📚 Year 7 WJEC Chemistry: Interdisciplinary Integrated Question Practice | Year 7 WJEC 化学：跨学科综合题型训练
Interdisciplinary questions in Year 7 WJEC Chemistry blend chemical concepts with ideas from maths, physics, biology, geography and even history. These questions test your ability to connect knowledge across subjects. This article provides training through worked examples, key tips and practice to help you master them.
跨学科综合题将 Year 7 WJEC 化学概念与数学、物理、生物、地理甚至历史的知识融合在一起。这些题目考察你联系不同学科知识的能力。本文通过实例解析、关键技巧和练习提供训练，帮助你攻克这类题型。
1. What Are Interdisciplinary Integrated Questions? | 什么是跨学科综合题？
In your WJEC Chemistry course, some questions will not be purely about chemistry. Instead, they will ask you to bring in skills from other subjects – like drawing a graph in maths, explaining a temperature curve using physics, or linking acid rain to rock erosion in geography. These questions show how science works in the real world, where subjects overlap.
在 WJEC 化学课程中，有些题目并不纯粹考察化学。它们要求你运用其他学科的技能——比如用数学绘制图表、用物理学解释温度曲线，或者将酸雨与地理中的岩石侵蚀联系起来。这些问题展示了现实世界中科学如何运作，学科之间相互交叉。
2. Chemistry and Mathematics: Ratios, Graphs and Units | 化学与数学：比例、图表与单位
Maths appears in chemistry whenever you handle data. You might need to calculate concentrations, convert units, or interpret line graphs. Being confident with ratios and unit changes (e.g. cm³ to dm³) is essential.
数学在处理数据时总会出现在化学中。你可能需要计算浓度、转换单位或解读折线图。熟练掌握比例和单位转换（例如 cm³ 到 dm³）是必不可少的。
Example: water. Calculate the concentration of the solution in g/dm³. (Remember: 1 dm³ = 1000 cm³)
例题：Jenny 将 5 g 食盐溶解在 100 cm³ 水中。计算溶液浓度，单位为 g/dm³。（提示：1 dm³ = 1000 cm³）
g/dm³. This type of calculation blends arithmetic with the chemical idea of concentration.
解答：首先进行体积转换：100 cm³ = 0.1 dm³。浓度 = 质量 ÷ 体积 = 5 g ÷ 0.1 dm³ = 50 g/dm³。这类计算将算术与化学中的浓度概念结合在一起。
You might also be asked to plot a cooling curve or a solubility graph. Practise reading axes, identifying trends and using data to predict unknown values.
你还可能被要求绘制降温曲线或溶解度图。练习读取坐标轴、识别变化趋势，并利用数据预测未知数值。
3. Chemistry and Physics: States of Matter and Energy Transfer | 化学与物理：物质状态与能量传递
The particle model explains changes of state, but heating and cooling curves come from physics. When a solid melts, the temperature stays constant even though energy is still being supplied. This energy is used to break forces between particles, not to speed them up.
粒子模型解释了状态变化，而加热和冷却曲线则来自物理学。当固体熔化时，尽管仍在供给能量，温度却保持不变。这部分能量被用来破坏粒子间的吸引力，而不是使粒子加速。
Example: A student heats a beaker of crushed ice and records the temperature every minute. The graph shows a flat plateau at 0 °C. Explain the plateau using ideas from chemistry and physics.
例题：一名学生加热一杯碎冰并每分钟记录温度。图像显示在 0 °C 时出现一个平台。请运用化学和物理知识解释这个平台。
Answer: At 0 °C, the ice is melting. The thermal energy supplied goes into overcoming the attractive forces holding water particles in a fixed solid structure, rather than raising the kinetic energy of the particles. So the temperature does not rise until all the ice has turned to liquid. This links the chemical concept of particle attraction with the physical concept of latent heat.
