📚 Cis-Trans Isomerism and E/Z Nomenclature in IB Chemistry | IB化学：顺反异构与E/Z构型命名
Geometric isomerism arises when the free rotation around a bond is restricted, most commonly at a carbon-carbon double bond. In IB Chemistry, you need to distinguish between the traditional cis-trans system and the more general E/Z nomenclature based on CIP priority rules.
几何异构源于分子中某些键的旋转受阻，最常见的例子是碳碳双键。在IB化学中，你需要区分传统的顺反命名法和基于CIP优先规则的更通用的E/Z命名法。
1. What Is Geometric Isomerism? | 什么是几何异构？
Geometric isomers are molecules with the same molecular formula and the same connectivity of atoms, but different spatial arrangements due to restricted rotation around a double bond or a ring structure.
几何异构体是指具有相同分子式和相同原子连接顺序，但由于双键或环结构限制旋转而具有不同空间排列的分子。
Double bonds prevent rotation because the p orbitals must stay parallel to form the π bond.
双键阻碍旋转，因为p轨道必须保持平行才能形成π键。
Each carbon in the double bond must have two different groups attached to it.
双键上的每个碳原子必须连接两个不同的基团。
2. Conditions for Cis-Trans Isomerism | 顺反异构的条件
For a simple alkene such as but-2-ene, the two identical methyl groups can be on the same side of the double bond (cis) or opposite sides (trans).
对于丁-2-烯这样的简单烯烃，两个相同的甲基可以在双键的同侧（顺式）或异侧（反式）。
CH₃CH=CHCH₃
e, propene CH₃CH=CH₂ has two hydrogens on one carbon, so cis-trans isomers are impossible.
如果任何一个双键碳连接两个相同基团，就不存在几何异构。例如丙烯CH₃CH=CH₂，其中一个碳上连有两个氢原子，因此不可能有顺反异构。
3. Cis and Trans Notation | 顺式与反式表示法
In the cis-trans system, we compare the two groups attached to each carbon in the double bond. If two similar or larger groups are on the same side, it is cis; if on opposite sides, it is trans.
在顺反命名法中，我们比较双键每个碳上连接的基团。如果两个相似或较大的基团在同侧，则为顺式；如果在异侧，则为反式。
| Cis-Isomer | Trans-Isomer |
| Higher priority groups on same side | Higher priority groups on opposite sides |
| Often less stable due to steric hindrance | Often more stable due to less crowding |
For example, cis-but-2-ene has the two methyl groups on the same side, while trans-but-2-ene has them on opposite sides.
例如，顺式丁-2-烯的两个甲基在同侧，反式丁-2-烯的两个甲基在异侧。
4. Limitations of the Cis-Trans System | 顺反命名法的局限性
The cis-trans system works well when identical groups exist on both double-bond carbons. But when the four substituents are all different, cis and trans become ambiguous.
当双键两侧存在相同基团时，顺反命名法非常有效。但当四个取代基都不同时，顺反命名就会变得模糊不清。
Consider 1-chloro-2-bromopropene: which groups should we compare? The cis-trans system cannot provide a clear and unambiguous description.
考虑1-氯-2-溴丙烯：应该比较哪两个基团？顺反命名法无法给出清晰且明确的描述。
Therefore, a more systematic method based on atomic number is needed. This is the E/Z system.
因此，需要一种基于原子序数的更系统的方法，这就是E/Z命名法。
5. CIP Priority Rules | CIP优先规则
The Cahn-Ingold-Prelog (CIP) priority rules assign a priority order to the two substituents on each carbon of the double bond.
Cahn-Ingold-Prelog（CIP）优先规则为双键每个碳上的两个取代基分配优先顺序。
Compare the atomic number of the atom directly attached to the double-bond carbon. Higher atomic number gets higher priority.
比较直接连接到双键碳的原子的原子序数。原子序数越大，优先顺序越高。
If the first atoms are identical, move outward to the next atoms until a difference is found.
如果第一个原子相同，则向外继续比较，直到找到差异。
Double bonds are treated as if the atom is bonded to two copies of that atom.
双键被视为该原子连接了两份相同的原子。
I > Br > Cl > S > F > O > N > C > H is a common priority sequence.
常见优先顺序为：I > Br > Cl > S > F > O > N > C > H。
6. E and Z Notation | E/Z命名法
After determining priorities on each carbon, we compare the two high-priority groups:
在确定每个碳上的优先顺序后，比较两个优先基团：
If the higher-priority groups are on the same side of the double bond, the configuration is Z (from German zusammen, meaning together).
如果两个优先基团在双键的同侧，则构型为Z（来自德语zusammen，意为“在一起”）。
If the higher-priority groups are on opposite sides, the configuration is E (from German entgegen, meaning opposite).
如果两个优先基团在异侧，则构型为E（来自德语entgegen，意为“相反”）。
Z = same side; E = opposite side
Z = 同侧；E = 异侧
7. Step-by-Step Determination | 分步判定方法
Let us apply E/Z naming systematically:
让我们系统性地应用E/Z命名法：
Identify the double bond and the two substituents on each carbon.
识别双键以及每个碳上的两个取代基。
Apply CIP rules to rank the two substituents on the left-hand carbon: priority 1 and priority 2.
应用CIP规则对左侧碳上的两个取代基排序：优先1和优先2。
Apply CIP rules to rank the two substituents on the right-hand carbon.
应用CIP规则对右侧碳上的两个取代基排序。
Compare the position of the two priority-1 groups. If they are on the same side, assign Z; if on opposite sides, assign E.
