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AS AQA Physics Unit 2 Past Paper (Jan 2019) Analysis | AS AQA 物理 Unit 2 真题解析(2019年1月)

2026-08-30 08:04 · 本文部分内容由AI辅助创作

📚 AS AQA Physics Unit 2 Past Paper (Jan 2019) Analysis | AS AQA 物理 Unit 2 真题解析(2019年1月)

The January 2019 AQA AS Physics Unit 2 paper focused exclusively on the electricity topic, testing candidates on current–potential difference graphs, resistivity, circuit analysis, potential dividers, and electromotive force with internal resistance. This article provides a systematic breakdown of every core concept examined in that paper, with worked examples and common pitfalls highlighted.

2019年1月AQA AS物理Unit 2试卷聚焦电学专题,全面考查了电流–电势差图像、电阻率、电路分析、分压器以及电动势与内阻等内容。本文将系统拆解该试卷涉及的全部核心概念,附有计算示例并指出常见失分点。


1. Paper Overview and Key Themes | 试卷概览与核心考点

The Jan 2019 paper consisted of two sections: Section A contained approximately 10 multiple-choice questions testing basic definitions and simple calculations, while Section B featured structured questions requiring extended written answers and multi-step calculations. Topics were weighted towards circuit analysis (about 40% of marks), followed by I-V characteristics (25%), resistivity (20%), and potential divider/internal resistance problems (15%).

2019年1月试卷包含两部分:A部分约10道选择题,考查基础定义与简单计算;B部分为结构化问答题,需要书面论述与多步计算。各考点分值分布为:电路分析约占40%,I-V特性曲线占25%,电阻率占20%,分压器与内阻问题占15%。

nd were comfortable rearranging equations such as ρ = RA/L and ε = I(R + r). The examiners' ource of lost marks was the incorrect handling of parallel resistors in combined circuits.

高分考生展现了熟练的单位换算能力,尤其是横截面积在mm²与m²之间的转换,并能灵活变形ρ = RA/L和ε = I(R + r)等公式。考官报告指出,最常见的失分原因是在混合电路中错误处理并联电阻。


2. Current, Charge and Potential Difference | 电流、电荷与电势差

s equivalent to one coulomb per second. In the January paper, a multiple-choice question asked candidates to identify the correct unit of current from a list of derived units — the correct answer being C s⁻¹ expressed as A.

电流定义为电荷流动的速率。公式I = ΔQ/Δt表明1安培等于每秒1库仑。1月试卷中有一道选择题要求从导出单位中识别电流的单位,正确答案是以C s⁻¹(即A)表示的安培。

1 J C⁻¹. A short-answer question required students to explain why the potential difference across a resistor is the same as the energy transferred per unit charge by the battery when no other components are present.

电势差V = W/Q是单位电荷在电路中两点间移动时所做的功,单位为伏特(V),1 V = 1 J C⁻¹。一道简答题要求学生解释当电路中无其他元件时,电阻两端的电势差为何等于电池单位电荷所转移的能量。

I = ΔQ/Δt   |   V = W/Q

Conventional current flows from positive to negative, which is opposite to the direction of electron flow. This distinction was tested directly in a true/false statement about electron movement in metallic conductors. Remember: charge is conserved, which leads directly to Kirchhoff's first law discussed later.

传统电流方向由正极流向负极,与电子流动方向相反。这一区别直接出现在关于金属导体中电子运动的判断题中。请记住:电荷守恒直接引出了后文将讨论的基尔霍夫第一定律。


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