📚 Year 7 CIE Physics: Cross-Curricular Integrated Question Practice | Year 7 CIE 物理：跨学科综合题型训练
Physics in Year 7 is not just about learning scientific facts; it is also about connecting ideas across different subjects. In the CIE curriculum, you will encounter problems that blend physics with mathematics, geography, biology, and even music. This article presents a series of integrated question types to help you build confidence in solving cross-curricular challenges.
7年级物理不仅仅是学习科学事实；它还需要将不同学科的知识联系起来。在CIE课程中，你会遇到将物理与数学、地理、生物甚至音乐相融合的问题。本文通过一系列综合题型，帮助你建立解决跨学科挑战的信心。
1. Measurement and Unit Conversion with Maths | 测量与单位换算中的数学
be comfortable with prefixes such as kilo (×10³), centi (×10⁻²), and milli (×10⁻³). For example, a ruler measured in centimetres may need to be expressed in metres for speed calculations.
许多7年级物理题目需要你进行测量和单位换算，将数学运算与科学量结合在一起。你需要熟练掌握如千（×10³）、厘（×10⁻²）和毫（×10⁻³）等词头。例如，用厘米测量的尺子可能需要转换为米来进行速度计算。
A typical cross-curricular question: A snail moves 12 cm in 1 minute. Calculate its speed in m/s.
一个典型的跨学科问题：一只蜗牛在1分钟内爬行了12 cm，计算它的速度，单位用 m/s。
0.12 ÷ 60 = 0.002 m/s. Notice how you must use division and decimal place value correctly.
解法：将厘米转换为米：12 cm = 0.12 m。将时间转换为秒：1 min = 60 s。然后速度 = 距离 ÷ 时间 = 0.12 ÷ 60 = 0.002 m/s。请注意，你必须正确使用除法和小数位值。
2. Speed and Distance-Time Graphs | 速度与距离—时间图
Interpreting distance–time graphs links physics with mathematical graph-reading skills. You may be asked to find the speed from the gradient of a straight-line graph or to describe a journey where an object stops, returns, or accelerates.
解读距离—时间图将物理与数学的图表阅读技能联系起来。你可能会被要求从直线图的斜率求速度，或描述某物体停止、返回或加速的行程。
For instance, a graph shows a bicycle travelling 100 m in 20 s, then resting for 10 s, and finally returning 60 m in 15 s. Calculate the speed for each section.
例如，一张图显示自行车在20 s内行驶100 m，然后休息10 s，最后在15 s内返回60 m。计算每一段的速度。
ing and interpreting such graphs helps you visualise motion, a skill shared with geography when reading travel maps.
第一段：速度 = 100 m ÷ 20 s = 5 m/s。休息段：速度 = 0 m/s。返回段：速度 = 60 m ÷ 15 s = 4 m/s。绘制和解读这种图形有助于将运动可视化，这也是阅读地理旅行地图时会用到的技能。
3. Density and Materials Science | 密度与材料科学
Density is a key concept that connects physics with chemistry and material engineering. You may need to identify unknown materials by calculating density from mass and volume measurements, then comparing with known values from a data table.
密度是一个将物理与化学及材料工程联系起来的关键概念。你可能需要通过测量质量和体积来计算密度，再与已知数值表比较，以识别未知材料。
Example question: A block of metal has a mass of 540 g and a volume of 200 cm³. Is it likely to be aluminium (density 2.7 g/cm³)?
例题：一块金属的质量为540 g，体积为200 cm³。它可能是铝（密度2.7 g/cm³）吗？
200 cm³ = 2.7 g/cm³. Yes, it matches aluminium. Another cross-curricular link: Archimedes' principle uses density to explain why some objects float, relating to ship design and biology (fish swim bladders).
密度 ρ = 质量 ÷ 体积 = 540 g ÷ 200 cm³ = 2.7 g/cm³。是的，与铝匹配。另一个跨学科联系：阿基米德原理利用密度解释为何一些物体会漂浮，与船舶设计和生物学（鱼鳔）相关。
4. Energy Transfers and Food Chains | 能量转移与食物链
Energy transfers appear in both physics and biology. CIE Year 7 questions often ask you to trace how chemical energy in food becomes kinetic or thermal energy in living organisms, or how energy is lost at each trophic level.