比较两个优先1基团的位置。如果同侧，则为Z；如果异侧，则为E。
Example: In 1-bromo-1-chloro-2-iodoethene, compare Br vs Cl on the first carbon and I vs H on the second carbon. I has higher priority than H, and Br has higher priority than Cl. If Br and I are on the same side, it is Z; if opposite, it is E.
例如：在1-溴-1-氯-2-碘乙烯中，比较第一个碳上的Br与Cl，以及第二个碳上的I与H。I的优先级高于H，Br的优先级高于Cl。如果Br和I在同侧，则为Z；如果在异侧，则为E。
8. E/Z vs Cis-Trans Comparison | E/Z与顺反命名对比
For many simple alkenes, cis corresponds to Z and trans corresponds to E. However, this is not always true.
对于许多简单烯烃，顺式对应Z，反式对应E。但这并不总是成立。
Consider 1-chloro-1-fluoro-propene: the higher priority groups on the two carbons are Cl and CH₃. If Cl and CH₃ are on the same side, it is Z, but the two smaller groups (H and F) may also be on the same side, making it look "cis-like" yet not a true cis isomer because the groups are not identical.
考虑1-氯-1-氟丙烯：两个碳上的优先基团分别是Cl和CH₃。如果Cl和CH₃在同侧，则为Z，但两个较小基团（H和F）也可能同侧，使其看似“顺式”，但并非真正的顺式异构体，因为基团不相同。
| Comparison | Cis-Trans | E/Z |
| Basis | Similar groups on same/opposite side | CIP priority groups on same/opposite side |
| Requires identical groups? | Often yes | No |
| General use | Simple alkenes, cycloalkanes | All alkenes with different substituents |
9. Geometric Isomerism in Cycloalkanes | 环烷烃中的几何异构
Cycloalkanes also display cis-trans isomerism because the ring prevents free rotation about C-C bonds.
环烷烃也存在顺反异构，因为环结构阻碍了C-C键的自由旋转。
In 1,2-dimethylcyclohexane, both methyl groups can be on the same face of the ring (cis) or opposite faces (trans).
在1,2-二甲基环己烷中，两个甲基可以在环的同一面（顺式）或相反面（反式）。
Note that E/Z nomenclature is not normally used for simple cycloalkanes unless a double bond is present outside the ring; cis-trans is preferred.
注意：对于简单的环烷烃，通常不使用E/Z命名法，除非环外有双键；优先使用顺反命名。
10. Physical Properties and Stability | 物理性质与稳定性
Cis and trans isomers often have different boiling points, melting points, and dipole moments.
顺式和反式异构体通常具有不同的沸点、熔点和偶极矩。
Cis alkenes typically have higher boiling points than trans alkenes because the molecular dipole is larger.
顺式烯烃通常比反式烯烃具有更高的沸点，因为顺式异构体的分子偶极矩更大。
Trans alkenes are generally more stable than cis alkenes because steric repulsion between large groups is minimized.
反式烯烃通常比顺式烯烃更稳定，因为大基团之间的空间排斥作用最小化。
Melting points may be higher for trans isomers because of better packing in the solid state.
反式异构体的熔点可能更高，因为固态堆积更好。
11. IB Exam Tips & Common Mistakes | IB考试技巧与常见错误
Students often lose marks by confusing E/Z with cis-trans or by applying priorities incorrectly.
学生常常因为混淆E/Z与顺反，或错误应用优先规则而失分。
Always use the directly attached atom first, not the whole group.
始终先比较直接连接的原子，而不是整个基团。
For substituents like -CH₂CH₃ vs -CH₃, both have carbon as the first atom, so compare the next atoms: one carbon and hydrogens vs one carbon and hydrogens. Since -CH₂CH₃ eventually has another carbon, it gets higher priority than -CH₃.
对于诸如-CH₂CH₃ vs -CH₃这样的取代基，第一个原子都是碳，因此继续比较下一层：一个碳加氢 vs 一个碳加氢。由于-CH₂CH₃最终连有另一个碳，其优先级高于-CH₃。
Do not say "cis = Z" without checking the actual groups. E/Z is the safer general method.
不要盲目说“顺式等于Z”，必须实际检查基团。E/Z是更安全通用的一般方法。
In exam questions, draw the displayed formula clearly and label the two sides of the double bond before assigning E or Z.
在考试题目中，先画出结构式，清楚标注双键两侧，再判定E或Z。
12. Worked Example: But-2-ene and Beyond | 实例解析：丁-2-烯及其拓展
For but-2-ene, CH₃CH=CHCH₃, each double-bond carbon has CH₃ and H.
对于丁-2-烯，CH₃CH=CHCH₃，每个双键碳上都有CH₃和H。
Priority: CH₃ > H on both carbons
优先级：CH₃ > H（两个碳上都相同）
If the two CH₃ groups are on the same side, it is Z-but-2-ene (which is also cis-but-2-ene). If they are on opposite sides, it is E-but-2-ene (trans-but-2-ene).
如果两个CH₃同侧，则为Z-丁-2-烯（即顺式丁-2-烯）；如果在异侧，则为E-丁-2-烯（即反式丁-2-烯）。
For a more complex example like 2-chlorobut-2-ene, the left carbon has Cl and CH₃; the right carbon has CH₃ and H. Cl > CH₃, and CH₃ > H. Thus the priority groups are Cl and CH₃. Their relative position determines E or Z.
对于更复杂的例子如2-氯丁-2-烯，左侧碳上有Cl和CH₃；右侧碳上有CH₃和H。Cl > CH₃，且CH₃ > H。因此优先基团为Cl和CH₃。它们的相对位置决定E或Z。
Published by TutorHao | Chemistry Revision Series | aleveler.com
更多咨询请联系16621398022（同微信）
或截图后用「扫一扫 → 相册」选择本图