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Quadratic Equations and Functions | 二次方程与二次函数

2026-08-30 03:52 · 本文部分内容由AI辅助创作

📚 Quadratic Equations and Functions | 二次方程与二次函数

Quadratic equations and functions form a cornerstone of IGCSE Mathematics. From solving simple equations to analysing parabolic motion, this topic appears in virtually every exam paper and provides the foundation for higher-level study.

二次方程与二次函数是IGCSE数学的核心内容。从求解简单方程到分析抛物线运动,这一主题几乎出现在每一份试卷中,并为更高层次的学习奠定基础。

1. Basic Form | 基本形式

A quadratic equation is a polynomial equation of degree 2, written in the standard form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0. The expression ax² + bx + c is called a quadratic expression.

二次方程是最高次数为2的多项式方程,其标准形式写作 ax² + bx + c = 0,其中 a、b、c 为常数,且 a ≠ 0。表达式 ax² + bx + c 称为二次表达式。

re both quadratic equations. Note that the coefficient of x² must not be zero; otherwise, the equation becomes linear.

例如,2x² + 3x - 5 = 0 和 x² - 4 = 0 都是二次方程。注意 x² 的系数不能为零,否则方程就变成一次方程了。


2. Factorisation Method | 因式分解法

Solving quadratic equations by factorisation relies on the zero product property: if the product of two factors equals zero, then at least one of the factors must be zero.

用因式分解法解二次方程依赖于零积性质:如果两个因式的乘积等于零,那么至少有一个因式必须为零。

3) = 0. Then we set each factor to zero: x + 2 = 0 or x + 3 = 0, giving x = -2 or x = -3.

解 x² + 5x + 6 = 0,我们先进行因式分解:(x + 2)(x + 3) = 0。然后令每个因子为零:x + 2 = 0 或 x + 3 = 0,解得 x = -2 或 x = -3。

fference of two squares, or the sum/product method. For example, a² - b² = (a - b)(a + b).

始终检查二次式是否可以通过提取公因式、平方差公式或和积法进行因式分解。例如,a² - b² = (a - b)(a + b)。


3. Completing the Square | 配方法

Completing the square is a powerful technique that transforms a quadratic expression ax² + bx + c into the form a(x - h)² + k. This form makes it easy to identify the turning point of a parabola.

配方法是一种强大的技巧,它将二次表达式 ax² + bx + c 变换为 a(x - h)² + k 的形式。这种形式便于确定抛物线的顶点。

of 6 (which is 3), square it (giving 9), and rewrite: x² + 6x + 9 - 9 + 2 = (x + 3)² - 7.

以 x² + 6x + 2 为例,取 6 的一半是 3,平方得 9,然后改写:x² + 6x + 9 - 9 + 2 = (x + 3)² - 7。

ctor it out first. For 2x² - 8x + 5: 2(x² - 4x) + 5 = 2[(x - 2)² - 4] + 5 = 2(x - 2)² - 3.

当 x² 的系数不为 1 时,先提出该系数。对于 2x² - 8x + 5:2(x² - 4x) + 5 = 2[(x - 2)² - 4] + 5 = 2(x - 2)² - 3。


4. The Quadratic Formula | 求根公式

adratic formula can solve any quadratic equation ax² + bx + c = 0. The roots are given by:

求根公式可以求解任何二次方程 ax² + bx + c = 0。其根为:

x = (-b ± √b² - 4ac) / 2a

This formula is derived by completing the square on the general form. It works for all quadratics, including those that cannot be factorised with integers.

该公式通过对一般形式配方法推导而来。它适用于所有二次方程,包括那些无法用整数因式分解的方程。

Example: Solve 2x² - 4x - 6 = 0. Here a = 2, b = -4, c = -6. Substituting: x = (4 ± √16 + 48) / 4 = (4 ± √64) / 4 = (4 ± 8) / 4. Thus x = 3 or x = -1.

例:解 2x² - 4x - 6 = 0。这里 a = 2,b = -4,c = -6。代入:x = (4 ± √16 + 48) / 4 = (4 ± √64) / 4 = (4 ± 8) / 4。因此 x = 3 或 x = -1。


5. The Discriminant | 判别式

he discriminant. It determines the nature of the roots without fully solving the equation.

Δ = b² - 4ac 这个表达式称为判别式。它无需完整解方程即可确定根的性质。

xample, for x² + 2x + 5 = 0, Δ = 4 - 20 = -16 < 0, so this equation has no real solutions.

例如,对于 x² + 2x + 5 = 0,Δ = 4 - 20 = -16 < 0,因此该方程没有实数解。


6. Vieta's Formulas | 根与系数的关系

then the sum and product of the roots satisfy simple relationships with the coefficients.

若 α 和 β 是 ax² + bx + c = 0 的根,则两根之和与两根之积与系数之间存在简单关系。

α + β = -b/a, αβ = c/a

These formulas allow us to construct a quadratic equation from given roots, or to find the value of symmetric expressions without computing the roots explicitly.

这些公式允许我们从给定的根构造二次方程,或者在不显式计算根的情况下求对称表达式的值。

uation whose roots are 3 and -2. Sum = 1, product = -6, so the equation is x² - x - 6 = 0.

例:求一个以 3 和 -2 为根的二次方程。两根之和 = 1,两根之积 = -6,因此方程为 x² - x - 6 = 0。


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7. Graphs of Quadratic Functions | 二次函数图像

x² + bx + c is a parabola. When a > 0, the parabola opens upward (U-shaped); when a < 0, it opens downward (∩-shaped).

二次函数 y = ax² + bx + c 的图像是一条抛物线。当 a > 0 时,抛物线开口向上(U形);当 a < 0 时,抛物线开口向下(∩形)。

The graph can intersect the x-axis at zero, one or two points, corresponding to the number of real roots of the quadratic equation.

图像与 x 轴的交点可以有零个、一个或两个,分别对应二次方程实数根的个数。

s of symmetry is x = -b/(2a); and the turning point (vertex) lies on the axis of symmetry.

图像的关键特征:y 截距为 c;x 截距为方程的根;对称轴为 x = -b/(2a);顶点位于对称轴上。


8. Vertex Form | 顶点形式

as y = a(x - h)² + k is in vertex form, where (h, k) is the turning point of the parabola.

二次函数写成 y = a(x - h)² + k 即顶点形式,其中 (h, k) 是抛物线的顶点。

To convert from standard form to vertex form, use completing the square. This is particularly useful in optimisation problems where the maximum or minimum value is required.

从标准形式转换为顶点形式需要使用配方法。这在需要求最大值或最小值的优化问题中特别有用。

horizontally, k shifts it vertically, and a determines the vertical stretch and direction.

注意顶点形式还揭示了基本图像 y = x² 的变换:h 使图像水平平移,k 使图像垂直平移,a 决定纵向伸缩和开口方向。


9. Applications | 实际应用

Quadratic equations model many real-world scenarios, including projectile motion, area optimisation, and parabolic structures.

二次方程建模了许多现实世界场景,包括抛体运动、面积优化和抛物线结构。

g is the acceleration due to gravity, v₀ the initial velocity, and h₀ the initial height.

抛体运动:向上抛出的物体的高度 h 由 h(t) = -½gt² + v₀t + h₀ 给出,其中 g 是重力加速度,v₀ 是初速度,h₀ 是初始高度。

Area optimisation: to find the maximum area of a rectangle with a fixed perimeter, we set up a quadratic function of one variable and find the vertex.

面积优化:要在固定周长下求矩形最大面积,我们建立一个关于一元变量的二次函数并找到其顶点。

Revenue problems: profit and revenue functions often take parabolic forms, allowing businesses to find the optimal selling price.

收入问题:利润和收入函数通常呈抛物线形式,帮助企业找到最优售价。


10. Exam Tips | 考试技巧

In IGCSE examinations, always check whether the question requires exact answers or decimal approximations. State your answer in the requested form.

在IGCSE考试中,务必检查题目要求的是精确答案还是小数近似值。按要求形式写出答案。

Remember that a² - b² = (a - b)(a + b) and other basic factorisation patterns can simplify problems considerably.

记住 a² - b² = (a - b)(a + b) 等基本因式分解模式可以大大简化问题。


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