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The Definite Integral as a Limit of a Sum | 积分作为和式的极限与应用

2026-08-30 17:15 · 本文部分内容由AI辅助创作

📚 The Definite Integral as a Limit of a Sum | 积分作为和式的极限与应用

In IB Mathematics, the definite integral is not just an antiderivative; it is defined as the limit of a sum of many small pieces. This idea links discrete computing with continuous exactness and gives us powerful tools for geometry, physics and statistics.

在 IB 数学中,定积分不只是求导的逆运算,它本质上是一系列微小量的和的极限。这种“分割、近似、求和、取极限”的思想,将离散计算与连续精确值联系起来,也为面积、路程、平均值和体积等实际问题提供了统一方法。


1. From Rectangle Sums to the Definite Integral | 从矩形和到定积分

choose a sample point xᵢ, and form the product f(xᵢ)Δx. Adding these products gives a Riemann sum that approximates the signed area under the curve.

设函数 f 在区间 [a,b] 上连续。将 [a,b] 分成 n 个等宽小区间,每个区间宽度为 Δx = (b−a)/n。在第 i 个小区间内取一点 xᵢ,构造乘积 f(xᵢ)Δx,再把这些乘积加起来,得到的就是曲线下方“有向面积”的黎曼和近似值。

∫ₐᵇ f(x) dx = limₙ→∞ ∑ᵢ₌₁ⁿ f(xᵢ)Δx, Δx = (b−a)/n

When n tends to infinity, the rectangles become thinner and thinner, and the sum approaches the definite integral. The integral sign itself resembles an elongated S, standing for “sum”.

当 n 趋于无穷大时,矩形越来越窄,和式的极限就是定积分。积分符号 ∫ 就像拉长的字母 S,正是 “Sum(和)” 的含义。


2. Left, Right and Midpoint Rectangles | 左矩形、右矩形和中点矩形

For the same n, the choice of sample point changes the estimate. The three most common choices are left endpoints, right endpoints and midpoints.

对于同样的 n,取样点的位置会改变估计值。最常用的三种取法分别是左端点、右端点和中点。

For f(x)=x², a=0, b=1 and n=4, the approximations are shown below.

对于 f(x)=x²,取 a=0,b=1,n=4,各近似值为:

MethodSumValue
Left0.25(0² + 0.25² + 0.5² + 0.75²)0.21875
Right0.25(0.25² + 0.5² + 0.75² + 1²)0.46875
Midpoint0.25(0.125² + 0.375² + 0.625² + 0.875²)0.328125
Exact∫₀¹ x² dx1/3 ≈ 0.3333

The midpoint method is often noticeably more accurate than left or right rectangles.

中点法通常比左矩形法或右矩形法更精确。


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3. The Formal Limit Definition | 定积分的正式极限定义

tends to a single finite number as the maximum subinterval width approaches zero, that number is the definite integral.

更一般地,黎曼和可以基于 [a,b] 的任意分割。对于每个长度为 Δxᵢ 的小区间,取样本点 cᵢ。当最大小区间宽度趋于零时,如果和式 ∑f(cᵢ)Δxᵢ 趋于唯一有限值,这个值就是定积分。

∫ₐᵇ f(x) dx = limₙ→∞ ∑ᵢ₌₁ⁿ f(a + i(b−a)/n) · (b−a)/n

ple: evaluate ∫₀¹ x² dx using the definition. Here f(x)=x², a=0, b=1, Δx=1/n and xᵢ = i/n.

例:用定义计算 ∫₀¹ x² dx。这里 f(x)=x²,a=0,b=1,Δx=1/n,xᵢ = i/n。

Sₙ = ∑ᵢ₌₁ⁿ (i/n)² · (1/n) = (1/n³) ∑ᵢ₌₁ⁿ i²

formula ∑ᵢ₌₁ⁿ i² = n(n+1)(2n+1)/6, we obtain Sₙ = n(n+1)(2n+1)/(6n³), whose limit is 1/3.

利用平方和公式 ∑ᵢ₌₁ⁿ i² = n(n+1)(2n+1)/6,得到 Sₙ = n(n+1)(2n+1)/(6n³),其极限为 1/3。

∫₀¹ x² dx = limₙ→∞ n(n+1)(2n+1)/(6n³) = 1/3


4. Geometric Meaning: Signed Area | 几何意义:有向面积

uals the area between the curve and the x-axis. If f(x) is sometimes negative, each rectangle contributes f(xᵢ)Δx, which may be negative, so the definite integral gives signed area.

若 f(x) ≥ 0,则 ∫ₐᵇ f(x) dx 等于曲线与 x 轴之间的面积。若 f(x) 在某些区间上为负,则每个矩形贡献 f(xᵢ)Δx 可能为负,因此定积分给出的是有向面积。

Total geometric area = ∫ₐᵇ |f(x)| dx

This distinction is essential in exam questions that ask for “area” rather than “integral”.

这一区别在考试中非常重要,因为题目若问 “面积”,而不是 “定积分”,就需要对 |f(x)| 积分。


5. Application: Displacement and Total Distance | 应用:位移与总路程

m t=a to t=b is the integral of v(t). However, total distance travelled is the integral of |v(t)|, because distance must always accumulate positively.

已知速度函数 v(t),从 t=a 到 t=b 的位移是 v(t) 的定积分;但实际总路程必须用 |v(t)| 的定积分,因为路程总是正向累积的。

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Published by TutorHao | IB Mathematics Revision Series | aleveler.com

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