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Core Methods for Probability Calculations in A-Level Mathematics | A-Level 数学:概率计算的核心方法

2026-08-30 11:55 · 本文部分内容由AI辅助创作

📚 Core Methods for Probability Calculations in A-Level Mathematics | A-Level 数学:概率计算的核心方法

Probability is a central topic in A-Level Mathematics, requiring a clear understanding of definitions, rules, and counting techniques. This article presents the core methods you need to solve probability questions reliably and efficiently.

概率是 A-Level 数学的核心主题,要求清晰理解定义、规则和计数技巧。本文整理了在考试中稳定、高效求解概率问题所需的核心方法。


1. Basic Definitions and Axioms of Probability | 概率的基本定义与公理

Probability measures how likely an event is to occur. For any event A, the probability P(A) satisfies: 0 ≤ P(A) ≤ 1. The sum of probabilities of all mutually exclusive and exhaustive outcomes in a sample space is 1.

概率衡量事件发生的可能性。对任意事件 A,概率 P(A) 满足:0 ≤ P(A) ≤ 1。样本空间中所有互斥且穷尽的结果的概率之和为 1。

For equally likely outcomes: P(A) = |A||S|

对于等可能结果:P(A) = |A||S|


2. Sample Space and Events | 样本空间与事件

The sample space S is the set of all possible outcomes of a random experiment. An event is a subset of the sample space. Representing the sample space clearly is often the first step in solving a probability problem.

样本空间 S 是随机试验所有可能结果的集合。事件是样本空间的子集。清晰地表示样本空间通常是解决概率问题的第一步。

Example: Tossing two fair coins has sample space {HH, HT, TH, TT}. The event "at least one head" is {HH, HT, TH}.

例如:抛两枚均匀硬币的样本空间为 {HH, HT, TH, TT}。事件“至少一个正面”为 {HH, HT, TH}。


3. Complement and Addition Rules | 互补法则与加法法则

The complement of event A, written A', is the set of outcomes not in A. The complement rule states P(A') = 1 - P(A). The addition rule connects the probability of a union with the probabilities of the individual events and their intersection.

事件 A 的补事件记为 A',是不在 A 中的结果集合。互补法则指出 P(A') = 1 - P(A)。加法法则将并事件的概率与各事件及其交的概率联系起来。

Addition rule: P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

加法法则:P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

At least one: P(at least one) = 1 - P(none)

至少一个:P(至少一个) = 1 - P(一个也没有)


4. Conditional Probability | 条件概率

Conditional probability measures the probability of one event given that another event has occurred. It is written P(A|B), read as "probability of A given B".

条件概率衡量在已知另一个事件发生的情况下某一事件发生的概率。记作 P(A|B),读作“在 B 条件下 A 的概率”。

P(A|B) = P(A ∩ B)P(B), provided P(B)>0

P(A|B) = P(A ∩ B)P(B),前提是 P(B)>0

Example: In a class of 30 students, 18 study physics and 12 study both physics and mathematics. Given that a randomly chosen student studies physics, the probability they also study mathematics is 12/18 = 2/3.

例如:一个班有 30 名学生,其中 18 人学习物理,12 人同时学习物理和数学。已知随机选出的学生学物理,则他也学数学的概率是 12/18 = 2/3。


5. Multiplication Rule and Independent Events | 乘法法则与独立事件

The multiplication rule is derived from the definition of conditional probability. It allows us to find the probability of an intersection by multiplying conditional probabilities.

乘法法则由条件概率的定义推导而来。它通过相乘条件概率来求交事件的概率。

P(A ∩ B) = P(A)P(B|A) = P(B)P(A|B)

P(A ∩ B) = P(A)P(B|A) = P(B)P(A|B)

Two events A and B are independent if the occurrence of one does not affect the probability of the other. In that case, P(A|B)=P(A) and the multiplication rule simplifies.

两个事件 A 和 B 独立,是指一个事件的发生不影响另一个事件发生的概率。此时 P(A|B)=P(A),乘法法则简化为:

Independent events: P(A ∩ B) = P(A)P(B)

独立事件:P(A ∩ B) = P(A)P(B)


6. Tree Diagrams and Systematic Listing | 树状图与系统列举

Tree diagrams are powerful tools for multi-stage probability problems. Each branch represents a possible outcome, and the probability written on each branch is usually a conditional probability.

