通过经常练习,你会发现跨学科问题变成了一种有趣的谜题,你的数学技能可以在许多不同的世界里解锁答案。


Published by TutorHao | Mathematics Revision Series | aleveler.com

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