← 返回资讯屏轩教育 · 行业资讯

The Sine and Cosine Rules: Solving Triangles | 正弦定理与余弦定理:解三角形

2026-08-30 04:48 · 本文部分内容由AI辅助创作

📚 The Sine and Cosine Rules: Solving Triangles | 正弦定理与余弦定理:解三角形

Trigonometry is a key topic in IGCSE Mathematics, and the sine rule and cosine rule are two powerful formulas used to solve non-right-angled triangles. Once you know when and how to apply them, many exam questions become straightforward.

三角学是 IGCSE 数学中的重点内容。正弦定理与余弦定理是解非直角三角形的两大有力工具。只要掌握它们的适用条件和正确用法,很多考试题都会变得简单明了。

1. What Are the Two Rules? | 两大定理是什么

The sine rule connects a side to the sine of its opposite angle. The cosine rule connects a side to the other two sides and the included angle. Both rules work for any triangle, not just a right-angled triangle.

正弦定理将一条边与其对角的正弦值联系起来;余弦定理则将一条边与另外两条边及其夹角联系起来。两大定理对任意三角形都适用,不限于直角三角形。


2. The Sine Rule: Formula | 正弦定理:公式

For any triangle ABC, label sides a, b and c so that side a is opposite angle A, side b is opposite angle B, and side c is opposite angle C. The sine rule states that the ratio of each side to the sine of its opposite angle is constant.

对任意三角形 ABC,设边 a 与角 A 相对,边 b 与角 B 相对,边 c 与角 C 相对。正弦定理说明:每条边与其对角正弦值的比是一个常数。

a / sin A = b / sin B = c / sin C

calculating an angle, it is often easier to use the reciprocal form sin A / a = sin B / b.

这个等式可以通过变形来求缺失的边或角。当需要求角时,使用倒数的形式 sin A / a = sin B / b 通常更为方便。


3. Using the Sine Rule to Find a Side | 用正弦定理求边

and side a = 12 cm. To find side b, write the sine rule in the form b / sin B = a / sin A.

假设在三角形 ABC 中,角 A = 50°,角 B = 72°,边 a = 12 cm。要求边 b,可将正弦定理写成 b / sin B = a / sin A 的形式。

b = 12 × sin 72° ÷ sin 50° = 14.9 cm

Always check that your calculator is in degree mode, not radian mode, before evaluating sine values.

在计算正弦值之前,务必检查计算器处于角度模式(Degree Mode),而不是弧度模式(Radian Mode)。


4. Using the Sine Rule to Find an Angle | 用正弦定理求角

. If b = 15, c = 10 and angle B = 80°, then sin C can be found from c / sin C = b / sin B.

求角时使用倒数形式。若 b = 15,c = 10,角 B = 80°,则由 c / sin C = b / sin B 可求出 sin C。

sin C = 10 × sin 80° ÷ 15 = 0.657

.p.). Remember that the inverse sine function gives a principal value, but another possible angle exists; this leads to the ambiguous case.

因此 C = arcsin(0.657) = 41.0°(精确到一位小数)。注意反三角函数给出一个主值,但还可能存在另一个符合条件的角,这就引出了“两解情况”。


5. The Ambiguous Case | 两解情况

ple, if sin C = 0.657, then C could be 41.0° or 139.0°, because sin(180° − 41°) = sin 41°.

当你已知两边及其中一边对角(SSA)时,正弦定理可能产生两个不同的三角形。例如,若 sin C = 0.657,则 C 可能是 41.0° 或 139.0°,因为 sin(180° − 41°) = sin 41°。


6. The Cosine Rule: Formula | 余弦定理:公式

The cosine rule is used when you have two sides and the included angle (SAS) or three sides (SSS). For a triangle with sides a, b and c, and angle A opposite side a, the rule is as follows.

余弦定理适用于已知两边及其夹角(SAS)或已知三边(SSS)的情形。对于边 a、b、c,角 A 与边 a 相对,规则如下。

a² = b² + c² − 2bc cos A

ng the triangle, you can also write b² = a² + c² − 2ac cos B and c² = a² + b² − 2ab cos C.

通过重新标注三角形,也可写为 b² = a² + c² − 2ac cos B 和 c² = a² + b² − 2ab cos C。


7. Using the Cosine Rule to Find a Side | 用余弦定理求边

se b = 8 cm, c = 11 cm and angle A = 35°. To find side a, substitute into the cosine rule.

设 b = 8 cm,c = 11 cm,角 A = 35°。要求边 a,代入余弦定理即可。

a² = 8² + 11² − 2 × 8 × 11 × cos 35°

a² = 64 + 121 − 144.1 = 40.9

a = √40.9 = 6.39 cm

This method is reliable because the cosine rule always gives a unique value for a side when the included angle is known.

这种方法非常可靠,因为当夹角已知时,余弦定理求边只会得到唯一值。


广告 / Sponsored

8. Using the Cosine Rule to Find an Angle | 用余弦定理求角

Rearrange the cosine rule to make cos A the subject. This form is useful when all three sides are known.

将余弦定理变形,用其他量表示 cos A。当三边都已知时,这个形式非常有用。

cos A = (b² + c² − a²) ÷ (2bc)

9, c = 12. Then cos A = (9² + 12² − 7²) ÷ (2 × 9 × 12) = 176 ÷ 216 = 0.8148, so A = 35.4°.

例:a = 7,b = 9,c = 12。则 cos A = (9² + 12² − 7²) ÷ (2 × 9 × 12) = 176 ÷ 216 = 0.8148,因此 A = 35.4°。

The inverse cosine function gives a unique angle between 0° and 180°, so there is no ambiguous case with the cosine rule.

反余弦函数在 0° 到 180° 之间给出唯一角,因此余弦定理不存在两解情况。


9. Area of a Triangle Using Trigonometry | 用三角函数求三角形面积

For any triangle, if you know two sides and the included angle, the area can be found using the formula below. This is especially useful in non-right-angled triangles where the perpendicular height is not given.

对任意三角形,若已知两边及其夹角,可用下面这个公式求面积。对于没有给出垂直高度的非直角三角形,这个公式尤其方便。

Area = ½ ab sin C

Here, a and b are two sides, and C is the angle between them. Make sure the angle is measured in degrees, and give your final answer in square units.

其中 a 和 b 是两条边,C 是它们的夹角。确保角度使用度数表示,最终答案要使用适当的面积单位。


10. Which Rule Should I Use? | 如何选择合适定理

Exam questions often require you to identify the most efficient method. The table below summarises the choice based on the information given.

考试题目经常要求你判断最有效的解题方法。下表总结了根据已知条件应如何选择。

Given Information Rule to Use
Two angles and one side (ASA or AAS) Sine Rule
Two sides and a non-included angle (SSA) Sine Rule, check ambiguous case
Two sides and the included angle (SAS) Cosine Rule for the third side
All three sides (SSS) Cosine Rule for an angle

11. Worked Example: Mixed Problem | 综合例题

A triangular garden has sides 8 m, 11 m and 14 m. Find the largest angle and the area of the garden. The largest angle is opposite the longest side, which is 14 m.

一块三角形花园的三边长分别为 8 m、11 m 和 14 m。求最大角以及花园面积。最大角对着最长边 14 m。

cos A = (8² + 11² − 14²) ÷ (2 × 8 × 11) = (64 + 121 − 196) ÷ 176 = −11 ÷ 176 = −0.0625

A = cos⁻¹(−0.0625) = 93.6°

× 8 × 11 × sin 93.6° ≈ 43.9 m². The largest angle is 93.6°, so this is an obtuse triangle.

求面积时,用两边及其夹角:Area = ½ × 8 × 11 × sin 93.6° ≈ 43.9 m²。最大角为 93.6°,因此这是钝角三角形。


12. Common Mistakes and Checklist | 常见错误与检查清单

The most common errors in IGCSE trigonometry questions come from careless use of the calculator or mixing up the formulas. Follow the checklist below to stay accurate.

IGCSE 三角学题目中最常见的错误来自计算器使用不当或混淆公式。请按照下面的清单来确保准确性。

Once you are comfortable with these two rules, solving triangle problems becomes a systematic process. Practice identifying the correct rule quickly, and always sketch the triangle before starting.

当你熟练掌握这两个定理后,解三角形问题将变成一个系统化的过程。练习快速判断应使用的定理,并在做题前先画出三角形草图。

Published by TutorHao | 数学 Revision Series | aleveler.com

广告 / Sponsored
【现货】剑桥国际高中教材 Cambridge IGCSE & O Level Additional Mathemati…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥198.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao