位移 Displacement u
初速度 Initial velocity v
末速度 Final velocity a
加速度 Acceleration t
时间 Time ### Newton's Laws and Force Diagrams 牛顿定律与受力分析 牛顿三定律是 M1 的灵魂。第一定律告诉你平衡状态下合力为零;第二定律 F=ma 是几乎每道力学题都要用到的核心公式;第三定律则提醒你力总是成对出现的,但作用在不同物体上。 Newton's three laws are the soul of M1. The First Law tells you that the resultant force is zero in equilibrium. The Second Law, F=ma, is the core formula used in nearly every mechanics problem. The Third Law reminds you that forces always come in pairs, but act on different objects. 做题时最关键的一步是画受力图 (force diagram)。先在图上标出所有作用在物体上的力:重力 (weight, 始终竖直向下)、法向反力 (normal reaction, 垂直于接触面)、摩擦力 (friction, 沿接触面与运动方向或趋势相反)、绳的张力 (tension, 沿绳的方向)。然后在运动方向上应用 F=ma。 The most critical step when solving problems is drawing a force diagram. First, mark all forces acting on the object: weight (always vertically downward), normal reaction (perpendicular to the contact surface), friction (along the surface, opposite to motion or tendency to move), and tension (along the direction of the string). Then apply F=ma in the direction of motion. 一个常见陷阱:当物体在斜面上时,记得把重力分解为平行于斜面和垂直于斜面的两个分量。平行分量是 mg sinθ,垂直分量是 mg cosθ。这个分解是 M1 考试的必考内容。 A common pitfall: when an object is on an inclined plane, remember to resolve weight into components parallel and perpendicular to the plane. The parallel component is mg sinθ and the perpendicular component is mg cosθ. This resolution is guaranteed to appear in M1 exams. Friction deserves special attention. The maximum static friction is F_max = μR, where μ is the coefficient of friction and R is the normal reaction. On a rough inclined plane, an object will be in equilibrium if tanθ ≤ μ. This is a classic exam result. 摩擦力需要特别关注。最大静摩擦力 F_max = μR,其中 μ 是摩擦系数,R 是法向反力。在粗糙斜面上,物体保持平衡的条件是 tanθ ≤ μ。这是一个经典的考试结论。 ### Connected Particles 连接体问题 连接体 (滑轮系统或相互接触的物体) 是 M1 的另一大考点。处理这类问题的核心策略是:对每个物体单独列 F=ma 方程,然后联立求解。 Connected particles (pulley systems or objects in contact) are another major M1 topic. The core strategy is: write F=ma for each object individually, then solve the simultaneous equations. For a pulley system with two particles of masses m1 and m2 connected by a light inextensible string over a smooth pulley: T - m1g = m1a (for the lighter mass moving upward) m2g - T = m2a (for the heavier mass moving downward) Acceleration a = (m2 - m1)g / (m1 + m2), and tension T = 2m1m2g / (m1 + m2). 对于由轻质不可伸长绳绕过光滑滑轮连接的两个物体 m1 和 m2 的滑轮系统:加速度 a = (m2 - m1)g / (m1 + m2),张力 T = 2m1m2g / (m1 + m2)。 记住:绳的张力在整个系统中是恒定的 (轻绳假设),加速度大小对两个物体也是相同的 (绳不可伸长)。这两个条件大大简化了计算。 Remember: tension is constant throughout the string (light string assumption), and the magnitude of acceleration is the same for both particles (inextensible string). These two conditions greatly simplify the calculations. Step 1
Draw clear force diagrams for each particle separately Step 2
Write F=ma for each particle in the direction of motion Step 3
