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Solving Quadratic Equations | 解二次方程

2026-08-30 00:32 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 解二次方程

Quadratic equations appear frequently in the Edexcel IGCSE Mathematics syllabus. In this article, we will explore the main methods for solving them, understand the meaning of the discriminant, and look at real-world applications.

二次方程在 Edexcel IGCSE 数学课程中频繁出现。在本文中,我们将探讨求解二次方程的主要方法,理解判别式的含义,并研究实际应用。


1. What Is a Quadratic Equation? | 什么是二次方程?

c = 0, where a, b and c are constants and a ≠ 0. The highest power of the variable x is 2.

二次方程是形如 ax² + bx + c = 0 的方程,其中 a、b、c 为常数,且 a ≠ 0。变量 x 的最高次数是 2。


2. Solving by Factorisation | 因式分解法

When the quadratic expression can be written as a product of two linear factors, we can solve by setting each factor equal to zero.

当二次表达式可以写成两个一次因式的乘积时,我们可以令每个因式等于零来求解。

Example: Solve x² - 5x + 6 = 0.

例如:解 x² - 5x + 6 = 0。

We factorise: (x - 2)(x - 3) = 0.

我们因式分解:(x - 2)(x - 3) = 0。

Therefore x = 2 or x = 3.

因此 x = 2 或 x = 3。

Steps for factorisation:

因式分解的步骤:

If (px + q)(rx + s) = 0, then x = -q/p or x = -s/r.

如果 (px + q)(rx + s) = 0,那么 x = -q/p 或 x = -s/r。


3. Solving by Taking Square Roots | 平方根法

ear term, i.e. ax² + c = 0, we can solve directly by isolating x² and taking square roots.

如果二次方程没有一次项,即 ax² + c = 0,我们可以直接分离 x² 并取平方根来求解。

Example: Solve 2x² - 8 = 0.

例如:解 2x² - 8 = 0。

Add 8 to both sides: 2x² = 8.

两边加 8:2x² = 8。

Divide by 2: x² = 4.

两边除以 2:x² = 4。

Take square roots: x = ±2.

取平方根:x = ±2。

Remember that the square root of a positive number has two values: one positive and one negative.

记住正数的平方根有两个值:一正一负。

If x² = k (k ≥ 0), then x = ±√k.

如果 x² = k(k ≥ 0),那么 x = ±√k。


4. Completing the Square | 配方法

Completing the square is a powerful technique that rewrites ax² + bx + c in the form a(x - h)² + k. This is especially useful when factorisation is difficult or impossible.

配方法是一种强有力的技巧,可将 ax² + bx + c 改写为 a(x - h)² + k。这在因式分解困难或不可能时特别有用。

For a quadratic x² + bx + c, add and subtract (b/2)².

对于二次式 x² + bx + c,加上并减去 (b/2)²。

Example: Solve x² + 6x + 1 = 0 by completing the square.

例如:用配方法解 x² + 6x + 1 = 0。

Rewrite: x² + 6x = -1.

改写:x² + 6x = -1。

Add (6/2)² = 9 to both sides: x² + 6x + 9 = 8.

两边加上 (6/2)² = 9:x² + 6x + 9 = 8。

Now (x + 3)² = 8, so x + 3 = ±√8.

于是 (x + 3)² = 8,所以 x + 3 = ±√8。

Therefore x = -3 ± 2√2.

因此 x = -3 ± 2√2。

x² + bx + c = (x + b/2)² - (b/2)² + c

x² + bx + c = (x + b/2)² - (b/2)² + c


5. The Quadratic Formula | 二次求根公式

The quadratic formula solves any quadratic equation directly. It is derived from completing the square.

二次求根公式可以直接求解任何二次方程。它通过配方法推导得出。

For ax² + bx + c = 0, x = (-b ± √b² - 4ac) / (2a).

对于 ax² + bx + c = 0,x = (-b ± √b² - 4ac) / (2a)。

Example: Solve 2x² + 3x - 2 = 0.

例如:解 2x² + 3x - 2 = 0。

Here a = 2, b = 3, c = -2.

