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Determining Critical Regions in Poisson Distribution Tests | 泊松分布检验中临界区域的确定方法

2026-08-30 12:21 · 本文部分内容由AI辅助创作

📚 Determining Critical Regions in Poisson Distribution Tests | 泊松分布检验中临界区域的确定方法

In a hypothesis test, the critical region (also called the rejection region) is the set of all values of the test statistic for which the null hypothesis H₀ is rejected. For a Poisson distribution X ~ Po(λ), where X is a discrete count variable, the critical region is always a set of integers at the lower end, the upper end, or both ends of the distribution. Mastering how to locate this region is an essential skill for Edexcel A-Level Further Mathematics.

在假设检验中,临界区域(又称拒绝域)是使得检验统计量落于其中时我们拒绝原假设 H₀ 的所有取值集合。对于泊松分布 X ~ Po(λ),由于 X 是离散型计数变量,临界区域总是位于分布低端、高端或两端的整数集合。熟练确定临界区域是 Edexcel 进阶数学考试中的核心技能。


1. Setting Up Hypotheses for a Poisson Test | 泊松检验假设的建立

has increased, giving H₀: λ = λ₀ against H₁: λ > λ₀. A two-tailed test examines whether the mean has changed in either direction, giving H₀: λ = λ₀ against H₁: λ ≠ λ₀.

在确定临界区域之前,我们必须正式写出假设。泊松均值记为 λ,检验有三种标准形式。单尾下限检验考察均值是否减小,即 H₀: λ = λ₀ 对 H₁: λ < λ₀。单尾上限检验考察均值是否增大,即 H₀: λ = λ₀ 对 H₁: λ > λ₀。双尾检验考察均值是否朝任一方向变化,即 H₀: λ = λ₀ 对 H₁: λ ≠ λ₀。

The significance level α (usually 5% or 1%) is the maximum probability of wrongly rejecting H₀ when it is true. Because the Poisson distribution is discrete, the actual probability of falling in the critical region is often less than α; we state this actual significance level when drawing conclusions.

显著性水平 α(通常取 5% 或 1%)是在 H₀ 为真时错误拒绝 H₀ 的最大概率。由于泊松分布是离散的,实际落入临界区域的概率往往小于 α;在作结论时需要说明实际显著性水平。


2. Finding a Lower-Tail Critical Region | 下尾临界区域的确定

while the cumulative probability remains no greater than α; the last such x is the critical value c.

对于显著性水平为 α 的下尾检验,我们要找最大的整数 c,使得 P(X ≤ c) ≤ α。此时临界区域为 X ≤ c。操作方法是从 x = 0 开始向上扫描累积概率 P(X ≤ x):只要累积概率仍不超过 α 就继续增大 x;最后一个满足条件的 x 即为临界值 c。

Example. Let X ~ Po(3), and test H₀: λ = 3 against H₁: λ < 3 at the 5% gion is X = 0. If we observe X = 0, we reject H₀ and conclude that the mean has decreased.

例。设 X ~ Po(3),在 5% 显著性水平下检验 H₀: λ = 3 对 H₁: λ < 3。比较 P(X ≤ 0) = e⁻³ ≈ 0.0498 ≤ 0.05,而 P(X ≤ 1) = 0.1991 > 0.05。因此 c = 0,临界区域为 X = 0。若观测到 X = 0,则拒绝 H₀,认为均值确实减小了。


3. Finding an Upper-Tail Critical Region | 上尾临界区域的确定

from large x until the cumulative probability first falls below 1 − α; the value just above is c − 1, and hence c is found.

对于上尾检验,我们要找最小的整数 c,使得 P(X ≥ c) ≤ α。由于泊松累积表给出的是 P(X ≤ x),我们利用恒等式 P(X ≥ c) = 1 − P(X ≤ c − 1)。因此需要找满足 P(X ≤ c − 1) ≥ 1 − α 的最小 c。实际操作中,从较大的 x 向下扫描 P(X ≤ x),直到累积概率首次低于 1 − α;前一个值就是 c − 1,从而确定 c。

Example. Let X ~ Po(3), test H₀: λ = 3 against H₁: λ > 3 at the 5% egion is X ≥ 7, and the actual significance level is P(X ≥ 7) = 1 − 0.9665 = 0.0335 = 3.35%.

例。设 X ~ Po(3),在 5% 显著性水平下检验 H₀: λ = 3 对 H₁: λ > 3。需要 P(X ≤ c − 1) ≥ 0.95。查表得 P(X ≤ 6) = 0.9665 ≥ 0.95,但 P(X ≤ 5) = 0.9161 < 0.95。因此 c − 1 = 6,即 c = 7。临界区域为 X ≥ 7,实际显著性水平为 P(X ≥ 7) = 1 − 0.9665 = 0.0335 = 3.35%。


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4. Two-Tailed Critical Regions | 双尾临界区域的确定

c₂) ≤ α/2, i.e. P(X ≤ c₂ − 1) ≥ 1 − α/2. The overall critical region is X ≤ c₁ or X ≥ c₂.

在双尾检验中,显著性水平被均分为两部分:每条尾巴各得 α/2。我们需要找到下临界值 c₁ 使得 P(X ≤ c₁) ≤ α/2,以及上临界值 c₂ 使得 P(X ≥ c₂) ≤ α/2,即 P(X ≤ c₂ − 1) ≥ 1 − α/2。总临界区域为 X ≤ c₁ 或 X ≥ c₂。

r critical region exists; similarly for the upper tail. In that case the two-tailed test effectively becomes one-sided in the opposite direction. You must still report this honestly in your conclusion.

一个重要的细节是:某一条尾可能根本不存在临界值。如果连 P(X = 0) 都大于 α/2,那么就没有下尾临界区域;上尾同理。此时双尾检验实际上只在另一个方向有效,在结论中必须如实说明这一点。


5. Worked Example — Lower-Tail Test | 完整例题——下尾检验

batch is λ = 4. A quality-control manager suspects the number has decreased. Test at the 5% significance level.

某商店声称每批次的次品均数为 λ = 4。质量控制经理怀疑次品数已经减少。在 5% 显著性水平下进行检验。

Let X be the number of defects per batch, with X ~ λ < 4. Since this is a one-tailed lower test, we seek the largest c with P(X ≤ c) ≤ 0.05.

设 X 为每批次次品数,X ~ Po(λ)。建立假设 H₀: λ = 4,H₁: λ < 4。由于这是单尾下限检验,我们找满足 P(X ≤ c) ≤ 0.05 的最大 c。

P(X ≤ 0) = 0.0183 ≤ 0.05, but P(X ≤ 1) = 0.0916 > 0.05

The cumulative probabilities for λ = 4 are shown below.

λ = 4 的累积概率如下表所示。

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