Solve the simultaneous equations for a and T ### Moments 力矩与平衡 力矩 (moment) 是力使物体绕某点转动的趋势,大小等于力乘以力到转动点的垂直距离:Moment = F × d。M1 中最重要的力矩考点是刚体的平衡条件:合力为零且合力矩为零。 A moment is the turning effect of a force about a point, equal to the force multiplied by the perpendicular distance from the force to the pivot: Moment = F × d. The most important moment topic in M1 is the equilibrium condition for a rigid body: resultant force = 0 and resultant moment = 0. 做题时选取合适的取矩点 (pivot) 是关键技巧。通常选择未知力最多的点作为取矩点,这样这些未知力对该点的力矩为零,可以直接消去,简化计算。 Choosing the right pivot is a key technique. Usually, pick the point with the most unknown forces as your pivot. These unknown forces will then have zero moment about that point and can be eliminated, simplifying the calculation. A uniform rod means the weight acts at the centre. A non-uniform rod requires you to find or use the given position of the centre of mass. Be careful to distinguish between uniform and non-uniform rods. 均匀杆意味着重力作用在几何中心。非均匀杆则需要你找出或使用给定的质心位置。要仔细区分均匀和非均匀杆。 ### Projectiles 抛体运动 抛体运动把运动学从一维拓展到了二维。核心思想是:水平方向和竖直方向的运动是独立的。水平方向:匀速运动 (ax = 0),vx = ucosθ 恒定不变。竖直方向:匀加速运动 (ay = -g),初始速度 vy = usinθ。 Projectiles extend kinematics from one dimension to two. The core idea: horizontal and vertical motions are independent. Horizontal: constant velocity (ax = 0), vx = ucosθ remains constant. Vertical: constant acceleration (ay = -g), initial velocity vy = usinθ. 六个关键公式要记牢: Six key formulas to memorize: Time of flight (飞行时间): t = 2usinθ / g Maximum height (最大高度): H = u^2 sin^2θ / (2g) Range (射程): R = u^2 sin2θ / g Horizontal position (水平位置): x = utcosθ Vertical position (竖直位置): y = utsinθ - (1/2)gt^2 Trajectory equation (轨迹方程): y = xtanθ - gx^2 / (2u^2 cos^2θ) 一个重要结论:在相同初速度下,45度发射角获得最大射程。如果两个抛射角的和等于90度 (如30度和60度),且初速度相同,则它们的射程相同。 An important result: for a given initial speed, 45 degrees gives the maximum range. If two launch angles sum to 90 degrees (e.g., 30 and 60 degrees) with the same initial speed, their ranges are equal. 做题时最常犯的错误是忘记 g 的符号。如果你取向上为正,那么 g = -9.8。竖直方向上的加速度始终是向下的。 The most common mistake in problem-solving is forgetting the sign of g. If you take upward as positive, then g = -9.8. The acceleration in the vertical direction is always downward. ### Momentum and Impulse 动量与冲量 Momentum is defined as p = mv. It is a vector quantity, so direction matters. Impulse is the change in momentum: I = mv - mu = F × t (for a constant force). 动量定义为 p = mv。它是矢量,所以方向很重要。冲量是动量的变化量:I = mv - mu = F × t (对于恒力)。 The principle of conservation of momentum applies when no external forces act on a system. In collisions: m1u1 + m2u2 = m1v1 + m2v2. This is a powerful tool for solving collision problems. 动量守恒定律适用于系统不受外力的情况。在碰撞中:m1u1 + m2u2 = m1v1 + m2v2。这是解决碰撞问题的重要工具。 特别注意:动量是矢量!如果两物体相向而行,其中一个的初速度要取负值。这可能是 M1 动量题中最容易丢分的地方。 Pay special attention: momentum is a vector! If two objects are moving toward each other, one of the initial velocities must be taken as negative. This is probably the easiest place to lose marks in M1 momentum questions. ### Work, Energy and Power 功、能与功率 Work done by a constant force: W = Fd cosθ, where θ is the angle between the force and the direction of motion. Kinetic energy: KE = (1/2)mv^2. Gravitational potential energy: GPE = mgh. 