这里 a = 2,b = 3,c = -2。

Substitute into the formula:

代入公式:

x = (-3 ± √(3² - 4×2×(-2))) / (2×2) = (-3 ± √9 + 16) / 4 = (-3 ± 5) / 4.

x = (-3 ± √(3² - 4×2×(-2))) / (2×2) = (-3 ± √9 + 16) / 4 = (-3 ± 5) / 4。

So x = 2/4 = 1/2 or x = -8/4 = -2.

因此 x = 2/4 = 1/2 或 x = -8/4 = -2。

Always check your substitution signs carefully, especially when c is negative.

代入时务必小心符号,特别是当 c 为负数时。


6. The Discriminant | 判别式

The expression b² - 4ac inside the square root is called the discriminant, often denoted by Δ.

根号中的表达式 b² - 4ac 称为判别式,通常记作 Δ。

It tells us the nature of the roots without solving the equation.

它无需解方程就能告诉我们根的性质。

Δ = b² - 4ac

Δ = b² - 4ac

Example: Determine the nature of the roots of x² - 4x + 4 = 0.

例如:判断 x² - 4x + 4 = 0 的根的性质。

Δ = (-4)² - 4×1×4 = 16 - 16 = 0, so there is one repeated root.

Δ = (-4)² - 4×1×4 = 16 - 16 = 0,所以有一个重根。


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7. Solving Word Problems with Quadratics | 二次方程应用题

Many word problems lead to quadratic equations. The key is to translate the problem into algebraic form and then solve.

许多应用题会导出二次方程。关键是将问题转化为代数形式,然后求解。

Example: The length of a rectangle is 3 cm longer than its width. The area is 40 cm². Find the width.

例如:一个长方形的长比宽长 3 cm,面积为 40 cm²。求宽。

Let the width be x cm. Then length = x + 3 cm.

设宽为 x cm,则长为 x + 3 cm。

Area equation: x(x + 3) = 40.

面积方程:x(x + 3) = 40。

Expanding: x² + 3x - 40 = 0.

展开:x² + 3x - 40 = 0。

Factorising: (x + 8)(x - 5) = 0.

因式分解:(x + 8)(x - 5) = 0。

So x = 5 or x = -8. Since width cannot be negative, x = 5 cm.

所以 x = 5 或 x = -8。由于宽不能为负,x = 5 cm。

Always reject solutions that do not make sense in the context of the problem.

始终舍去在问题情境中无意义的解。


8. Graphs of Quadratic Functions | 二次函数图像

a. The roots of the equation ax² + bx + c = 0 correspond to the x-intercepts of the graph.

y = ax² + bx + c 的图像是一条抛物线。方程 ax² + bx + c = 0 的根对应于图像与 x 轴的交点。

Using the discriminant, we know whether the parabola crosses the x-axis, touches it, or does not meet it at all.

利用判别式,我们可以知道抛物线是与 x 轴相交、相切还是完全不相交。


9. Common Mistakes to Avoid | 常见错误

Students often make errors when solving quadratics. Here are some important points to remember.

学生在求解二次方程时经常犯错。以下是一些需要记住的重要点。


10. Practice Strategies | 练习策略

To master quadratic equations, practice a variety of questions. Start with factorisation, then complete the square, and finally use the formula.

要掌握二次方程,练习多种题型。从因式分解开始,然后配方法,最后使用公式。

Suggested practice plan:

建议练习计划:

Remember to show all steps clearly to avoid careless errors.

记得清楚展示所有步骤,避免粗心错误。


Summary | 总结

Quadratic equations are a central topic in IGCSE Mathematics. You should be able to solve them by factorisation, completing the square, and the quadratic formula. The discriminant helps you determine the number and type of roots without solving fully. Regular practice will build confidence and accuracy.

二次方程是 IGCSE 数学的核心主题。你应该能够通过因式分解、配方法和二次公式来求解它们。判别式可以帮助你在不完全求解的情况下确定根的数量和类型。定期练习将建立信心并提高准确性。

Published by TutorHao | Mathematics Revision Series | aleveler.com

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