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Quadratic Functions & Equations: Complete IGCSE Guide | 二次函数与二次方程:IGCSE 完整指南

2026-08-30 05:26 · 本文部分内容由AI辅助创作

📚 Quadratic Functions & Equations: Complete IGCSE Guide | 二次函数与二次方程:IGCSE 完整指南

Quadratic functions and equations form a cornerstone of the IGCSE Mathematics syllabus. This guide provides a comprehensive, exam-focused walkthrough of everything you need to know — from factorisation and the quadratic formula to graphing and word problems.

二次函数与二次方程是 IGCSE 数学考纲的核心内容。本指南将带你系统梳理所有必考知识点——从因式分解、求根公式到图像绘制与应用题,一网打尽。


1. What Is a Quadratic Expression? | 什么是二次表达式?

A quadratic expression is a polynomial of degree 2, meaning the highest power of the variable is 2. Its general form is written as:

二次表达式是次数为 2 的多项式,即变量的最高次幂为 2。它的一般形式写作:

ax² + bx + c = 0, where a ≠ 0

Here, a, b, and c are constants, and a must not be zero — if a ssion becomes linear. For example, 3x² + 5x − 2 = 0 is quadratic, while 2x + 7 = 0 is not.

其中 a、b、c 为常数,且 a 不能为零——若 a = 0,则表达式变为一次式。例如,3x² + 5x − 2 = 0 是二次方程,而 2x + 7 = 0 则不是。


2. Standard Form vs. Vertex Form | 标准形式与顶点形式

ula. The vertex form y = a(x − h)² + k directly reveals the turning point of the parabola.

二次函数有两种重要形式。标准形式 y = ax² + bx + c 便于确定 y 截距并应用求根公式;顶点形式 y = a(x − h)² + k 则能直接显示出抛物线的顶点。

Form / 形式 Equation / 方程 Key Feature / 关键特征
Standard 标准 y = ax² + bx + c y-intercept at (0, c)
Vertex 顶点 y = a(x − h)² + k Vertex at (h, k)

The vertex form is especially powerful when sketching graphs: if a > 0, the parabola opens upward with a minimum at (h, k); if a < 0, it opens downward with a maximum at (h, k).

顶点形式在画图时尤为强大:若 a > 0,抛物线开口向上,在 (h, k) 处取得最小值;若 a < 0,抛物线开口向下,在 (h, k) 处取得最大值。


3. Solving by Factorisation | 因式分解法求解

Factorisation is often the fastest method when the quadratic has simple integer roots. The goal is to rewrite ax² + bx + c as the product of two brackets, then set each bracket to zero.

当二次方程存在简单的整数根时,因式分解往往是最快的方法。目标是将 ax² + bx + c 改写为两个括号相乘的形式,然后令每个括号分别等于零。

Example / 示例: Solve x² − 5x + 6 = 0 by factorisation.

We look for two numbers that multiply to give +6 and add to give −5. These numbers are −2 and −3. Therefore:

我们寻找两个数,它们相乘为 +6,相加为 −5。这两个数是 −2 和 −3。因此:

(x − 2)(x − 3) = 0

each factor to zero gives x = 2 or x = 3. Always expand your brackets to check the answer.

令每个因式等于零,得到 x = 2 或 x = 3。务必展开括号验证答案是否正确。


4. The Quadratic Formula | 求根公式

solution method. For any quadratic equation ax² + bx + c = 0, the solutions are given by:

当因式分解困难或无法进行时,求根公式提供了一种通用的解法。对于任意二次方程 ax² + bx + c = 0,其解由以下公式给出:

x = (−b ± √b² − 4ac) / 2a

Example / 示例: Solve 2x² − 4x − 3 = 0 using the quadratic formula.

Here a = 2, b = −4, c = −3. Substituting into the formula:

这里 a = 2,b = −4,c = −3。代入公式:

x = (4 ± √16 + 24) / 4 = (4 ± √40) / 4

Simplifying: x = (4 ± 2√10) / 4 = 1 ± √10 / 2. This gives two irrational roots.

化简得:x = (4 ± 2√10) / 4 = 1 ± √10 / 2,得到两个无理数根。


5. Completing the Square | 配方法

Completing the square transforms a quadratic into vertex form, making it easy to identify maximum and minimum points. The process begins by halving the coefficient of x.