能量转移出现在物理和生物学中。CIE 7年级题目常要求你追踪食物中的化学能如何转化为生物体的动能或热能，或者能量在每个营养级如何损耗。
Consider a simple food chain: grass → rabbit → fox. The Sun' ough photosynthesis and stored as chemical energy. When a rabbit eats grass, only about 10% of that energy is transferred to the rabbit's body; the rest is lost as heat and waste.
考虑一个简单的食物链：草 → 兔 → 狐狸。太阳的光能通过光合作用被草捕获并储存为化学能。当兔子吃草时，只有约10%的能量转移到兔子体内；其余的以热和废物的形式损耗。
y efficiency: if grass contains 1000 J of energy usable by the rabbit, how much reaches the rabbit? 10% 0 J. This links percentage calculations with the physics principle of energy conservation.
你可能会被要求计算能量效率：如果草含有可供兔子使用的1000 J能量，有多少到达兔子？1000 J的10% = 100 J。这将百分比计算与物理学的能量守恒原理联系起来。
5. Heat Transfer and Weather Systems | 热传递与天气系统
Conduction, convection, and radiation are essential in understanding weather and climate, linking physics with geography. For example, sea breezes form because land heats up and cools down faster than water, creating convection currents.
传导、对流和辐射对于理解天气和气候至关重要，将物理与地理联系起来。例如，海陆风的形成是因为陆地比水升温和降温更快，产生了对流。
A typical question: In a coastal area during the day, warm air above the land rises, and cooler air from the sea moves in to replace it. Name the heat transfer process involved and explain why this happens.
一个典型问题：白天在沿海地区，陆地上方的暖空气上升，海上的冷空气移来补充。说出涉及的热传递过程并解释原因。
Answer: The process is convection. The land absorbs solar radiation more quickly than the sea, warming the air above it. This warm air expands, becomes less dense, and rises, while denser cool air flows in from the sea, creating a sea breeze. Such questions require you to apply radiation and convection concepts to real-world geography.
答案：该过程是对流。陆地比海洋更快地吸收太阳辐射，加热其上方的空气。暖空气膨胀，密度变小而上升，同时密度较大的冷空气从海上流入，形成海风。这类问题要求你将辐射和对流概念应用于真实的地理场景。
6. Sound Propagation and Musical Instruments | 声音的传播与乐器
Sound is a topic where physics meets music. You may need to explain how changing the length of a guitar string or the air column in a flute affects pitch, linking wave frequency to musical notes.
声音是物理与音乐交汇的主题。你可能需要解释改变吉他弦的长度或长笛中空气柱的长度如何影响音高，将波的频率与音符联系起来。
Question: A guitarist presses a string at different frets to shorten its vibrating length. How does this change the pitch heard?
问题：吉他手在不同品位按弦以缩短振动的弦长。这如何改变听到的音高？
Shorter strings vibrate at a higher frequency, producing a higher pitch. This is because the frequency of a stretched string is inversely proportional to its length. The same principle applies in wind instruments: a shorter air column gives a higher note. This integrates the physics of waves with musical scales and even mathematics (ratios of lengths for notes).
较短的弦以更高的频率振动，产生更高的音高。这是因为拉伸弦的频率与其长度成反比。同样的原理也适用于管乐器：较短的气柱发出较高的音。这将波的物理学与音乐音阶甚至数学（音符长度比）结合在一起。
7. Light Reflection and the Human Eye | 光的反射与人类眼睛
The study of light reflection links physics to biology through the human eye. You need to understand how light enters the eye, is refracted by the lens, and forms an image on the retina – a real application of ray diagrams.
对光反射的研究通过人类眼睛将物理与生物学联系起来。你需要理解光如何进入眼睛，被晶状体折射，并在视网膜上形成图像——这是光线图的真实应用。
Question: Draw a ray diagram to show how a convex lens focuses light from a distant object onto the retina. Label the principal focus.
问题：画一个光线图，展示凸透镜如何将远处物体的光聚焦到视网膜上。标出主焦点。
In your diagram, parallel rays from a distant point enter the eye and are refracted by the convex lens so they converge on the retina. The focal length of the eye lens changes as ciliary muscles adjust its shape – a biological feedback system that applies physics. Problems may also ask how glasses correct short-sightedness, using diverging lenses.
