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Solving Quadratic Equations | 解一元二次方程

2026-08-30 03:37 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 解一元二次方程

Quadratic equations are one of the most important topics in IGCSE Mathematics. They appear in algebra, graphs, geometry, and even real-life problem solving. This guide will take you through every method you need to solve a quadratic equation confidently, step by step.

一元二次方程是 IGCSE 数学中最重要的主题之一。它们出现在代数、图像、几何甚至实际生活问题中。本指南将带你逐步掌握解决一元二次方程所需的每一种方法,让你自信应对考试。


1. What Is a Quadratic Equation? | 什么是一元二次方程

A quadratic equation is a polynomial equation of degree 2. This means the highest power of the variable is 2. The general form is written as:

一元二次方程是次数为 2 的多项式方程,这意味着变量的最高次数是 2。它的一般形式写作:

ax² + bx + c = 0

Here, a, b, and c are constants, and a ≠ 0. If a were zero, the equation would become linear, not quadratic.

其中 a、b、c 是常数,且 a ≠ 0。如果 a 等于零,方程就会变成一次方程,而不是二次方程。

For example, x² - 5x + 6 = 0 is quadratic, while 2x + 3 = 0 is not.

例如,x² - 5x + 6 = 0 是二次方程,而 2x + 3 = 0 不是。


2. Standard Form and Key Features | 标准形式与关键特征

0. This makes it easier to factorise, complete the square, or apply the quadratic formula.

在解任何一元二次方程之前,你应该先将其整理成标准形式 ax² + bx + c = 0。这样更容易进行因式分解、配方或使用求根公式。

Key features of a quadratic expression ax² + bx + c include:

二次表达式 ax² + bx + c 的关键特征包括:

Always check that the equation is in the correct order: x² term first, then x term, then constant.

始终检查方程是否按正确顺序排列:先 x² 项,再 x 项,最后常数项。


3. Solving by Factorisation | 因式分解法

Factorisation is often the quickest method when the quadratic has simple integer factors. The idea is to write ax² + bx + c as a product of two brackets.

当二次方程具有简单的整数因子时,因式分解通常是最快的方法。其核心思想是将 ax² + bx + c 写成两个括号的乘积。

0. We look for two numbers that multiply to 6 and add to -5. These numbers are -2 and -3.

考虑方程 x² - 5x + 6 = 0。我们需要找到两个数,它们相乘等于 6,相加等于 -5。这两个数是 -2 和 -3。

(x - 2)(x - 3) = 0

of two factors is zero, then at least one factor must be zero. So x - 2 = 0 or x - 3 = 0.

如果两个因子的乘积为零,那么至少有一个因子为零。所以 x - 2 = 0 或 x - 3 = 0。

Therefore, the solutions are x = 2 and x = 3.

因此,解为 x = 2 和 x = 3。

numbers that multiply to 6 and add to 7. These are 1 and 6. Then rewrite the middle term:

对于首项系数不为 1 的二次方程,例如 2x² + 7x + 3 = 0,因式分解需要更加小心。将 a 和 c 相乘 (2 × 3 = 6),找到两个数相乘等于 6 且相加等于 7,它们是 1 和 6。然后重写中间项:

2x² + 1x + 6x + 3 = 0

factorise: x(2x + 1) + 3(2x + 1) = 0, giving (2x + 1)(x + 3) = 0. Hence x = -½ or x = -3.

分组并提取公因式:x(2x + 1) + 3(2x + 1) = 0,得到 (2x + 1)(x + 3) = 0。因此 x = -½ 或 x = -3。


4. Solving by Completing the Square | 配方法

s is useful for solving equations that do not factorise easily, and it also helps in sketching graphs.

配方法将二次方程转化为 (x + p)² = q 的形式。这在解不易因式分解的方程时非常有用,也有助于绘制图像。

by halving the coefficient of x, which is 6, to get 3. Write (x + 3)² and subtract 3² = 9:

以方程 x² + 6x + 2 = 0 为例。首先将 x 的系数 6 除以 2,得到 3。写成 (x + 3)²,然后减去 3² = 9:

(x + 3)² - 9 + 2 = 0

Simplify: (x + 3)² - 7 = 0, so (x + 3)² = 7.

化简: (x + 3)² - 7 = 0,所以 (x + 3)² = 7。

Take the square root of both sides: x + 3 = ±√7. Therefore x = -3 ± √7.

两边开平方:x + 3 = ±√7。因此 x = -3 ± √7。

ple, for 2x² - 8x + 5 = 0, divide by 2 to get x² - 4x + 2.5 = 0, then complete the square.

对于 a > 1 的二次方程,先两边除以 a。例如,对于 2x² - 8x + 5 = 0,除以 2 得到 x² - 4x + 2.5 = 0,然后再配方。


5. The Quadratic Formula | 求根公式

ethod that works for any quadratic equation. For ax² + bx + c = 0, the roots are given by:

求根公式是一种适用于任何一元二次方程的通用方法。对于 ax² + bx + c = 0,根由下式给出:

x = (-b ± √b² - 4ac) / 2a

Let's solve 2x² - 3x - 2 = 0 using the formula. Here a = 2, b = -3, c = -2.

让我们用公式解 2x² - 3x - 2 = 0。其中 a = 2,b = -3,c = -2。

First calculate the discriminant b² - 4ac = (-3)² - 4(2)(-2) = 9 + 16 = 25.

首先计算判别式 b² - 4ac = (-3)² - 4(2)(-2) = 9 + 16 = 25。

Then substitute: x = (3 ± √25) / 4 = (3 ± 5) / 4.

