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Motion in Polar Coordinates | 极坐标下的运动描述

2026-08-30 17:06 · 本文部分内容由AI辅助创作

📚 Motion in Polar Coordinates | 极坐标下的运动描述

Describing motion in polar coordinates is a powerful technique in IB Mathematics, especially when dealing with circular or spiral paths. Instead of using fixed x and y axes, we locate a point by its distance from the origin and the angle it makes with a reference direction.

在极坐标中描述运动是IB数学中非常实用的技巧,特别适合处理圆周或螺旋轨迹。我们不再使用固定的x轴和y轴,而是通过点到原点的距离以及与参考方向之间的夹角来确定位置。


1. Polar Coordinate Basics | 极坐标基础

In polar coordinates, a point P is represented by (r, θ), where r is the radial distance from the pole (origin) and θ is the polar angle measured from the positive x-axis. The conversion to Cartesian coordinates is:

在极坐标系中,点P用(r, θ)表示,其中r是到极点(原点)的径向距离,θ是从正x轴起逆时针旋转的极角。转换为直角坐标的关系为:

x = r cos θ, y = r sin θ, r² = x² + y², tan θ = y / x

describing motion, both r and θ can depend on time t. Thus we write r = r(t) and θ = θ(t).

描述运动时,r和θ都可以随时间t变化,因此我们写成r = r(t) 和 θ = θ(t)。


2. Unit Vectors in Polar Coordinates | 极坐标中的单位矢量

The key to analyzing motion in polar coordinates is using the two unit vectors: the radial unit vector er and the transverse (angular) unit vector e_θ.

分析极坐标中运动的关键是使用两个单位矢量:径向单位矢量er和横向(角向)单位矢量e_θ。

These are defined as:

它们的定义如下:

er = cos θ i + sin θ j

e_θ = -sin θ i + cos θ j

i and j are the standard Cartesian unit vectors. Notice that e_θ is obtained by rotating er by 90 degrees counterclockwise.

这里i和j是标准直角坐标单位矢量。注意e_θ由er逆时针旋转90度得到。


3. Derivatives of Unit Vectors | 单位矢量的导数

To find velocity and acceleration, we must differentiate the unit vectors with respect to time. Using the chain rule:

为了求速度和加速度,我们必须对单位矢量关于时间求导。利用链式法则:

d(er)/dt = θ̇ e_θ

d(e_θ)/dt = -θ̇ er

Here θ̇ e results are fundamental: the radial unit vector changes in the transverse direction, and the transverse unit vector changes in the negative radial direction.

这里θ̇ = dθ/dt是角速度。这些结果非常重要:径向单位矢量的变化方向是横向,而横向单位矢量的变化方向是负径向。


4. Position Vector | 位置矢量

The position vector of a particle in polar coordinates is simply:

质点在极坐标中的位置矢量可以简洁地写成:

r = r er

This means the particle is at a distance r from the origin along the direction er transverse component of position because e_θ points perpendicular to the radial direction.

这意味着质点沿er方向距离原点为r。位置没有横向分量,因为e_θ垂直于径向方向。


5. Velocity in Polar Coordinates | 极坐标中的速度

Differentiating the position vector with respect to time using the product rule and the derivative of er gives:

对位置矢量关于时间求导,使用乘积法则以及er的导数,得到:

v = ṙ er + r θ̇ e_θ

Thus the velocity has two components:

因此速度具有两个分量:

径向分量:vr = ṙ,表示距原点距离的变化快慢。

横向分量:v_θ = r θ̇,表示绕原点旋转产生的速度。


6. Acceleration in Polar Coordinates | 极坐标中的加速度

Differentiating the velocity vector again, and carefully applying the product rule to both terms, yields the acceleration:

再次对速度矢量求导,并仔细对两项应用乘积法则,得到加速度:

a = (r̈ - r θ̇²) er + (r θ̈ + 2 ṙ θ̇) e_θ

The radial component contains r̈ and the centripetal term -r θ̇². The transverse component contains r θ̈ and the Coriolis term 2 ṙ θ̇.

径向分量包含r̈和向心项-r θ̇²。横向分量包含r θ̈和科里奥利项2 ṙ θ̇。

In uniform circular motion, r is constant, so ṙ = 0 and r̈ = 0, giving a = -r θ̇² er, which points toward the center.

