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A2 Physics: Electromagnetic Induction Exam Essentials | A2 物理:电磁感应 考点精讲

2026-07-14 17:56 · 本文部分内容由AI辅助创作

📚 A2 Physics: Electromagnetic Induction Exam Essentials | A2 物理:电磁感应 考点精讲

Electromagnetic induction is a cornerstone of A2 Physics, linking magnetic fields, motion, and electrical energy. It explains how a changing magnetic flux can drive a current in a conductor, and it underpins everything from massive power station generators to the tiny transformers in your phone charger. This revision guide walks you through the key concepts, essential equations, and common exam pitfalls, ensuring you can tackle both qualitative and quantitative problems with confidence.

电磁感应是 A2 物理的基石,它将磁场、运动和电能联系起来。它解释了变化的磁通量如何驱动导体中的电流,从巨大的发电站发电机到手机充电器中的微型变压器,都离不开这个原理。本复习指南将带你梳理核心概念、关键方程和常见考试陷阱,帮助你自信应对定性和定量问题。

1. Magnetic Flux and Flux Linkage | 磁通量与磁链

netic field of flux density B and a flat area A, the flux is given by Φ = BA cos θ, where θ is the angle between the field lines and the normal to the surface. The unit of magnetic flux is the weber (Wb). When a coil has N turns, the total flux linkage is NΦ.

磁通量 Φ 衡量穿过某一表面的磁感线条数。对于磁通密度为 B 的匀强磁场和平面面积 A,Φ = BA cos θ,其中 θ 是磁感线与表面法线之间的夹角。磁通量的单位是韦伯(Wb)。当线圈有 N 匝时,总磁链为 NΦ。

nd flux linkage is maximum. When the coil is parallel to the field, θ = 90°, flux is zero.

一个常见考试错误是混淆角度。当线圈垂直于磁场时,其法线与 B 平行,θ = 0°,cos 0° = 1,磁链最大。当线圈平行于磁场时,θ = 90°,磁链为零。


2. Faraday's Law of Electromagnetic Induction | 法拉第电磁感应定律

Faraday's law states that the magnitude of the induced emf ε in a circuit is equal to the rate of change of magnetic flux linkage through the circuit. Mathematically, for a coil of N turns:

ε = −N ΔΦ/Δt

The negative sign indicates the direction of the induced emf, which is given by Lenz's law. In exam questions, the minus sign is often omitted when calculating magnitude, but you should mention it when explaining direction.

法拉第定律指出,电路中感应电动势 ε 的大小等于穿过该电路的磁链变化率。对于 N 匝线圈,数学表达式为:

ε = −N ΔΦ/Δt

负号表示感应电动势的方向,这由楞次定律给出。在考题中,计算大小时常略去负号,但在解释方向时必须提及。

You must be able to determine the induced emf from a graph of Φ against t. The emf is the negative gradient of the flux-time graph. A steep slope means a large induced emf.

你必须能从 Φ-t 图确定感应电动势。电动势是磁通量-时间图线的负梯度。斜率越陡,感应电动势越大。


3. Lenz's Law and Energy Conservation | 楞次定律与能量守恒

Lenz's law states that the direction of the induced current is such that it opposes the change in magnetic flux that produced it. This opposition is a direct consequence of the conservation of energy. If the induced current aided the change, a small movement would produce more current, leading to a greater flux change, and so on, creating energy from nothing - which is impossible.

楞次定律指出,感应电流的方向总是阻碍引起感应电流的磁通量变化。这种阻碍是能量守恒定律的直接结果。如果感应电流助长变化,一个微小的运动就会产生更多电流,导致更大的磁通变化,如此下去就会无中生有地创造能量——这是不可能的。

In a typical scenario, when the north pole of a magnet approaches a coil, the coil becomes a north pole facing it to repel the magnet back. When the magnet is withdrawn, the coil becomes a south pole to attract it back. This opposing force shows that work must be done to move the magnet, transforming mechanical energy into electrical energy.

典型场景中,当磁铁 N 极靠近线圈,线圈面对磁铁的一端也变成 N 极以排斥磁铁。当磁铁抽出时,线圈变成 S 极以吸引磁铁。这种阻力表明移动磁铁必须做功,从而将机械能转化为电能。


4. Motional EMF and the Flux Cutting Rule | 动生电动势与切割磁感线规则

When a straight conductor of length l moves with velocity v perpendicular to a uniform magnetic field B, an emf is induced between its ends. This is often called motional emf, given by:

ε = B l v

ective component is v sin θ, so ε = B l v sin θ. This equation can be derived from Faraday's law by considering the area swept out per unit time, ΔA/Δt = l v.

当长度为 l 的直导体以速度 v 垂直于匀强磁场 B 运动时,其两端会产生感应电动势,常称为动生电动势:

ε = B l v

条件是 v 同时垂直于 B 和导体的长度方向。若导体运动方向与磁场成 θ 角,有效分量为 v sin θ,则 ε = B l v sin θ。该方程可以通过考虑单位时间扫过的面积 ΔA/Δt = l v 从法拉第定律导出。

This formula is particularly useful for problems involving an aircraft flying through the Earth's magnetic field, or a rod sliding on metal rails in a magnetic field. Remember to identify the correct length that is cutting flux.

该公式对涉及飞机穿越地球磁场飞行、或金属杆在磁场中的金属轨道上滑动等问题特别有用。务必确定切割磁感线的有效长度。


5. The AC Generator | 交流发电机

e flux linkage varies as NΦ = NBA cos(ωt), and the induced emf is the negative derivative:

ε = NBA ω sin(ωt)

is a sinusoidal alternating voltage. The time period T is related to ω by ω = 2π/T = 2πf.

简单交流发电机由 N 匝面积为 A 的线圈在匀强磁场 B 中以恒定角速度 ω 旋转构成。磁链变化为 NΦ = NBA cos(ωt),感应电动势为其负导数:

ε = NBA ω sin(ωt)

峰值电动势 ε₀ 为 NBA ω。输出为正弦交流电压。周期 T 与 ω 的关系为 ω = 2π/T = 2πf。

ne is perpendicular to the field (maximum flux, zero emf). The emf curve is a sine wave. For a DC generator, a split-ring commutator rectifies the output, giving a varying but unidirectional emf.

当需要绘制电动势随时间变化的图像时,从 t = 0 开始,此时线圈平面垂直于磁场(磁通量最大,电动势为零)。电动势曲线为正弦波。对于直流发电机,换向器将输出整流,得到变化但单向的电动势。


6. The Ideal Transformer | 理想变压器

A transformer changes the magnitude of an alternating voltage. It consists of two coils, the primary and the secondary, wound on a common soft iron core. An alternating current in the primary sets up a changing magnetic flux in the core, which links the secondary coil and induces an emf across it. For an ideal transformer with no energy losses:

Vₚ / Vₛ = Nₚ / Nₛ

and because power in equals power out, Vₚ Iₚ = Vₛ Iₛ, so:

Iₛ / Iₚ = Nₚ / Nₛ

变压器改变交流电压的大小,由绕在共用软铁芯上的初级线圈和次级线圈组成。初级线圈中的交流电在铁芯中产生变化的磁通,该磁通与次级线圈交链,从而在其次级感应出电动势。对于无能量损失的理想变压器:

Vₚ / Vₛ = Nₚ / Nₛ

且由于输入功率等于输出功率,Vₚ Iₚ = Vₛ Iₛ,因此:

Iₛ / Iₚ = Nₚ / Nₛ

A step-up transformer has Nₛ > Nₚ, so Vₛ > Vₚ but Iₛ < Iₚ. Real transformers have losses due to resistance in the windings, eddy currents in the core, and hysteresis. These reduce efficiency below 100%.

升压变压器 Nₛ > Nₚ,故 Vₛ > Vₚ 但 Iₛ < Iₚ。实际变压器因绕组电阻、铁芯涡流和磁滞现象而导致能量损失,效率低于 100%。


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7. Eddy Currents | 涡流

Eddy currents are circulating currents induced within a bulk conductor when it is exposed to a changing magnetic field. According to Lenz's law, these currents flow in such a way as to oppose the change causing them. In many devices, eddy currents are undesirable because they dissipate energy as heat. They can be reduced by laminating the core - building it from thin insulated sheets that restrict the paths of the currents.

涡流是块状导体处于变化的磁场中时,在其内部感应出的环流。根据楞次定律,这些电流以阻碍引起它们的变化的方式流动。在众多设备中,涡流因以热能形式耗散能量而不受欢迎。通过将铁芯制成薄绝缘片叠层,可以限制涡流路径,从而减小涡流。

Eddy currents also have useful applications, such as in electromagnetic braking, where a metal disc moving through a magnetic field experiences a retarding force due to the induced eddy currents. Induction hobs use eddy currents to heat pans directly.

