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Mastering the AQA AS Physics Unit 3 Insert (June 2019) | 掌握AQA AS物理第3单元考试附页(2019年6月)

2026-08-30 08:07 · 本文部分内容由AI辅助创作

📚 Mastering the AQA AS Physics Unit 3 Insert (June 2019) | 掌握AQA AS物理第3单元考试附页(2019年6月)

The AQA AS Physics Insert is an official data and formula booklet provided in the exam, designed to support you when solving numerical and analytical problems. This guide breaks down the key sections of the June 2019 Unit 3 insert, explains how to use each constant and equation correctly, and highlights common mistakes to avoid.

AQA AS物理考试附页是官方提供的数据与公式手册,旨在帮助您在解答数值计算与分析题时快速查找所需常量与方程。本指南分模块解读2019年6月第3单元附页中的关键内容,教您如何正确使用其中每个常量与公式,并指出常见易错点。


1. Overview of the Insert | 附页概览

The insert is an A5 booklet containing SI prefixes, fundamental constants, and the equations you are expected to recall or apply. It is not a substitute for understanding physics, but it saves time and reduces memory burden.

附页是小册子,包含SI词头、基本物理常量以及要求您记忆或应用的公式。它不能代替对物理的理解,但可以节省时间、减轻记忆负担。


2. Key Physical Constants | 核心物理常量

The table below lists the most frequently used constants from the June 2019 insert. These values are given to three or four significant figures.

下表列出了2019年6月附页中最常用的常量。这些数值通常给出三到四位有效数字。

Symbol | 符号Value | 数值Typical use | 典型用途
g9.81 N kg⁻¹Weight, gravitational PE | 重力、重力势能
e1.60 × 10⁻¹⁹ CCharge on an electron | 电子电荷
c3.00 × 10⁸ m s⁻¹Speed of electromagnetic waves | 电磁波速度
h6.63 × 10⁻³⁴ J sPhoton energy, de Broglie wavelength | 光子能量、德布罗意波长
mₑ9.11 × 10⁻³¹ kgElectron mass | 电子质量
mₚ1.67 × 10⁻²⁷ kgProton mass | 质子质量
k8.99 × 10⁹ N m² C⁻²Coulomb’s law | 库仑定律
Nₐ6.02 × 10²³ mol⁻¹Avogadro constant | 阿伏伽德罗常量

Always quote constants from the insert rather than from memory; the exam may use slightly different values.

务必优先引用附页中的常量值,避免凭记忆带入与试卷不一致的数据。


3. Mechanics and Materials Equations | 力学与材料方程

The insert provides equations for uniform acceleration, Newton’s laws, and material properties. Master these before tackling past papers.

附页提供匀加速运动、牛顿定律和材料性质的方程。在练习真题前,请先熟记这些内容。

v = u + at, s = ut + ½at², v² = u² + 2as

For materials, the key equations are Hooke’s law and Young modulus.

对于材料问题,核心方程是胡克定律和杨氏模量。

F = kΔL, σ = F/A, ε = ΔL/L, E = σ/ε = FL/(AΔL)


4. Waves Formulae | 波动公式

Wave questions appear frequently in AQA AS Unit 3. The insert includes the wave speed equation and the diffraction grating equation.

波动问题在AQA AS第3单元中频繁出现。附页中包含波速方程和衍射光栅方程。

v = fλ, nλ = d sin θ

Also remember the refractive index definition:

还需记住折射率定义:

n = c/v = sin i / sin r


5. Electrical and Quantum Formulae | 电学与量子公式

Direct current circuits and quantum phenomena form a major part of the AS course. The insert supplies all essential relations.

直流电路和量子现象是AS课程的重要组成部分。附页提供了所有必要关系式。

V = IR, P = VI = I²R = V²/R

For capacitors and the photoelectric effect, the insert gives:

对于电容器和光电效应,附页给出:

Q = It, E = hf = hc/λ, hf = φ + KE_max


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6. Using the Insert Effectively in Calculations | 在计算中有效使用附页

The insert should be used as a reference, not as a magic book. Efficient use involves knowing exactly which equation to select.

附页应作为参考资料使用,而不是魔法书。高效使用意味着准确选择所需的方程。

Follow this four-step strategy:

请遵循四步策略:


7. Common Pitfalls and How to Avoid Them | 常见误区及避免方法

Many students lose marks not because of difficult mathematics but because of simple mistakes with units and symbols.

许多学生丢分不是因为数学难,而是因为单位与符号的简单错误。

Always write down the equation from the insert before substituting numbers; this earns method marks even if the arithmetic goes wrong.

在代入数据前,务必先从附页中写出方程;即使计算有误,也能获得方法分。


8. Worked Example Based on June 2019 Insert | 基于2019年6月附页的例题

Let’s apply the insert to a typical AS question: "A photon of wavelength 550 nm is incident on a metal surface with work function 2.10 eV. Calculate the maximum kinetic energy of an emitted electron."

我们用一个典型AS题目应用附页:“波长为550 nm的光子照射逸出功为2.10 eV的金属表面。计算发射电子的最大动能。”

First, use the equation from the insert:

首先,使用附页中的方程:

E = hc/λ and KE_max = E – φ

Convert λ to metres: 550 nm = 5.50 × 10⁻⁷ m.

将λ换算为米:550 nm = 5.50 × 10⁻⁷ m。

Then E = (6.63 × 10⁻³⁴ × 3.00 × 10⁸) / (5.50 × 10⁻⁷) = 3.62 × 10⁻¹⁹ J.

然后E = (6.63 × 10⁻³⁴ × 3.00 × 10⁸) / (5.50 × 10⁻⁷) = 3.62 × 10⁻¹⁹ J。

Convert φ to joules: 2.10 × 1.60 × 10⁻¹⁹ = 3.36 × 10⁻¹⁹ J.

将φ换算为焦耳:2.10 × 1.60 × 10⁻¹⁹ = 3.36 × 10⁻¹⁹ J。

Therefore KE_max = 3.62 × 10⁻¹⁹ – 3.36 × 10⁻¹⁹ = 2.60 × 10⁻²⁰ J.

因此KE_max = 3.62 × 10⁻¹⁹ – 3.36 × 10⁻¹⁹ = 2.60 × 10⁻²⁰ J。

This demonstrates how two simple insert equations combine to solve a multi-step problem.

这展示了两个简单附页方程如何组合来解决多步骤问题。


9. Revision Strategies | 复习策略

To master the insert, you must familiarise yourself with every equation before the exam. Do not open the insert for the first time on exam day.

要掌握附页,您必须在考试前熟悉每一个方程。不要在考试当天才第一次翻开附页。


10. Conclusion | 结论

The AQA AS Physics Unit 3 insert is a powerful tool. If you understand its content and practice using it under exam conditions, you will improve both speed and accuracy significantly.

AQA AS物理第3单元附页是一个强力工具。如果您理解其内容并在考试条件下练习使用,速度和准确度都会显著提高。

Always rely on the insert for constants and equations, but combine it with clear written reasoning and correct unit conversions. Good luck with your revision!

始终依赖附页获取常量与方程,同时配合清晰的书面推导和正确的单位换算。祝你复习顺利!

Published by TutorHao | Physics Revision Series | aleveler.com

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