树状图是处理多阶段概率问题的强大工具。每条分支代表一个可能结果,分支上标注的概率通常是条件概率。

Example: A bag contains 3 red and 5 blue balls. Two balls are drawn without replacement. The probability that both are red is 38 × 27 = 328.

例如:一个袋子中有 3 个红球和 5 个蓝球。不放回地抽取两个球。两个球都是红球的概率是 38 × 27 = 328。


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7. Permutations and Combinations in Probability | 排列与组合在概率计算中的应用

For equally likely outcomes, counting the number of favorable outcomes and the total number of outcomes is essential. Permutations count ordered arrangements, while combinations count unordered selections.

对于等可能结果,计算有利结果数和总结果数至关重要。排列计数有序排列,组合计数无序选取。

nPr = n!(n-r)!, nCr = binomnr = n!r!(n-r)!

nPr = n!(n-r)!,nCr = binomnr = n!r!(n-r)!

Example: From 6 boys and 4 girls, choose 3 students at random. The probability that all chosen are boys is 6C3⁄10C3 = 20120 = 16.

例如:从 6 名男生和 4 名女生中随机选 3 人。选出的全是男生的概率是 6C3⁄10C3 = 20120 = 16。


8. Law of Total Probability | 全概率公式

The law of total probability allows us to calculate the probability of an event B by splitting the sample space into mutually exclusive parts. If A1, A2, …, An form a partition of the sample space, then for any event B:

全概率公式通过将样本空间划分为互斥部分来计算事件 B 的概率。如果 A1, A2, …, An 构成样本空间的一个划分,则对任意事件 B:

P(B) = P(A1)P(B|A1) + P(A2)P(B|A2) + ⋯ + P(An)P(B|An)

P(B) = P(A1)P(B|A1) + P(A2)P(B|A2) + ⋯ + P(An)P(B|An)

Example: Two machines produce items. Machine A produces 60% of items and has a 2% defect rate; Machine B produces the rest with a 5% defect rate. The overall defect probability is 0.6 × 0.02 + 0.4 × 0.05 = 0.032.

例如:两台机器生产零件。机器 A 生产 60% 的零件,次品率为 2%;机器 B 生产其余零件,次品率为 5%。总次品概率为 0.6 × 0.02 + 0.4 × 0.05 = 0.032。


9. Bayes' Theorem | 贝叶斯定理

Bayes' theorem is used to reverse the direction of conditioning. It tells us the posterior probability P(Ai|B) after observing B, based on prior probabilities and likelihoods.

贝叶斯定理用于逆转条件的方向。它在观察到 B 之后,基于先验概率和似然给出后验概率 P(Ai|B)。

P(Ai|B) = P(Ai)P(B|Ai)⁄P(B), where P(B) is found by the law of total probability

P(Ai|B) = P(Ai)P(B|Ai)⁄P(B),其中 P(B) 由全概率公式求得

Example: In the previous machine example, if an item is defective, the probability it came from machine A is 0.6 × 0.020.032 = 0.375.

例如:在前面的机器例子中,如果零件是次品,它来自机器 A 的概率是 0.6 × 0.020.032 = 0.375。


10. Random Variables and Expectation | 随机变量与期望

In many probability problems, we assign numerical values to outcomes. A random variable X maps outcomes to numbers, and its probability distribution lists each value x with its probability P(X=x).

在许多概率问题中,我们为结果赋予数值。随机变量 X 将结果映射为数值,其概率分布列出每个取值 x 及其概率 P(X=x)。

Example: For a fair die, E(X) = 16(1+2+3+4+5+6) = 3.5.

例如:对于公平骰子,E(X) = 16(1+2+3+4+5+6) = 3.5。

Key formulas: E(aX+b)=aE(X)+b, Var(aX+b)=a2Var(X)

关键公式:E(aX+b)=aE(X)+b,Var(aX+b)=a2Var(X)


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