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Essential Maths Book 8H Question Type Analysis | KS3 数学 8H 题型解析

2026-07-14 05:17 · 本文部分内容由AI辅助创作

📚 Essential Maths Book 8H Question Type Analysis | KS3 数学 8H 题型解析

The Essential Maths Book 8H is a comprehensive resource for Key Stage 3 students aiming for higher tier proficiency. It covers a wide range of topics from number operations to algebra, geometry, and statistics. This article breaks down typical question types found in the book, offering step-by-step analysis and bilingual explanations to help students master the key concepts and succeed in assessments.

《Essential Maths Book 8H》是面向 Key Stage 3 高等级学生的综合性数学教材,涵盖了从数字运算到代数、几何和统计的广泛主题。本文解析书中常见的题型,提供逐步分析及中英双语讲解,帮助学生掌握关键概念并在考试中取得优异成绩。


1. Fractions, Decimals and Percentages | 分数、小数与百分数

de the numerator by the denominator. For example, convert 3/8 to a decimal: 3 ÷ 8 = 0.375.

要将分数转换为小数,用分子除以分母。例如,把 3/8 转换为小数:3 ÷ 8 = 0.375。

To convert a decimal to a percentage, multiply by 100 and add the % sign. Therefore 0.375 × 100 = 37.5%.

要将小数转换为百分数,乘以100并加上%符号。因此0.375 × 100 = 37.5%。

r 2/5 + 1/4, the LCM of 5 and 4 is 20. So 2/5 = 8/20 and 1/4 = 5/20 → 8/20 + 5/20 = 13/20.

进行分数加减时,先找到公分母。例如 2/5 + 1/4,5和4的最小公倍数是20,所以2/5 = 8/20,1/4 = 5/20 → 8/20 + 5/20 = 13/20。

vision is performed by flipping the second fraction (the reciprocal) and then multiplying.

分数相乘,直接将分子相乘、分母相乘:2/3 × 4/5 = (2×4)/(3×5) = 8/15。分数除法先翻转第二个分数(取倒数),再相乘。


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2. Ratio and Proportion | 比率与比例

Simplifying ratios involves dividing all parts by their greatest common factor (GCF). For instance, simplify 12:18:24. The GCF is 6, so divide each term by 6 to get 2:3:4.

化简比率需要将所有部分除以它们的最大公因数(GCF)。例如,化简 12:18:24,最大公因数是6,各项除以6得到 2:3:4。

Sharing in a given ratio: If £50 is shared in the ratio 2:3, the total number of parts is 2+3=5. One part is £50 ÷ 5 = £10, so the shares are 2 × £10 = £20 and 3 × £10 = £30.

按给定比率分配:如果£50按2:3分配,总份数为2+3=5。一份为£50 ÷ 5 = £10,因此分配额为2 × £10 = £20和3× £10 = £30。

Direct proportion problems often involve scaling. If 4 apples cost £1.20, the cost of 10 apples is found by the unitary method: 1 apple costs £1.20 ÷ 4 = £0.30, so 10 apples cost 10 × £0.30 = £3.00. Alternatively use the multiplier 10/4: (10/4) × £1.20 = £3.00.

正比例问题常涉及缩放。如果4个苹果售价£1.20,可用单位法求10个苹果的价钱:1个苹果价为£1.20 ÷ 4 = £0.30,则10个苹果为10 ×

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