← 返回资讯屏轩教育 · 行业资讯

Solving Quadratic Equations | 解二次方程

2026-08-30 04:59 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 解二次方程

Quadratic equations are one of the most important topics in IGCSE Mathematics. You will encounter them in algebra, coordinate geometry, and problem-solving questions across both Papers 1 and 2. Mastering the different methods of solving quadratics will give you a strong foundation for higher-level mathematics.

二次方程是 IGCSE 数学中最重要的主题之一。你会在代数、坐标几何以及试卷 1 和试卷 2 的应用题中遇到它们。掌握解二次方程的不同方法,将为你的高阶数学学习打下坚实的基础。


1. What Is a Quadratic Equation? | 什么是二次方程

A quadratic equation is a polynomial equation of degree 2, meaning the highest power of the variable is 2. Its standard form is:

二次方程是最高次数为 2 的多项式方程,意味着变量的最高次幂是 2。它的标准形式是:

ax² + bx + c = 0, where a ≠ 0

comes linear. The values of x that satisfy the equation are called the roots or solutions of the equation. A quadratic equation can have at most two real roots.

其中 a、b、c 是常数,且 a 不能为零。如果 a = 0,方程就变成了一次方程。满足方程的 x 值称为方程的根或解。一个二次方程最多可以有两个实数根。


2. Solving by Factorisation | 因式分解法

1, we find two numbers that multiply to give c and add to give b. For the general form ax² + bx + c, we look for two numbers that multiply to give ac and add to give b.

当二次方程具有简单的整数根时,因式分解是最快的方法。当 a = 1 时,我们找到两个数相乘等于 c、相加等于 b。对于一般形式 ax² + bx + c,我们需要找到两个数相乘等于 ac、相加等于 b。

need two numbers that multiply to 6 and add to -5. These numbers are -2 and -3. Therefore:

例如,解 x² - 5x + 6 = 0。我们需要两个数相乘等于 6、相加等于 -5。这两个数是 -2 和 -3。因此:

(x - 2)(x - 3) = 0

or x = 3. Always check your answers by substituting them back into the original equation.

根据零乘积性质,要么 x - 2 = 0,要么 x - 3 = 0。因此 x = 2 或 x = 3。记得将解代回原方程进行验算。


3. Difference of Two Squares | 平方差

mely useful when solving equations of the form x² - k = 0, where k is a positive constant.

一个特殊的因式分解情况是平方差公式:a² - b² = (a - b)(a + b)。这在解 x² - k = 0(k 为正数)形式的方程时非常有用。

For example, solve x² - 9 = 0. Since 9 = 3², we can write:

例如,解 x² - 9 = 0。因为 9 = 3²,我们可以写成:

(x - 3)(x + 3) = 0

Thus, x = 3 or x = -3. Notice that for x² = k where k > 0, the solutions are x = √k and x = -√k. Do not forget the negative root!

因此,x = 3 或 x = -3。注意对于 x² = k(k > 0),解为 x = √k 和 x = -√k。千万不要忘记负根!


4. Completing the Square | 配方法

Completing the square is a technique that works for any quadratic equation, even when factorisation is not possible. For an expression x² + bx, we add and subtract (b/2)² to form a perfect square.

配方法是一种适用于任何二次方程的技巧,即使在无法因式分解时也能使用。对于表达式 x² + bx,我们通过加上和减去 (b/2)² 来构造一个完全平方。

Example: solve x² + 6x + 8 = 0. First, rewrite the first two terms:

例:解 x² + 6x + 8 = 0。首先重写前两项:

x² + 6x = (x + 3)² - 9

implifies to (x + 3)² - 1 = 0. Hence (x + 3)² = 1, so x + 3 = ±1, giving x = -2 or x = -4.

因此方程变为 (x + 3)² - 9 + 8 = 0,化简为 (x + 3)² - 1 = 0。所以 (x + 3)² = 1,x + 3 = ±1,得到 x = -2 或 x = -4。

first divide through by a before completing the square. The result can be written in the form a(x - h)² + k, which is also useful for graph sketching.

对于一般的二次方程 ax² + bx + c = 0,先除以 a 再进行配方。结果可写成 a(x - h)² + k 的形式,这对画图也非常有用。


5. The Quadratic Formula | 二次公式

tic equation. It is derived by completing the square on the general form ax² + bx + c = 0.