恒力做功:W = Fd cosθ,其中 θ 是力与运动方向之间的夹角。动能:KE = (1/2)mv^2。重力势能:GPE = mgh。 The work-energy principle states that the total work done on a particle by all forces (including friction) equals the change in its kinetic energy. This is often faster than using SUVAT for problems involving variable forces or curved paths. 功能原理指出:所有力 (包括摩擦力) 对质点做的总功等于其动能的变化量。对于涉及变力或曲线路径的问题,用功能原理往往比 SUVAT 更快。 Power is the rate of doing work: P = Fv for an object moving at constant speed against a resistance. This formula frequently appears in car or train propulsion problems. 功率是做功的速率:对于以恒定速度克服阻力运动的物体,P = Fv。这个公式经常出现在汽车或火车驱动的题目中。 ### Exam Strategy 考试策略 Edexcel M1 考试中时间通常比较紧。建议按照以下顺序做题: Time is usually tight in the Edexcel M1 exam. I suggest the following approach: (1) 先用 2 分钟浏览整张卷子,找出你最擅长的题,从它们开始。Start with your strongest questions after a 2-minute scan of the entire paper. (2) 每道题都画受力图或示意图,即使题目没有要求。Draw a diagram for every question, even if not asked. (3) 注意单位一致。M1 中最常见的单位陷阱是 g 和 kg 的混淆,以及 cm 和 m。Watch unit consistency. The most common unit pitfall in M1 is mixing g and kg, or cm and m. (4) 最终答案保留 2 到 3 位有效数字,除非题目另有说明。Give final answers to 2 or 3 significant figures unless stated otherwise. (5) 如果卡住了超过 5 分钟,先跳过,不要在一道题上耗光时间。If stuck for more than 5 minutes, move on. Do not burn all your time on one question. (6) 最后留 5 分钟检查:所有力的方向是否正确,符号是否统一,单位是否一致。Reserve 5 minutes at the end to check: are all force directions correct, are signs consistent, are units uniform? Kinematics
SUVAT 5 equations
SUVAT 五方程 Forces
F=ma + Resolution
受力分解 Moments
Equilibrium ΣM=0
合力矩为零 Projectiles
Horizontal + Vertical
水平竖直独立 Momentum
Conservation p = mv
动量守恒矢量 ### Common Mistakes to Avoid 常见错误避坑 (1) Forgetting that acceleration can be negative. If a car is braking, a is negative relative to the direction of motion. 忘记加速度可以为负。如果汽车在刹车,相对于运动方向 a 为负。 (2) Using SUVAT when acceleration is not constant. SUVAT only works for uniform acceleration. 在加速度不恒定时使用 SUVAT。SUVAT 只对匀加速有效。 (3) Confusing mass and weight. Mass is in kg, weight is mg in Newtons. Do not write "mass = 50N". 混淆质量和重量。质量单位是 kg,重量是 mg 以牛顿为单位。不要写 "质量 = 50N"。 (4) Forgetting that tension is the same on both sides of a smooth pulley only if the string is light. 忘记只有在轻绳条件下,光滑滑轮两侧的张力才相等。 (5) Using g = 9.8 when the question says g = 10, or vice versa. Always use the g value specified in the question. 题目说 g = 10 时用了 g = 9.8,反之亦然。始终使用题目指定的 g 值。 (6) Forgetting to resolve forces perpendicular to the plane when calculating the normal reaction on an incline. 在计算斜面上的法向反力时忘记把力沿垂直于斜面方向分解。 🎓 A-Level Mechanics is all about practice. The more past papers you work through, the more patterns you will recognise. Keep a formula sheet handy, do timed practice, and focus on understanding rather than memorising. For tutoring inquiries, contact us at 16621398022 (same number on WeChat). 🎓 A-Level 力学就是靠练习堆出来的。做过的真题越多,你能识别的题型模式就越多。准备一张公式表,计时练习,重在理解而非死记。如需辅导咨询,联系 16621398022 同微信。
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