在你的图中，来自远处点的平行光线进入眼睛，被凸透镜折射后会聚于视网膜。眼晶状体的焦距会随睫状肌调整形状而改变——这是一个应用物理学的生物反馈系统。问题也可能问及如何用发散透镜矫正近视。
8. Simple Circuits and Home Safety | 简单电路与家庭安全
Electric circuits in Year 7 physics often connect with everyday technology and safety. You may be asked to draw circuit diagrams using standard symbols, calculate current or voltage, and relate these to home wiring, fuses, and circuit breakers.
7年级物理中的电路常常与日常技术和安全相联系。你可能需要画出使用标准符号的电路图，计算电流或电压，并将这些与家庭布线、保险丝和断路器联系起来。
Question: A table lamp has a resistance of 500 Ω and is connected to a 230 V mains supply. Calculate the current flowing. Why is it important to use the correct fuse rating?
问题：一盏台灯的电阻为500 Ω，连接到230 V的市电。计算流过的电流。为什么使用合适额定值的保险丝很重要？
Using Ohm' 6 A. The fuse should be rated slightly above this, e.g., 1 A. If a fault causes a much higher current, the fuse melts and breaks the circuit, preventing overheating and fires. This merges physics calculations with safety engineering – a practical cross-curricular skill.
使用欧姆定律：电流 I = V ÷ R = 230 V ÷ 500 Ω = 0.46 A。保险丝的额定值应略高于此，例如1 A。如果故障导致电流过高，保险丝熔断并切断电路，防止过热和火灾。这融合了物理计算与安全工程——一种实用的跨学科技能。
9. Integrated Case Study: Solar-Powered Car | 综合案例研究：太阳能汽车
This extended scenario brings together many physics topics. A team designs a small solar-powered car using a solar panel, an electric motor, and lightweight wheels. The car races in a competition.
这个扩展情景汇聚了许多物理主题。一个团队设计了一辆小型太阳能汽车，使用太阳能电池板、电动马达和轻质车轮。这辆车参加比赛。
(a) The solar panel converts light energy from the Sun into electrical energy. Name the energy transfer from the Sun to the panel.
(a) 太阳能电池板将来自太阳的光能转化为电能。说出从太阳到电池板的能量转移。
trical energy to kinetic energy. What is the wasted energy form, and how can it be reduced? If the car travels 50 m in 10 s, calculate its average speed. Speed = 50 m ÷ 10 s = 5 m/s.
答案：能量通过辐射传递。(b) 马达将电能转化为动能。耗散的能量形式是什么？如何减少？耗散的能量主要是摩擦导致的热能。使用润滑剂和光滑的轴承可减少摩擦。(c) 如果汽车在10 s内行驶50 m，计算它的平均速度。速度 = 50 m ÷ 10 s = 5 m/s。
(d) Discuss how the mass of the car affects its acceleration. According to Newton's second law, a larger mass requires a greater force to achieve the same acceleration. Lightweight materials such as carbon fibre are preferred. This mini-project integrates energy, forces, motion, and material properties – a perfect cross-curricular challenge.
(d) 讨论汽车的质量如何影响其加速度。根据牛顿第二定律，更大的质量需要更大的力才能达到相同的加速度。碳纤维等轻质材料更受青睐。这个迷你项目整合了能量、力、运动和材料性质——一个完美的跨学科挑战。
10. Strategies for Tackling Cross-Curricular Questions | 应对跨学科问题的策略
To succeed in these integrated physics questions, always follow a clear approach:
要成功解答这些综合物理问题，始终遵循清晰的策略：
1. Read the question carefully and underline the key physics concepts involved (e.g. energy, density, speed). 2. Identify the linked subject – is it maths (calculation), geography (maps, climate), or biology (body systems)? 3. Extract the numerical data and check units; convert if necessary. 4. Apply the relevant physics formula and solve step by step. 5. Write a clear answer, using correct units and scientific vocabulary.
1. 仔细阅读题目，在涉及的物理关键概念（如能量、密度、速度）下划线。2. 确定联系到的学科——是数学（计算）、地理（地图、气候）还是生物（身体系统）？3. 提取数值数据并检查单位；必要时进行换算。4. 应用相关的物理公式，逐步求解。5. 写出清晰的答案，使用正确的单位和科学词汇。
Cross-curricular problems are not harder; they simply reward you for connecting what you already know from different lessons. Regular practice with these types of questions will sharpen your analytical thinking and prepare you for future IGCSE sciences.
跨学科问题并不更难；它们只是在奖励你将不同课堂上已学知识联系起来的能力。经常练习这类题目将提升你的分析思维能力，为未来的IGCSE科学学习做好准备。
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