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A-Level Physics: Definition and Units of Magnetic Flux Density | A-Level 物理:磁通量密度的定义与单位

2026-08-30 14:08 · 本文部分内容由AI辅助创作

📚 A-Level Physics: Definition and Units of Magnetic Flux Density | A-Level 物理:磁通量密度的定义与单位

Magnetic flux density is one of the most important concepts in A-Level physics, especially in the CIE syllabus. It connects magnetic forces, electric currents, and the geometry of magnetic fields into a single measurable quantity. This article explains its definition, the equation used to define it, its units, and common exam applications.

磁通量密度是 A-Level 物理(尤其是 CIE 考纲)中最核心的概念之一。它将磁力、电流和磁场的几何形状联系成一个可测量的物理量。这篇文章将讲解它的定义、定义式、单位以及常见考点应用。


1. What Is Magnetic Flux Density? | 什么是磁通量密度?

Magnetic flux density, usually given the symbol B, describes how strong and how concentrated a magnetic field is at a particular point. It is a vector quantity, meaning it has both magnitude and direction. The direction of B is the direction in which a tiny north pole would experience a force, or equivalently, the direction of the field lines.

磁通量密度通常用符号 B 表示,用来描述磁场在某一点的强弱与密集程度。它是一个矢量,既有大小也有方向。B 的方向是小磁针北极受力方向,也就是磁场线的切线方向。

Although many students first meet B in the context of the force on a current-carrying wire, the formal definition relies on that very force. The SI unit of B is the tesla (T), named after Nikola Tesla.

虽然很多同学首次接触 B 是在电流导线受力的场景中,但 B 的正式定义恰恰依赖这个力。B 的国际单位是特斯拉(T),以尼古拉·特斯拉命名。


2. The Defining Equation: F = BIL sin θ | 定义式:F = BIL sin θ

For a straight wire of effective length L carrying a current I inside a uniform magnetic field of flux density B, the magnetic force F on the wire is given by:

对于一段有效长度为 L、通有电流 I 的直导线,处于磁通量密度为 B 的匀强磁场中时,导线受到的磁力 F 为:

F = B I L sin θ

en the wire is perpendicular to the field, θ = 90° and sin θ = 1, so the force is maximum:

其中 θ 是电流方向与磁场方向之间的夹角。当导线垂直于磁场时,θ = 90°,sin θ = 1,力达到最大值:

F = B I L

This maximum-force case is used to define B. Rearranging gives:

这个最大力的情况被用来定义 B。整理后得到:

B = F / (I L)

Thus magnetic flux density can be defined as the force per unit current per unit length acting on a straight conductor placed perpendicular to the magnetic field.

因此磁通量密度可以定义为:垂直于磁场的直导线,单位电流、单位长度上所受到的磁力。


3. Alternative Definition: Magnetic Flux per Unit Area | 另一种定义:单位面积上的磁通量

Magnetic flux density is also related to magnetic flux Φ. Magnetic flux is the total number of magnetic field lines passing through a given area, while flux density is the concentration of those lines per unit area. For a uniform field perpendicular to a plane of area A:

磁通量密度还与磁通量 Φ 有关。磁通量是穿过某一面积的总磁场线数,而磁通量密度是单位面积上磁场线的密集程度。对于匀强磁场且方向垂直于面积为 A 的平面时:

Φ = B A

If the field is not perpendicular to the area, a cos θ factor is needed, where θ is the angle between the magnetic field direction and the normal to the area:

如果磁场不垂直于平面,则需要乘以 cos θ,其中 θ 是磁场方向与平面法线之间的夹角:

Φ = B A cos θ

Because the tesla can be expressed as a weber per square metre (Wb m⁻²), B can be thought of as "flux per unit area." This is why it is called flux density.

因为特斯拉也可以表示为韦伯每平方米(Wb m⁻²),所以 B 可以被理解为“单位面积上的磁通量”。这就是为什么它被称为磁通量密度。


4. Unit of Magnetic Flux Density: The Tesla | 磁通量密度的单位:特斯拉

s⁻²), current I has units of amperes (A), and length L has units of metres (m). Therefore:

从 B = F / (I L) 出发,我们可以推导出特斯拉用 SI 基本单位表示的形式。力 F 的单位是牛顿(N = kg m s⁻²),电流 I 的单位是安培(A),长度 L 的单位是米(m)。因此:

1 T = 1 N A⁻¹ m⁻¹ = 1 kg A⁻¹ s⁻²

Equivalently, using the flux definition Φ = B A, we have:

等效地,从磁通量定义 Φ = B A 可得:

1 T = 1 Wb m⁻²

So one tesla is the flux density that produces a force of 1 newton on a 1 metre wire carrying a current of 1 ampere, when the wire is perpendicular to the field.