在匀速圆周运动中,r为常数,因此ṙ = 0且r̈ = 0,得到a = -r θ̇² er,指向圆心。


7. Uniform Circular Motion | 匀速圆周运动

n a circle of radius R with constant angular speed ω, we have r = R and θ = ωt + θ₀. Then:

对于半径为R、角速度恒为ω的圆周运动,有r = R,θ = ωt + θ₀。于是:

v = R ω e_θ

a = -R ω² er

cceleration = Rω². The acceleration vector always points towards the center of the circle.

这与我们熟悉的结果一致:速率 = Rω,向心加速度 = Rω²。加速度矢量始终指向圆心。


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8. Angular Velocity and Angular Acceleration | 角速度与角加速度

In polar motion problems, θ̇ represents the angular velocity and θ̈ represents the angular acceleration. These are often denoted by ω and α respectively.

在极坐标运动问题中,θ̇表示角速度,θ̈表示角加速度。它们通常分别用ω和α表示。

When θ̈ = 0, the angular velocity is constant, and the transverse acceleration simplifies to 2 ṙ θ̇, which is nonzero only if the radial distance is changing.

当θ̈ = 0时,角速度为常数,横向加速度简化为2 ṙ θ̇,只有在径向距离变化时才不为零。

Example: if r = t² and θ = 3t, then θ̇ = 3 and θ̈ ses steadily, causing a transverse acceleration even though the angular speed is constant.

例如:若r = t²且θ = 3t,则θ̇ = 3,θ̈ = 0。径向距离持续增大,即使角速度恒定,也会产生横向加速度。


9. Motion along a Spiral | 螺旋运动

= aθ. Suppose a particle moves along this spiral with constant angular speed ω, so θ = ωt.

一个常见的应用是阿基米德螺旋线,满足r = aθ。假设质点以恒定角速度ω沿此螺旋运动,即θ = ωt。

Then r = aωt, ṙ = aω, and r̈ = 0. The velocity components are:

则r = aωt,ṙ = aω,r̈ = 0。速度分量为:

v = aω er + aω² t e_θ

The acceleration components are:

加速度分量为:

a = -aω³ t² er + 2aω² e_θ

Notice how the radial acceleration grows with t² due to the increasing curvature as the spiral expands.

注意径向加速度随t²增大,这是因为螺旋扩展时曲率不断变化。


10. Relating Polar and Cartesian Descriptions | 极坐标与直角坐标描述的联系

Sometimes it is necessary to switch between polar and Cartesian descriptions. Given x(t) and y(t), we can find r and θ:

有时需要在极坐标和直角坐标描述之间转换。已知x(t)和y(t),可求出r和θ:

r = √x² + y², θ = arctan(y/x)

Then the polar velocity components can be computed from ṙ = (x ẋ + y ẏ) / r and θ̇ = (x ẏ - y ẋ) / r².

然后可由ṙ = (x ẋ + y ẏ) / r和θ̇ = (x ẏ - y ẋ) / r²计算极坐标速度分量。

Conversely, if vr and v_θ are known, the Cartesian velocity components are:

反之,如果已知vr和v_θ,直角坐标速度分量为:

ẋ = vr cos θ - v_θ sin θ

ẏ = vr sin θ + v_θ cos θ


11. Worked Example: Elliptical Motion | 例题:椭圆运动

rticle moving such that r = a(2 + cos t) and θ = t. Find the radial acceleration at t = 0.

考虑一个质点,其运动满足r = a(2 + cos t)和θ = t。求t = 0时径向加速度。

First compute derivatives:

首先计算导数:

ṙ = -a sin t, r̈ = -a cos t, θ̇ = 1, θ̈ = 0

At t = 0: r = 3a, ṙ = 0, r̈ = -a, θ̇ = 1. Therefore:

在t = 0时:r = 3a,ṙ = 0,r̈ = -a,θ̇ = 1。因此:

ar = r̈ - r θ̇² = -a - 3a = -4a

The negative sign indicates the radial acceleration points toward the origin (in the -er direction). The transverse acceleration is a_θ = r θ̈ + 2 ṙ θ̇ = 0.

负号表示径向加速度指向原点(沿-er方向)。横向加速度为a_θ = r θ̈ + 2 ṙ θ̇ = 0。


12. Exam Tips and Common Mistakes | 考试技巧与常见错误

To succeed in polar motion questions, keep these points in mind:

要在极坐标运动问题中取得好成绩,请谨记以下几点:

Practicing differentiation of unit vectors and applying the product rule correctly will help you avoid calculation errors.

练习单位矢量的微分并正确应用乘积法则,将有助于避免计算错误。


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