涡流也有有益的用途,例如电磁制动,金属盘在磁场中运动时,因感应涡流而受到阻力。电磁炉利用涡流直接加热锅具。


8. The DC Motor and Back EMF | 直流电动机与反电动势

When a motor runs, the coil rotates in a magnetic field, and an emf is induced across it due to the very same flux cutting we discussed. This induced emf opposes the supply voltage and is called back emf. The net voltage driving current through the motor is the supply voltage minus the back emf. Back emf increases with the motor's speed, so the starting current is very high because initially there is no back emf.

电动机运转时,线圈在磁场中旋转,由于我们前面讨论过的切割磁感线效应,线圈两端会感应出电动势。这个感应电动势与电源电压方向相反,称为反电动势。驱动电流通过电动机的净电压等于电源电压减去反电动势。反电动势随电机转速增大而增大,因此启动电流很大,因为最初没有反电动势。

If the motor is stalled, the back emf drops to zero, causing the current to surge and potentially burn out the motor. This is why fuses or circuit breakers are essential in motor circuits.

若电动机堵转,反电动势降为零,导致电流激增,可能烧毁电动机。这就是为什么电动机电路中必须安装保险丝或断路器。


9. Graphs and Key Calculations | 图像与关键计算

ld. Remember the phase relationships: Φ is a cosine wave (maximum at t=0), and ε is a sine wave (zero at t=0 and then positive), so ε lags behind Φ by 90°.

你必须能够绘制并解读线圈在磁场中旋转时的 Φ、NΦ、ε 以及电流随时间变化的图像。牢记相位关系:Φ 为余弦波(t=0 时最大),ε 为正弦波(t=0 时为零随后变正),因此 ε 滞后 Φ 90°。

e, or the current in the primary coil. Use efficiency = (output power / input power) × 100% for non-ideal cases. The rms value of an AC is Irms = I₀ / √2, and similarly for voltage.

对于变压器,典型计算包括求匝数、输出电压或初级线圈电流。对于非理想情况,使用效率 =(输出功率/输入功率)× 100%。交流电的有效值 Irms = I₀ / √2,电压同理。

he force on a current-carrying rod moving in a field using F = B I l and then apply Newton's laws to find terminal velocity.

使用 ε = B l v 时,确保所有量均使用国际单位制:B 单位为特斯拉,l 为米,v 为米/秒。在许多问题中,你需要用 F = B I l 求磁场中运动载流杆所受的力,然后应用牛顿定律求终端速度。


10. Common Exam Pitfalls and Tips | 常见失分点与应试技巧


11. Practical Applications in Context | 实际应用场景

Electromagnetic induction is not just theory. In microphones, sound waves cause a coil attached to a diaphragm to move in a magnetic field, inducing a varying emf that produces an electrical audio signal. In magnetic flow meters, a conducting liquid flowing through a magnetic field induces a voltage proportional to the flow rate. Even the card readers on London's transport network use induction to power and communicate with smartcards.

电磁感应不仅是理论。在麦克风中,声波使附着在振膜上的线圈在磁场中移动,感应出变化的电动势,产生电音频信号。在电磁流量计中,导电流体流过磁场时会感应出与流速成正比的电压。就连伦敦交通网络的读卡器也利用感应为智能卡供电并与之通信。

Recognising these applications helps you answer new-style contextual exam questions that ask you to apply your knowledge to unfamiliar situations.

认识这些应用有助于你回答新型情境考题,这类题目要求你将知识运用到不熟悉的场景中。


12. Summary of Essential Formulae | 核心公式汇总

QuantityEquationNotes
Magnetic fluxΦ = BA cos θθ between B and normal
Flux linkageNΦN turns
Faraday's lawε = −N ΔΦ/ΔtDirection by Lenz
Motional emfε = B l vl perpendicular to B and v
Generator emfε = NBA ω sin(ωt)Peak ε₀ = NBA ω
Transformer ratioVₚ/Vₛ = Nₚ/NₛIdeal, AC only
RMS valueIrms = I₀ / √2Same for V
Force on rodF = B I lUsed in motor/braking

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