因此,1 特斯拉是:当 1 米长导线通有 1 安培电流且垂直磁场放置时,受到 1 牛顿磁力所对应的磁通量密度。


5. Magnetic Flux Density and Moving Charges | 磁通量密度与运动电荷

A charged particle moving with velocity v through a magnetic field B experiences a magnetic force. For a charge q, the magnitude of the force is:

带电粒子以速度 v 在磁场 B 中运动时,会受到磁力。对于电荷 q,力的大小为:

F = q v B sin θ

equation is often used in circular motion problems involving charged particles in magnetic fields.

其中 θ 是速度方向与磁场方向的夹角。当电荷垂直磁场运动时,sin θ = 1,F = qvB。这个公式常用于解带电粒子在磁场中做圆周运动的题目。

This relationship is also a possible way to define B: the magnetic flux density is the force acting on a unit charge moving at unit velocity perpendicular to the field.

这一关系也可以用来定义 B:磁通量密度是单位电荷以单位速度垂直磁场运动时所受到的磁力。


6. Magnetic Flux Density vs Magnetic Flux | 磁通量密度与磁通量的区别

Students often confuse magnetic flux density B and magnetic flux Φ. The table below summarises the key differences.

同学们经常混淆磁通量密度 B 和磁通量 Φ。下表总结了它们的核心区别。

Quantity Magnetic Flux Density B Magnetic Flux Φ
Nature Vector (strength of field at a point) Scalar (total field lines through an area)
Symbol B Φ
SI unit tesla (T) weber (Wb)
Related formula B = F / (IL) Φ = B A cos θ

Note that Φ depends on the area through which the field passes, while B is a local property of the field. A strong field can have a small flux if the area is tiny; a weak field can have a large flux if the area is huge.

注意:Φ 取决于磁场穿过的面积,而 B 是磁场的局部属性。场很强但面积很小时,磁通量可能很小;场很弱但面积很大时,磁通量也可能很大。


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7. Worked Example: Calculating Force from B | 例题:由 B 计算磁力

A straight wire of length 0.20 m carries a current of 4.0 A and is placed in a uniform magnetic field of flux density 0.30 T. The wire is perpendicular to the field. Calculate the magnetic force on the wire.

一根长为 0.20 m 的直导线通有 4.0 A 的电流,放在磁通量密度为 0.30 T 的匀强磁场中,导线与磁场垂直。求导线所受磁力。

Since the wire is perpendicular to the field, sin θ = 1. Using F = BIL:

因为导线垂直于磁场,sin θ = 1。利用 F = BIL:

F = 0.30 × 4.0 × 0.20 = 0.24 N

The force is 0.24 N. Use Fleming's left-hand rule to determine the direction if required.

力为 0.24 N。如果需要确定方向,可以用弗莱明左手定则。

If the wire were at 30° to the field instead, then θ = 30° and:

如果导线与磁场夹角为 30°,则 θ = 30°,于是:

F = 0.30 × 4.0 × 0.20 × sin 30° = 0.12 N

This smaller value shows why the sin θ factor is essential in the general formula.

这个较小的值说明为什么通用公式中的 sin θ 因子必不可少。


8. Worked Example: Determining B from Measurements | 例题:由测量值求 B

A student places a 5.0 cm wire at right angles to a magnetic field. When a current of 2.0 A flows, the wire experiences a force of 0.015 N. What is the magnetic flux density?

学生将一根 5.0 cm 的导线垂直放入磁场中,当通过 2.0 A 电流时,导线受到 0.015 N 的力。求磁通量密度。

metres: L = 0.050 m. Since the wire is perpendicular to the field, rearrange B = F / (IL):

首先将长度换算为米:L = 0.050 m。由于导线垂直磁场,整理 B = F / (IL):

B = 0.015 / (2.0 × 0.050) = 0.15 T

So the flux density is 0.15 T.

因此磁通量密度为 0.15 T。


9. Common Exam Misconceptions | 常见考试误区


10. Key Points for Revision | 复习要点


With these definitions and formulas, you can confidently solve CIE A-Level problems on magnetic flux density and connect them to forces on currents and moving charges.

掌握了这些定义和公式,你就能自信地解决 CIE A-Level 中关于磁通量密度的问题,并将其与电流受力和运动电荷受力联系起来。

Published by TutorHao | Physics Revision Series | aleveler.com

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