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Solving Quadratic Equations | 解二次方程

2026-08-30 00:48 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 解二次方程

Quadratic equations appear in nearly every IGCSE Mathematics paper. Understanding how to solve them efficiently and accurately is essential for top grades.

二次方程几乎出现在每份IGCSE数学试卷中。理解如何高效且准确地求解它们,是获得高分的关键。


1. Standard Form | 标准形式

A quadratic equation is any equation that can be written in the form ax² + bx + c = 0, where a, b and c are constants and a ≠ 0.

二次方程是任何可以写成 ax² + bx + c = 0 形式的方程,其中 a、b、c 是常数,且 a ≠ 0。

For example, 2x² – atic equation in standard form. Some equations need rearranging before they fit this form.

例如,2x² – 5x + 3 = 0 就是一个标准形式的二次方程。有些方程需要先整理才能变成这种形式。


2. Factorising Quadratics | 二次方程的因式分解

Factorising is the process of writing a quadratic expression as a product of two brackets. For x² + bx + c, find two numbers that multiply to give c and add to give b.

因式分解是把二次表达式写成两个括号相乘的过程。对于 x² + bx + c,需要找到两个数,它们相乘等于 c,相加等于 b。

x + 12. The numbers 3 and 4 multiply to 12 and add to 7, so x² + 7x + 12 = (x + 3)(x + 4).

例如:对 x² + 7x + 12 因式分解。数字 3 和 4 相乘得 12,相加得 7,所以 x² + 7x + 12 = (x + 3)(x + 4)。

volved. For ax² + bx + c, find factors of a × c that add to b, then split the middle term.

当 x² 的系数不是 1 时,过程更复杂。对于 ax² + bx + c,找到 a × c 的因子,使其相加等于 b,然后拆开中间项。


3. Solving by Factoring | 用因式分解求解

he quadratic is factorised, use the zero product property: if AB = 0, then A = 0 or B = 0.

一旦二次式被因式分解,就使用零乘积性质:如果 AB = 0,那么 A = 0 或 B = 0。

Solve x² – 5x + 6 = 0. Factorise to get (x – 2)(x – 3) = 0. Then x – 2 = 0 or x – 3 = 0, giving x = 2 or x = 3.

解 x² – 5x + 6 = 0。因式分解得到 (x – 2)(x – 3) = 0。于是 x – 2 = 0 或 x – 3 = 0,得到 x = 2 或 x = 3。

Always check your solutions by substituting back into the original equation.

务必把解代回原方程进行检查。


4. The Quadratic Formula | 二次公式

The quadratic formula solves any quadratic equation, even when factorising is difficult or impossible.

二次公式可以求解任何二次方程,即使因式分解困难或无法进行时也适用。

x = (−b ± √b² − 4ac) / 2a

This formula is derived from completing the square and is given in the Edexcel formula book, but you must know how to use it.

该公式由配方法推导而来,Edexcel 公式册中会给出,但你必须知道如何使用它。

Example: Solve 2x² + 3x − 2 = 0. Here a = 2, b = 3, c = −2. Substitute into the formula:

例如:解 2x² + 3x − 2 = 0。这里 a = 2, b = 3, c = −2。代入公式:

x = (−3 ± √(3² − 4×2×(−2))) / (2×2) = (−3 ± √25) / 4

So x = (−3 + 5)/4 = 0.5 or x = (−3 − 5)/4 = −2.

所以 x = (−3 + 5)/4 = 0.5 或 x = (−3 − 5)/4 = −2。


5. Completing the Square | 配方法

Completing the square rewrites ax² + bx + c in the form a(x + p)² + q. This is useful for finding turning points and solving equations.

配方法把 ax² + bx + c 改写为 a(x + p)² + q 的形式。这有助于找到顶点并求解方程。

For example, x² + 6x + 2 = (x + 3)² − 9 + 2 = (x + 3)² − 7.

例如,x² + 6x + 2 = (x + 3)² − 9 + 2 = (x + 3)² − 7。

To solve (x + 3)² − 7 = 0, add 7 to both sides, then take the square root:

要解 (x + 3)² − 7 = 0,两边加 7,然后取平方根:

x + 3 = ±√7, so x = −3 ± √7


6. The Discriminant | 判别式

he part under the square root: Δ = b² − 4ac. Its value tells us how many real roots exist.

二次方程的判别式是根号下的部分:Δ = b² − 4ac。它的值告诉我们存在多少个实根。

Value of b² − 4ac Number of real roots Graphical meaning
Positive Two distinct roots Cuts the x-axis twice
Zero One repeated root Touches the x-axis once
Negative No real roots Does not meet the x-axis

判别式的值

实根数量

图形意义

Positive | 正值; Zero | 零; Negative | 负值。这些表格行对应为:两个不同的根/一个重根/无实根;与x轴相交两次/相切一次/不相交。


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7. Graphical Solutions | 图形解法

re the x-coordinates of the points where the graph of y = ax² + bx + c crosses the x-axis.

二次方程 ax² + bx + c = 0 的根,是抛物线 y = ax² + bx + c 与 x 轴交点的横坐标。

To solve a quadratic graphically, draw the curve accurately and read off the x-intercepts. Solutions may be approximate.

用图形法解二次方程时,需要准确画出曲线并读出 x 截距。解可能是近似值。

like x² + 2x − 8 = 0 by plotting y = x² + 2x − 8 and finding where it crosses the x-axis.

你也可以通过绘制 y = x² + 2x − 8 并找到它与 x 轴的交点,来解像 x² + 2x − 8 = 0 这样的方程。


8. Word Problems | 应用题

Many mark-worthy questions involve setting up a quadratic equation from a real-world context. Define your variable carefully.

许多分值较高的问题需要从实际情境中建立二次方程。要仔细定义未知数。

idth, and its area is 40 cm². Let width = x, then length = x + 3. Therefore x(x + 3) = 40.

例如:一个矩形的长比宽多 3 cm,面积为 40 cm²。设宽为 x,则长为 x + 3。因此 x(x + 3) = 40。

x² + 3x − 40 = 0

Factorise: (x + 8)(x − 5) = 0. Since width is positive, x = 5. The length is 8 cm.

因式分解:(x + 8)(x − 5) = 0。因为宽为正数,所以 x = 5。长为 8 cm。


9. Roots and Coefficients | 根与系数

+ bx + c = 0 with roots α and β, the sum of roots is α + β = −b and the product is αβ = c.

对于二次方程 x² + bx + c = 0,若根为 α 和 β,则根之和 α + β = −b,根之积 αβ = c。

This relationship is useful for finding unknown coefficients without solving the equation.

这个关系可用于不解方程而求出未知系数。

en the other root is 12 ÷ 3 = 4. The sum of roots is 3 + 4 = 7, so −k = 7, meaning k = −7.

例如,如果 x² + kx + 12 = 0 的一个根是 3,那么另一个根是 12 ÷ 3 = 4。根之和为 3 + 4 = 7,所以 −k = 7,即 k = −7。


10. Practice Questions | 练习

Work through these questions to test your understanding. Answer each one fully before checking.

完成以下问题来测试你的理解。请先完整作答,再核对。


11. Common Mistakes | 常见错误

Here are frequent errors that lose marks in exams:

以下是在考试中常见的丢分错误:


12. Summary | 总结

You now have four main methods for solving quadratic equations: factorising, the quadratic formula, completing the square, and graphical interpretation. Choose the most efficient method for each question.

你现在掌握了四种解二次方程的主要方法:因式分解、二次公式、配方法和图形解法。根据每道题选择最有效的方法。

Remember to always check the discriminant, verify your solutions, and read word problems carefully. Regular practice is the key to success in IGCSE Mathematics.

记住要始终检查判别式、验证解,并仔细阅读应用题。定期练习是IGCSE数学成功的关键。

Published by TutorHao | Mathematics Revision Series | aleveler.com

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