配方法将二次式转化为顶点形式,从而轻松确定最大值和最小值。该过程首先需要将 x 的系数除以 2。

Example / 示例: Write x² + 6x + 5 in the form (x + p)² + q.

f 6 is 3, so we write (x + 3)². Since (x + 3)² = x² + 6x + 9, we subtract 9 to compensate:

6 的一半是 3,因此我们写出 (x + 3)²。由于 (x + 3)² = x² + 6x + 9,减去 9 以作补偿:

x² + 6x + 5 = (x + 3)² − 9 + 5 = (x + 3)² − 4

This tells us the vertex is at (−3, −4), and the minimum value of the function is −4.

由此可知顶点坐标为 (−3, −4),函数的最小值为 −4。


6. The Discriminant | 判别式

ac, determines the number and nature of roots without solving the equation. It reveals whether the roots are real, equal, or unreal.

判别式,记作 Δ = b² − 4ac,无需解方程即可判断根的个数与性质。它能揭示根是实数、相等还是虚数。

Example / 示例: Determine the nature of roots for 3x² − 2x + 5 = 0.

Here Δ = (−2)² − 4 × 3 × 5 = 4 − 60 = −56 < 0, so the equation has no real roots.

此处 Δ = (−2)² − 4 × 3 × 5 = 4 − 60 = −56 < 0,因此方程没有实数根。


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7. Sketching Quadratic Graphs | 绘制二次函数图像

To sketch a quadratic graph accurately, you need to find the key features: the roots, the y-intercept, and the vertex. Follow these steps:

要准确绘制二次函数图像,需要找出关键特征点:根、y 截距和顶点。请按以下步骤操作:

  1. Find the y-intercept by substituting x = 0.

    代入 x = 0 求 y 截距。

  2. Find the roots by setting y = 0, using factorisation or the quadratic formula.

    令 y = 0,通过因式分解或求根公式求根。

  3. Find the vertex using x = −b / 2a, then substitute back to find y.

    用 x = −b / 2a 求顶点的 x 坐标,再代回原式求 y 坐标。

  4. Plot the points and draw a smooth curve.

    标出这些点并绘制平滑曲线。

Vertex x-coordinate: x = −b / 2a

Remember: when a > 0 the parabola has a U-shape; when a < 0 it has an inverted U-shape.

注意:当 a > 0 时抛物线呈 U 形;当 a < 0 时呈倒 U 形。


8. Quadratic Inequalities | 二次不等式

Solving quadratic inequalities extends the concept of solving equations. After finding the roots, you use a number line or the graph to determine the range of x that satisfies the inequality.

解二次不等式是方程求解的延伸。在找到根之后,借助数轴或函数图像来确定满足不等式的 x 取值范围。

Example / 示例: Solve x² − x − 6 > 0.

3 and x = −2. Sketching the parabola shows it lies above the x-axis when x < −2 or x > 3.

首先因式分解:(x − 3)(x + 2) > 0。根为 x = 3 和 x = −2。绘制抛物线可知:当 x < −2 或 x > 3 时,函数图像在 x 轴上方。

Solution: x < −2 or x > 3

If the inequality is ≥ 0, we include the roots: x ≤ −2 or x ≥ 3.

若不等式为 ≥ 0,则需包含根:x ≤ −2 或 x ≥ 3。


9. Applications in Word Problems | 应用题中的二次函数

Quadratic equations appear frequently in real-world contexts, from projectile motion to area optimisation. The key is to translate the problem into a quadratic equation and then solve it using the most appropriate method.

二次方程在现实场景中频繁出现,从抛体运动到面积优化问题。关键在于将实际问题转化为二次方程,然后使用最合适的方法求解。

Example / 示例: A rectangle has an area of 40 m². Its length is 3 m longer than its width. Find the dimensions.

示例:一个长方形的面积为 40 平方米。其长比宽多 3 米。求其尺寸。

Let the width be x. Then the length is (x + 3), and the area equation is:

设宽为 x,则长为 (x + 3),面积方程为:

x(x + 3) = 40 → x² + 3x − 40 = 0

0, so x = 5 (rejecting x = −8, as length cannot be negative). The rectangle is 5 m by 8 m.

因式分解得 (x + 8)(x − 5) = 0,所以 x = 5(舍去 x = −8,因为长度不能为负)。该长方形宽 5 米、长 8 米。


10. Exam Tips and Common Mistakes | 考试技巧与常见错误

Avoiding common pitfalls is essential for maximising your marks. Here are the most frequent errors students make:

避免常见陷阱对于最大化得分至关重要。以下是学生最常犯的错误:

Always check your solutions by substituting them back into the original equation. In GDC-supported exams, use your graphic calculator to verify the graph matches your algebraic answer.

始终将解代回原方程进行验证。在允许使用图形计算器的考试中,可用计算器绘制图像来确认代数答案与图形一致。


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