答案：在 0 °C 时，冰正在熔化。供给的热能用于克服使水粒子保持在固定固体结构中的吸引力，而不是提高粒子的动能。因此，在所有冰变成液态之前，温度不会升高。这就将化学中的粒子吸引力概念与物理中的潜热概念联系了起来。
4. Chemistry and Biology: Carbon Dioxide in Living Organisms | 化学与生物：生命体中的二氧化碳
Carbon dioxide (CO₂) appears in both chemistry and biology. The classic test for CO₂ is bubbling it through limewater, which turns milky. Living things produce CO₂ during respiration and take it in during photosynthesis.
二氧化碳（CO₂）在化学和生物中都会出现。检验二氧化碳的经典方法是将其通入石灰水中，石灰水会变浑浊。生物在呼吸作用中产生 CO₂，在光合作用中吸收 CO₂。
Example: A snail is placed in a sealed container with a sensor that measures CO₂ level. The graph shows CO₂ rising steadily. Later, a plant is added and the container is placed in light; the CO₂ level drops. Use both biology and chemistry to interpret the results.
例题：将一只蜗牛放入一个带有 CO₂ 传感器的密封容器中。图表显示 CO₂ 稳步上升。随后放入一株植物并将容器置于光照下，CO₂ 水平下降。请运用生物和化学知识解释这一结果。
Join-up answer: The snail respires, releasing CO₂ as a waste product (biology). The CO₂ can be detected because it reacts with substances like limewater to form a white precipitate (chemistry). When the plant is added and given light, it photosynthesises, taking in CO₂ and releasing O₂, so the CO₂ level falls. The question links respiration, photosynthesis and the chemical identity of a gas.
综合解答：蜗牛进行呼吸作用，释放出废物 CO₂（生物学）。CO₂ 能够被检测到是因为它会与石灰水之类物质反应，生成白色沉淀（化学）。加入植物并给予光照后，植物进行光合作用，吸收 CO₂ 并释放 O₂，因此 CO₂ 水平下降。该题目将呼吸作用、光合作用与一种气体的化学特性联系在了一起。
5. Chemistry and Geography: Acid Rain and Rock Weathering | 化学与地理：酸雨与岩石风化
Acid rain forms when acidic gases (e.g. sulfur dioxide, nitrogen oxides) dissolve in rainwater. This links chemistry to geography because acid rain speeds up the weathering of rocks, especially limestone and marble (both contain calcium carbonate).
当酸性气体（如二氧化硫、氮氧化物）溶解在雨水中时，就形成了酸雨。这就将化学与地理联系了起来，因为酸雨会加速岩石的风化，尤其是石灰岩和大理石（两者都含有碳酸钙）。
Example: A statue made of marble (calcium carbonate) has become eroded over many years in a city with high air pollution. Write a word equation for the reaction between calcium carbonate and sulfuric acid from acid rain. Suggest why the damage is worse in a busy city than in the countryside.
例题：一座用大理石（碳酸钙）制成的雕像在一个空气污染严重的城市中经过多年后受到了侵蚀。写出碳酸钙与酸雨中的硫酸反应的文字方程式。并提出为什么在繁忙的城市中损坏比在乡村更为严重。
on dioxide. The busy city has more vehicles and factories releasing acidic gases, so rain becomes more acidic. Greater acidity means a faster reaction with the marble, causing more visible erosion. This links geographical location to chemical reaction rate.
解答：碳酸钙 + 硫酸 → 硫酸钙 + 水 + 二氧化碳。繁忙的城市有更多车辆和工厂排放酸性气体，因此雨水酸性更强。酸性更强意味着与大理石的反应更快，造成更明显的侵蚀。这就将地理位置与化学反应速率联系在了一起。
6. Chemistry and Environmental Science: Purifying Water | 化学与环境科学：水的净化
Providing clean water involves several separation techniques from chemistry – filtration to remove insoluble solids and distillation or evaporation to obtain pure water from a solution. Environmental science focuses on why this matters for health and ecosystems.
