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Oxford AQA International AS Further Mathematics (9665) Pure Topic Test – Key Concepts | 牛津AQA国际AS进阶数学(9665)纯数主题测试知识点精讲

2026-07-14 20:38 · 本文部分内容由AI辅助创作

📚 Oxford AQA International AS Further Mathematics (9665) Pure Topic Test – Key Concepts | 牛津AQA国际AS进阶数学(9665)纯数主题测试知识点精讲

This article provides a concise yet thorough revision of the core pure mathematics topics covered in the Oxford AQA International AS Level Further Mathematics (9665) specification. Mastering these concepts will boost your performance in topic tests and build a solid foundation for the full A-level. We focus on complex numbers, matrices, roots of polynomials, series, proof by induction, and vectors.

本文为牛津AQA国际AS进阶数学(9665)大纲中的纯数核心主题提供简明而全面的复习。掌握这些概念将提升你在主题测试中的表现,并为完整的A-level打下坚实基础。我们将重点讲解复数、矩阵、多项式根、级数、数学归纳法和向量。


1. Complex Numbers – Introduction and Operations | 复数 – 介绍与运算

A complex number is of the form z = a + bi, where a and b are real numbers and i is the imaginary unit with i² = –1.

复数的标准形式为 z = a + bi,其中 a 和 b 为实数,i 为虚数单位且满足 i² = –1。

The real part is Re(z) = a and the imaginary part is Im(z) = b. Two complex numbers are equal if and only if their real parts are equal and their imaginary parts are equal.

实部为 Re(z) = a,虚部为 Im(z) = b。两个复数相等当且仅当它们的实部和虚部分别相等。

Addition and subtraction are performed component-wise: (a + bi) + (c + di) = (a + c) + (b + d)i. Multiplication uses distributive law and i² = –1: (a + bi)(c + di) = (ac – bd) + (ad + bc)i.

加法和减法按分量进行:(a + bi) + (c + di) = (a + c) + (b + d)i。乘法利用分配律和 i² = –1:(a + bi)(c + di) = (ac – bd) + (ad + bc)i。

The complex conjugate of z = a + bi is z* = a – bi. The product z z* = a² + b² is a real number, which is the square of the modulus |z| = √a² + b². Division is performed by multiplying numerator and denominator by the conjugate of the denominator.

共轭复数 z* = a – bi。乘积 z z* = a² + b² 是一个实数,即模的平方:|z| = √a² + b²。除法通过分子分母同乘分母的共轭来实现。

For z = a + bi, |z| = √a² + b², z⁻¹ = z* / |z|² (z ≠ 0)

When solving equations with complex coefficients, treat i as a constant and equate real and imaginary parts to find unknowns.

求解含复数系数的方程时,将 i 视为常数,令实部与虚部分别相等以求出未知数。


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2. Argand Diagrams and Modulus-Argument Form | 阿甘图与模-辐角形式

Complex numbers can be represented as points on an Argand diagram with the x-axis as the real part and y-axis as the imaginary part. The modulus |z| gives the distance from the origin and the argument arg(z) is the angle measured anticlockwise from the positive real axis.

复数可以表示为阿甘图上的点,横轴为实部,纵轴为虚部。模 |z| 表示从原点到该点的距离,辐角 arg(z) 是从正实轴逆时针量起的角度。

The modulus-argument form (polar form) is z = r(cos θ + i sin θ), often abbreviated as r cis θ, where r = |z| and θ = arg(z).

模-辐角形式(极形式)为 z = r(cos θ + i sin θ),常简写为 r cis θ,其中 r = |z|,θ = arg(z)。

z = r (cos θ + i sin θ) = r cis θ

Multiplication and division in polar form become simple: z₁z₂ = r₁r₂ cis(θ₁ + θ₂) and z₁/z₂ = (r₁/r₂) cis(θ₁ – θ₂). This reveals the geometric effect: multiplying by a complex number scales by its modulus and rotates by its argument.

极形式下的乘法和除法变得简单:z₁z₂ = r₁r₂ cis(θ₁ + θ₂),z₁/z₂ = (r₁/r₂) cis(θ₁ – θ₂)。这揭示了其几何意义:乘以一个复数相当于按模缩放并按辐角旋转。

Loci in the Argand diagram, such as |z – a| = r (a circle) or |z – a| = |z – b| (perpendicular bisector), are frequently tested and should be interpreted geometrically.

阿甘图中的轨迹,如 |z – a| = r(圆)或 |z – a| = |z – b|(垂直平分线),是常见考点,应从几何角度加以理解。


3. Roots of Polynomial Equations | 多项式方程的根

For a quadratic equation ax² + bx + c = 0 with roots α and β, the relationships are α + β = –b/a and αβ = c/a.

对于二次方程 ax² + bx + c = 0 及其根 α 和 β,有关系式 α + β = –b/a 和 αβ = c/a。

For a cubic equation ax³ + bx² + cx + d = 0 with roots α, β, γ, the sums are α + β + γ = –b/a, αβ + βγ + γα = c/a, and αβγ = –d/a.

对于三次方程 ax³ + bx² + cx + d =

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