二次公式是一种通用方法,可以解任何二次方程。它是通过对一般形式 ax² + bx + c = 0 配方推导得出的。

x = (-b ± √b² - 4ac) / 2a

ula. For example, solve 2x² - 4x - 6 = 0. Here, a = 2, b = -4, c = -6. Substituting gives:

只需将 a、b、c 的值代入公式即可。例如,解 2x² - 4x - 6 = 0。这里 a = 2,b = -4,c = -6。代入得:

x = (4 ± √16 + 48) / 4 = (4 ± √64) / 4 = (4 ± 8) / 4

. The formula works for every quadratic equation, but be careful with negative values of b — substituting into (-b) correctly is a common source of errors.

因此,x = (4 + 8)/4 = 3 或 x = (4 - 8)/4 = -1。公式适用于所有二次方程,但代入负数 b 时要特别小心——正确计算 (-b) 是常见的易错点。


广告 / Sponsored

6. The Discriminant | 判别式

ac, tells us the nature of the roots without solving the full equation. It is the part under the square root in the quadratic formula.

判别式,记作 Δ = b² - 4ac,可以帮助我们在不完全解方程的情况下判断根的性质。它是二次公式中根号下的部分。

o it has no real roots. Its graph never crosses the x-axis. In exam questions, the phrases "equal roots", "real roots", and "no real roots" directly correspond to these three cases.

例如,方程 x² + 4x + 5 = 0 的判别式 Δ = 16 - 20 = -4 < 0,所以它没有实数根。其图像不与 x 轴相交。考试中 "等根"、"实数根"、"无实数根" 等表述分别对应这三种情况。


7. Graphical Solutions | 图像解法

s of its graph y = ax² + bx + c. The graph is a parabola with a vertical axis of symmetry.

二次方程的根对应其图像 y = ax² + bx + c 的 x 截距。该图像是抛物线,具有竖直的对称轴。

is given by x = -b/(2a), and the axis of symmetry is the vertical line through that point.

顶点(转向点)可以通过配方法找到:y = a(x - h)² + k 的顶点为 (h, k)。另外,顶点坐标的 x 值可以用 x = -b/(2a) 计算,对称轴就是经过该点的竖直线。

If a > 0, the parabola opens upwards and the vertex is a minimum point; if a < 0, it opens downwards and the vertex is a maximum point. This is often tested alongside inequality questions.

如果 a > 0,抛物线开口向上,顶点是最小值点;如果 a < 0,开口向下,顶点是最大值点。这一点经常与不等式问题结合考查。


8. Word Problems | 应用题

Many exam questions require you to form and solve a quadratic equation from a given context. For example: "The area of a rectangle is 20 cm². Its length is 4 cm more than its width. Find the width."

许多考试题目要求你从给定情境中建立并求解二次方程。例如:"一个矩形的面积是 20 平方厘米。它的长比宽多 4 厘米。求宽。"

Let the width be x cm. Then the length is (x + 4) cm. The area gives:

设宽为 x 厘米。则长为 (x + 4) 厘米。由面积得:

x(x + 4) = 20 → x² + 4x - 20 = 0

Using the quadratic formula:

使用二次公式:

x = (-4 ± √16 + 80) / 2 = (-4 ± √96) / 2 = (-4 ± 4√6) / 2 = -2 ± 2√6

Since the width must be positive, x = -2 + 2√6 utions when the context requires positive values, and state the final answer with the correct unit.

由于宽度必须为正数,所以 x = -2 + 2√6 ≈ 2.90 厘米。如果题意要求正值,必须舍去负数解,并带上正确单位写出最终答案。


9. Common Mistakes and Exam Tips | 常见错误与考试建议

By mastering these five methods — factorisation, difference of two squares, completing the square, the quadratic formula, and the discriminant — you will be well-prepared for any quadratic equation question on your IGCSE exam.

通过掌握这五种方法——因式分解、平方差、配方法、二次公式和判别式——你将能够从容应对 IGCSE 考试中任何关于二次方程的题目。


Published by TutorHao | Mathematics Revision Series | aleveler.com

广告 / Sponsored
【现货】剑桥国际高中教材 Cambridge IGCSE & O Level Additional Mathemati…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥198.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao