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Solving Quadratic Equations | 二次方程求解

2026-08-30 04:47 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 二次方程求解

Quadratic equations are a central topic in IGCSE Mathematics. Learning to solve them efficiently and understand their graphs is essential for higher-level algebra and many real-world applications.

二次方程是 IGCSE 数学的核心内容。掌握其求解技巧并理解对应图像,对后续代数学习及众多实际应用都至关重要。


1. The Standard Form of a Quadratic Equation | 二次方程的标准形式

A quadratic equation is an equation that can be written in the form ax² + bx + c = 0, where a, b, and c are constants, and a ≠ 0.

二次方程是可以写成 ax² + bx + c = 0 形式的方程,其中 a、b、c 为常数,且 a ≠ 0。

Here, x represents an unknown variable. The highest power of x is 2, which is why the equation is called "quadratic" (from the Latin quadratus, meaning square).

这里 x 表示未知数,其最高次数为 2,因此被称为“二次”(quadratic,源自拉丁语 quadratus,意为“平方”)。

ax² + bx + c = 0, a ≠ 0


2. Solving by Factorisation | 因式分解法

If the quadratic expression can be factorised into two linear factors, we can set each factor equal to zero and solve.

如果二次式可以分解为两个一次因式的乘积,则可令每个因式等于零,从而求出解。

For example, solve x² - 5x + 6 = 0. The factors are (x - 2)(x - 3) = 0, so x = 2 or x = 3.

例如,解 x² - 5x + 6 = 0,因式分解为 (x - 2)(x - 3) = 0,所以 x = 2 或 x = 3。

This method works only when the expression can be factorised over integers or simple rationals.

此方法仅在二次式可以被分解为整数或简单有理数因子时才适用。


3. Solving by Completing the Square | 配方法

Completing the square rewrites ax² + bx + c in the form (x + p)² + q, which can then be solved by taking square roots.

配方法将 ax² + bx + c 改写成 (x + p)² + q 的形式,然后通过开平方求解。

For example, solve x² + 6x + 4 = 0. Half of 6 is 3, so:

例如,解 x² + 6x + 4 = 0,6 的一半是 3,于是:

(x + 3)² - 9 + 4 = 0 → (x + 3)² = 5

Then x + 3 = ±√5, so x = -3 ± √5.

于是 x + 3 = ±√5,所以 x = -3 ± √5。

general quadratic ax² + bx + c = 0, divide by a first if a ≠ 1, then complete the square.

对于一般二次方程 ax² + bx + c = 0,若 a ≠ 1,则先除以 a,再进行配方。


4. The Quadratic Formula | 二次公式

The quadratic formula is a universal method that solves any quadratic equation, whether or not it has simple factors.

二次公式是通用的求解方法,适用于任何二次方程,无论其是否具有简单因子。

x = (-b ± √b² - 4ac) / 2a

For example, solve 2x² - 3x - 1 = 0. Here a = 2, b = -3, c = -1.

例如,解 2x² - 3x - 1 = 0,这里 a = 2,b = -3,c = -1。

x = (3 ± √((-3)² - 4·2·(-1))) / (2·2) = (3 ± √17) / 4

Always use this formula when factorisation is difficult or impossible. Ensure the equation is in the standard form before substituting.

当因式分解困难或无法分解时,始终使用该公式。代入前务必确保方程为标准形式。


5. The Discriminant and Nature of Roots | 判别式与根的性质

The expression b² - 4ac is called the discriminant. It determines the number and type of roots.

表达式 b² - 4ac 称为判别式,它决定了根的个数与类型。

Discriminant 判别式 Nature of roots 根的形态
b² - 4ac > 0 Two distinct real roots 两个不同实数根
b² - 4ac = 0 One repeated real root 一个重根(两个相等实数根)
b² - 4ac < 0 No real roots 没有实数根

If the discriminant is a perfect square and a, b, c are rational, the equation factorises over rationals.

若判别式是完全平方数且 a、b、c 为有理数,则方程可以在有理数范围内因式分解。

6. The Graph of a Quadratic Function | 二次函数的图像

The graph of y = ax² + bx + c is a parabola. Its shape depends on the sign of a.

函数 y = ax² + bx + c 的图像是抛物线,其形状取决于 a 的正负。

The x-coordinate of the vertex is x = -b / 2a. The y-coordinate is found by substituting this x-value into the equation.

顶点的横坐标为 x = -b / 2a,纵坐标通过将该 x 值代入方程求得。


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7. Roots, x-intercepts and the Axis of Symmetry | 根、x 轴交点与对称轴

e the x-intercepts of the graph y = ax² + bx + c. They are also called the zeros or roots.

ax² + bx + c = 0 的解就是图像 y = ax² + bx + c 与 x 轴的交点,也称为零点或根。

The axis of symmetry of the parabola is the vertical line x = -b / 2a. It passes through the vertex and lies halfway between the two roots.

抛物线的对称轴是垂直线 x = -b / 2a,它经过顶点,并位于两个根的正中间。

If the equation has two roots r₁ and r₂, then:

若方程有两个根 r₁ 和 r₂,则:

x = -b / 2a = (r₁ + r₂) / 2

This relationship is useful for quickly finding the vertex or checking the accuracy of factorisation.

这一关系可快速求顶点坐标或检验因式分解是否正确。


8. Solving Quadratic Inequalities | 二次不等式的求解

Quadratic inequalities such as x² - x - 6 < 0 can be solved by sketching the parabola and determining where the graph is below or above the x-axis.

二次不等式(如 x² - x - 6 < 0)可通过画抛物线草图,确定图像在 x 轴下方或上方的区间来求解。

, solve the corresponding equation x² - x - 6 = 0 to get critical points x = -2 and x = 3.

首先解对应方程 x² - x - 6 = 0,得到临界点 x = -2 和 x = 3。

Since the parabola opens upwards (a > 0), the graph is below the x-axis between the roots. Therefore x² - x - 6 < 0 means -2 < x < 3.

因为抛物线开口向上(a > 0),图像在两根之间位于 x 轴下方。所以 x² - x - 6 < 0 的解为 -2 < x < 3。


9. Modelling Real-Life Situations | 实际情境建模

example, the projectile height h after t seconds can be modelled by h = -4.9t² + vt + h₀.

二次方程常出现在物理、经济和几何问题中。例如,抛体在 t 秒后的高度 h 可建模为 h = -4.9t² + vt + h₀。

Example: A rectangular garden has an area of 60 m². Its length is 4 m longer than its width. Let the width be x m, then length is (x + 4) m, so:

例:一块矩形花园面积为 60 平方米,长比宽多 4 米。设宽为 x 米,则长为 (x + 4) 米,于是:

x(x + 4) = 60 → x² + 4x - 60 = 0

y factorisation gives (x + 10)(x - 6) = 0, so x = 6 (since x = -10 is not a valid length).

因式分解得 (x + 10)(x - 6) = 0,故 x = 6(x = -10 不合题意,舍去)。

Always check that the answer makes sense in the context of the problem.

务必检查答案是否符合问题实际意义。


10. Common Mistakes and Exam Tips | 常见错误与应试技巧

Students often lose marks on quadratic questions due to avoidable errors. Here are key tips.

学生在二次方程题目中常因可避免的错误丢分。以下是一些关键提示。

Practising a variety of problems will build speed and confidence. Make sure you know when to use each method.

多做不同类型的题目能提升速度和信心,并确保你知道每种方法适用的时机。


Published by TutorHao | Mathematics Revision Series | aleveler.com

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