然后代入:x = (3 ± √25) / 4 = (3 ± 5) / 4。

(3 + 5)/4 = 2, or x = (3 - 5)/4 = -½. This matches the factorisation result from earlier.

所以 x = (3 + 5)/4 = 2,或 x = (3 - 5)/4 = -½。这与之前的因式分解结果一致。

The formula is especially helpful when factorisation is difficult or impossible, such as when the roots are irrational or complex.

当因式分解困难或无法进行时,例如根为无理数或复数时,这个公式特别有帮助。


6. The Discriminant | 判别式

The expression b² - 4ac inside the quadratic formula is called the discriminant. It tells us how many real roots the quadratic equation has, without solving it fully.

求根公式中的 b² - 4ac 称为判别式。它无需完全解方程,就能告诉我们一元二次方程有多少个实数根。

There are three cases:

有三种情况:

Discriminant Δ = b² - 4ac Number of Real Roots Graph Intersection with x-axis
Δ > 0 Two distinct real roots Two points
Δ = 0 One repeated real root One point (touches)
Δ < 0 No real roots No intersection

判别式 Δ = b² - 4ac

判别式 Δ = b² - 4ac 的三种情况:Δ > 0 表示有两个不同的实数根;Δ = 0 表示有一个重根;Δ < 0 表示没有实数根。

For example, the equation x² + 2x + 5 = 0 has Δ = 4 - 20 = -16, so it has no real roots.

例如,方程 x² + 2x + 5 = 0 的判别式 Δ = 4 - 20 = -16,因此它没有实数根。

Knowing the discriminant also helps you decide which method to use. If Δ is a perfect square, the quadratic factorises neatly.

了解判别式还有助于你决定使用哪种方法。如果 Δ 是完全平方数,则二次方程可以简洁地因式分解。


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7. Solving Word Problems | 应用题求解

Many real-world problems can be modelled by quadratic equations. Common examples include area problems, projectile motion, and number puzzles.

许多现实问题都可以用二次方程建模。常见的例子包括面积问题、抛体运动和数字谜题。

Consider a rectangle whose length is 3 cm longer than its width. If the area is 40 cm², find the width.

考虑一个长方形,其长比宽长 3 cm。如果面积为 40 cm²,求宽。

Let the width be x cm. Then the length is (x + 3) cm. The equation is:

设宽为 x cm,则长为 (x + 3) cm。方程为:

x(x + 3) = 40

Expand: x² + 3x - 40 = 0. Factorise: (x + 8)(x - 5) = 0.

展开:x² + 3x - 40 = 0。因式分解:(x + 8)(x - 5) = 0。

So x = -8 or x = 5. Since a width cannot be negative, the width is 5 cm.

所以 x = -8 或 x = 5。由于宽度不能为负数,所以宽为 5 cm。

Always check whether the solutions make sense in the context of the problem. Negative lengths, times, or counts are usually rejected.

始终检查解在问题情境中是否有意义。负数长度、时间或数量通常会被舍去。


8. Sketching Quadratic Graphs | 二次函数图像

x² + bx + c is a parabola. Understanding its shape and key points helps you solve equations graphically.

二次函数 y = ax² + bx + c 的图像是一条抛物线。理解其形状和关键点有助于用图像法解方程。

The important features are:

重要特征包括:

ertex, complete the square or use the formula x = -b / 2a, then substitute back to find y.

要找到顶点,可以使用配方法或公式 x = -b / 2a,然后代回求 y。

Sketching the graph is a good way to check your algebraic solutions for reasonableness.

绘制图像是检查代数解是否合理的好方法。


9. Common Mistakes | 常见错误

Students often lose marks on quadratic equations due to avoidable mistakes. Here are the most common ones and how to avoid them.

学生通常因为可避免的错误而在一元二次方程上失分。以下是最常见的错误以及如何避免它们。

A reliable way to check your work is to substitute your answers back into the original equation.

检查工作的一种可靠方法是将你的答案代回原方程。


10. Practice Questions | 练习题

Now it's time to apply what you have learned. Try these questions without looking at the solutions, then check your answers.

现在是时候应用你所学的内容了。尝试不看解答做这些题,然后检查你的答案。

  1. Solve x² - 7x + 12 = 0 by factorisation.
  2. 用因式分解法解 x² - 7x + 12 = 0。
  3. Solve 3x² + 5x - 2 = 0 using the quadratic formula.
  4. 用求根公式解 3x² + 5x - 2 = 0。
  5. Solve x² + 2x - 4 = 0 by completing the square. Leave your answer in surd form.
  6. 用配方法解 x² + 2x - 4 = 0。答案保留根号形式。
  7. Find the discriminant of 2x² + 4x + 1 = 0 and state the number of real roots.
  8. 求 2x² + 4x + 1 = 0 的判别式,并说明实数根的个数。
  9. The product of two consecutive positive integers is 56. Find the integers.
  10. 两个连续正整数的乘积是 56。求这两个整数。

Answers: 1) x = 3, x = 4. 2) x = ½, x = -2. 3) x = -1 ± √5. 4) Δ = 8, two real roots. 5) 7 and 8.

答案:1) x = 3,x = 4。2) x = ½,x = -2。3) x = -1 ± √5。4) Δ = 8,两个实数根。5) 7 和 8。

If you make a mistake, review the relevant section and try again. Consistent practice is the key to mastering quadratic equations.

如果你犯了错误,请复习相关章节并再次尝试。坚持练习是掌握一元二次方程的关键。


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