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A-Level Biology: Cell Biology & Microscopy Techniques | A-Level 生物:细胞生物学与显微镜技术

2026-08-30 12:38 · 本文部分内容由AI辅助创作

📚 A-Level Biology: Cell Biology & Microscopy Techniques | A-Level 生物:细胞生物学与显微镜技术

The cell is the fundamental unit of all living organisms. Mastering cell structure and the techniques used to study it is essential for the CIE A-Level Biology examinations. This article provides a comprehensive revision guide, placing particular emphasis on microscopy techniques, magnification, and organelle function.

细胞是一切生物体的基本结构单位。掌握细胞结构以及研究细胞的技术手段,是 CIE A-Level 生物考试的关键。本文是一份全面的复习指南,重点介绍显微镜技术、放大倍数与细胞器功能。


1. The Cell Theory | 细胞学说

The cell theory was established in the 19th century by Schleiden, Schwann, and Virchow, and it remains the organising principle of biology. It rests on three fundamental claims, all of which you are expected to apply when comparing different cell types in the CIE examination.

细胞学说由施莱登、施万和菲尔肖于 19 世纪建立,至今仍是生物学的组织原则。该学说基于三项基本主张,在 CIE 考试中,你需要运用这些观点来比较不同类型的细胞。

Notable exceptions exist, such as viruses, which are acellular and considered non-living under most definitions. However, A-Level questions rarely ask you to debate this; instead, focus on how the structure of a cell supports its function.

例外情况确实存在,例如病毒无细胞结构,在大多数定义下被视为非生命体。但 A-Level 试题很少要求你争论这一点;相反,重点在于理解细胞结构如何支持其功能。


2. Prokaryotic vs Eukaryotic Cells | 原核细胞与真核细胞

One of the most frequently tested distinctions in CIE Biology is the difference between prokaryotic and eukaryotic cells. Prokaryotic cells, such as bacteria, lack a true nucleus and membrane-bound organelles. Eukaryotic cells, found in plants, animals and fungi, possess a membrane-bound nucleus and many specialised organelles.

CIE 生物考试中最常考的区别之一就是原核细胞与真核细胞的差异。原核细胞(如细菌)没有真正的细胞核和膜包围的细胞器;而真核细胞存在于植物、动物和真菌中,具有膜包围的细胞核和多种特化细胞器。

Feature Prokaryotic 原核细胞 Eukaryotic 真核细胞
Nucleus Absent; DNA free in cytoplasm Present; enclosed by nuclear envelope
Membrane-bound organelles Absent Present
Ribosomes 70S (smaller) 80S in cytoplasm; 70S in mitochondria & chloroplasts
Cell wall Peptidoglycan (murein) Cellulose in plants; chitin in fungi; absent in animals
Typical size 0.5 – 5 μm 10 – 100 μm
DNA arrangement Circular DNA; no histones Linear DNA associated with histone proteins

In addition, prokaryotic cells divide by binary fission, while eukaryotic cells divide by mitosis or meiosis. Prokaryotes may also possess plasmids — small circles of DNA that carry additional genes, such as antibiotic resistance.

此外,原核细胞通过二分裂进行增殖,而真核细胞通过有丝分裂或减数分裂增殖。原核细胞还可能含有质粒——携带额外基因(如抗生素抗性基因)的小型环状 DNA。


3. Key Organelles and Their Functions | 关键细胞器及其功能

Each organelle in a eukaryotic cell has a specific role. The CIE syllabus tests both the structure and function of organelles, and you must be able to link the two. Below are the most important organelles for the examination.

真核细胞中的每种细胞器都有特定功能。CIE 考纲考查细胞器的结构与功能,并且要求你能够将二者联系起来。以下是考试中最重要的一些细胞器。

You should also remember the plant-specific structures: a cell wall made of cellulose for structural support, and a large central vacuole for turgor pressure and storage.

你还应记住植物特有的结构:由纤维素构成的细胞壁以提供结构支撑,以及用于维持膨压和储存物质的大型中央液泡。


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4. Light Microscopy | 光学显微镜技术

solution limit of approximately 200 nm (0.2 μm). This means that two objects closer than 200 nm cannot be distinguished as separate structures under the LM.

光学显微镜利用可见光和玻璃透镜放大标本。其最高放大倍率约为 ×1500,分辨率极限约为 200 nm(0.2 μm)。这意味着在光学显微镜下,相距小于 200 nm 的两个物体无法被分辨为独立结构。

Common exam question: explain why organelles such as ribosomes cannot be seen with a light microscope. The answer must state that ribosomes are smaller than the resolution limit of 200 nm and therefore cannot be resolved as separate structures.

常见考题:解释为什么核糖体等细胞器无法用光学显微镜观察到。答案必须指出:核糖体小于光学显微镜 200 nm 的分辨率极限,因此无法被分辨为独立结构。


5. Electron Microscopy | 电子显微镜技术

Electron microscopes use a beam of electrons instead of visible light. Electrons have a much shorter wavelength, enabling far higher resolution. There are two main types you need to know for CIE A-Level Biology.

电子显微镜使用电子束代替可见光。电子的波长比可见光短得多,因此能够实现高得多的分辨率。CIE A-Level 生物考试要求你掌握两种主要类型。

Both types of electron microscope operate in a vacuum, so specimens must be fixed, dehydrated and coated with heavy metal stains. Consequently

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