提供清洁水涉及多种化学分离技术——过滤去除不溶性固体，蒸馏或蒸发从溶液中获取纯水。环境科学则关注这为什么对健康和生态系统至关重要。
Example: River water contains mud, dissolved salts and bacteria. Describe a sequence of purification steps you could use in the laboratory to obtain pure water. Then explain why removing dissolved salts is important for drinking water quality.
例题：河水中含有泥浆、溶解的盐和细菌。描述你在实验室中为获得纯水而采用的一系列净化步骤。然后解释为什么去除溶解盐对饮用水质量很重要。
Answer: First, filter the water to remove mud and other insoluble particles. Then, use distillation: heat the filtered water so it evaporates, and condense the vapour to collect pure water. The dissolved salts are left behind. Dissolved salts give water an unpleasant taste and, in high concentrations, can be harmful to health. This question blends chemistry (separation methods) with environmental health awareness.
解答：首先过滤水，去除泥浆和其他不溶性颗粒。然后使用蒸馏：加热滤过的水使其蒸发，再冷凝水蒸气以收集纯水。溶解的盐会留在原容器中。溶解的盐会使水有令人不快的味道，高浓度时还可能对健康有害。这道题将化学（分离方法）与环境健康意识结合在了一起。
7. Chemistry and History: Extracting Metals from Ores | 化学与历史：从矿石中提取金属
Historical periods like the Bronze Age depended on the ability to extract metals from their ores using charcoal (a form of carbon). In Year 7, you learn about the reaction of metal oxides with carbon as a reduction process.
像青铜时代这样的历史时期依赖于使用木炭（一种碳的形式）从矿石中提取金属的能力。在 Year 7，你会学到金属氧化物与碳的反应是一种还原过程。
Example: pper oxide reacts with carbon: copper oxide + carbon → copper + carbon dioxide. Suggest why this discovery was so important for the development of early civilisations, combining history and chemistry.
例题：古人将孔雀石（碳酸铜）与木炭一起加热来提取铜。孔雀石先分解生成氧化铜，然后氧化铜与碳反应：氧化铜 + 碳 → 铜 + 二氧化碳。结合历史和化学，说明这一发现为何对早期文明的发展如此重要。
Answer: Chemically, carbon removes oxygen from copper oxide, leaving pure copper metal. Historically, the ability to produce copper and, later, bronze (copper + tin) allowed people to make stronger tools, weapons and ornaments, leading to advances in farming, warfare and trade. This question makes you see a chemical reaction in a human context.
解答：从化学上讲，碳从氧化铜中去除了氧，留下纯铜金属。从历史上看，能够生产铜以及后来生产青铜（铜 + 锡），使人们能够制造更坚固的工具、武器和装饰品，从而推动了农业、战争和贸易的进步。这道题让你在人类发展背景下看待一个化学反应。
8. Chemistry and Design Technology: Choosing Materials | 化学与设计技术：选择材料
When designing a product, you must choose materials by considering their properties – a task that joins chemistry with design technology. Properties like transparency, density, heat resistance and reactivity with water all come from a material's chemical structure.
设计产品时，你必须根据材料的性质进行选择——这项任务将化学与设计技术结合在了一起。透明性、密度、耐热性以及与水的反应性等性质都来自材料的化学结构。
Example: Compare the properties of polythene (a plastic) and glass for making a water bottle. Use the table below to help you decide which is more suitable.
例题：比较聚乙烯（一种塑料）和玻璃在制作水瓶时的性质。利用下表帮你决定哪种材料更合适。
| Property | Polythene | Glass |
|---|---|---|
| Density | Low (lightweight) | High (heavy) |
| Transparency | Can be translucent | Very transparent |
| Resistance to shattering | Good (flexible) | Poor (brittle) |
| Reactivity with water | Unreactive | Unreactive |
Answer: Polythene is lightweight and shatter-resistant, making the bottle safer and easier to carry. Glass is heavier and breaks easily, which is a safety risk. Although glass is clearer, the practical advantages of polythene usually make it the preferred material for everyday water bottles. This decision uses chemical properties and design criteria together. Published by TutorHao | Year 7 Chemistry Revision Series | aleveler.com
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