← 返回资讯屏轩教育 · 行业资讯

Solving Quadratic Equations: Factorising, Formula and Completing the Square | 解二次方程:因式分解、公式法与配方法

2026-08-30 00:24 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations: Factorising, Formula and Completing the Square | 解二次方程:因式分解、公式法与配方法

Quadratic equations appear in almost every IGCSE Mathematics paper. Whether you are solving them by factorising, using the quadratic formula, or completing the square, a clear step-by-step approach will help you avoid mistakes and gain full marks.

二次方程几乎出现在每一份IGCSE数学试卷中。无论你是通过因式分解、公式法还是配方法来解题,清晰的分步思路都能帮助你避免错误、拿到满分。


1. What Is a Quadratic Equation? | 什么是二次方程

can be written in the form ax² + bx + c = 0, where a, b and c are real numbers and a ≠ 0.

二次方程是未知数最高次数为2的多项式方程,可写成 ax² + bx + c = 0,其中a、b、c为实数,且a ≠ 0。

ax² + bx + c = 0 (a ≠ 0)


2. Standard Form and Rearranging | 标准形式与整理方程

e the equation so that one side is zero. For example, x² = 5x - 6 becomes x² - 5x + 6 = 0.

求解前,一定要将方程整理成一边为零的形式。例如,x² = 5x - 6 应写成 x² - 5x + 6 = 0。

Expanding brackets and collecting like terms are essential skills. Do not try to factorise before the equation is in standard form.

展开括号、合并同类项是基本技能。在方程化为标准形式之前不要急于因式分解。

le: (x - 2)(x + 3) = 4. Expand first, then subtract 4: x² + x - 6 = 4, so x² + x - 10 = 0.

例如:(x - 2)(x + 3) = 4。先展开,然后两边减4:x² + x - 6 = 4,即 x² + x - 10 = 0。


3. Solving by Factorising (when a = 1) | 因式分解法(a=1时)

ly to give c and add to give b. Then write (x + p)(x + q) = 0 and set each factor to zero.

当a = 1时,寻找两个数,使其乘积为c、和为b。然后写成 (x + p)(x + q) = 0,并令每个因式等于零。

ecause (-2) × (-3) = 6 and (-2) + (-3) = -5. So (x - 2)(x - 3) = 0, giving x = 2 or x = 3.

对于 x² - 5x + 6 = 0,两个数是 -2 和 -3,因为 (-2) × (-3) = 6,(-2) + (-3) = -5。所以 (x - 2)(x - 3) = 0,解得 x = 2 或 x = 3。


4. Solving by Factorising (when a ≠ 1) | 因式分解法(a≠1时)

When a ≠ 1, factorising is more challenging. One method is to multiply a and c, find two numbers whose product is ac and sum is b, then split the middle term and factor by grouping.

当a ≠ 1时,因式分解更具挑战性。一种方法是先计算a与c的乘积,找到两个数使它们的积为ac、和为b,然后拆分中间项并分组因式分解。

= 2 × 3 = 6. The numbers are 1 and 6 because 1 × 6 = 6 and 1 + 6 = 7. Split 7x as x + 6x:

例如:2x² + 7x + 3 = 0。这里 ac = 2 × 3 = 6。两个数是1和6,因为1 × 6 = 6,1 + 6 = 7。将7x拆为x + 6x:

2x² + x + 6x + 3 = 0 → x(2x + 1) + 3(2x + 1) = 0 → (x + 3)(2x + 1) = 0

Thus x = -3 or x = -½.

因此 x = -3 或 x = -½。


5. Solving by the Quadratic Formula | 公式法

orks for any quadratic equation, even when factorising is difficult. For ax² + bx + c = 0,

公式法适用于任何二次方程,即使难以因式分解。对于 ax² + bx + c = 0,

x = ( -b ± √b² - 4ac ) / (2a)

Substitute the values of a, b and c. Simplify the square root first, then calculate the two solutions.

代入a、b、c的值。先化简根号,再计算两个解。

Example: 2x² - 4x - 3 = 0. Here a = 2, b = -4, c = -3.

例如:2x² - 4x - 3 = 0,其中 a = 2,b = -4,c = -3。

x = ( 4 ± √16 + 24 ) / 4 = ( 4 ± √40 ) / 4 = ( 4 ± 2√10 ) / 4 = ( 2 ± √10 ) / 2


6. Solving by Completing the Square | 配方法

Completing the square writes a quadratic as a(x + p)² + q. For x² + bx, add and subtract (b/2)².

配方法将二次式写成 a(x + p)² + q 的形式。对于 x² + bx,需要加上并减去 (b/2)²。

2 = 0. Since (6/2)² = 9, rewrite as (x + 3)² - 9 + 2 = 0, so (x + 3)² = 7. Then x + 3 = ±√7, giving x = -3 ± √7.

例如:x² + 6x + 2 = 0。因为 (6/2)² = 9,改写为 (x + 3)² - 9 + 2 = 0,即 (x + 3)² = 7。于是 x + 3 = ±√7,得 x = -3 ± √7。


广告 / Sponsored

7. The Discriminant | 判别式

The expression b² - 4ac is called the discriminant, often denoted by Δ. It tells you how many real roots the quadratic has.

表达式 b² - 4ac 称为判别式,常用 Δ 表示。它告诉我们二次方程有几个实数根。

Discriminant Δ | 判别式 Δ Roots | 根的情况
Δ > 0 Two distinct real roots | 两个不同实数根
Δ = 0 Two equal real roots (a repeated root) | 两个相等实数根(重根)
Δ < 0 No real roots | 无实数根

or example, the equation x² + 2x + 3 = 0 has Δ = 4 - 12 = -8 < 0, so it has no real roots.

例如,方程 x² + 2x + 3 = 0 的 Δ = 4 - 12 = -8 < 0,因此没有实数根。


8. Quadratic Graphs and Roots | 二次函数图像与根

= ax² + bx + c. The graph is a parabola that opens upward if a > 0 and downward if a < 0.

方程 ax² + bx + c = 0 的解就是图像 y = ax² + bx + c 的x轴交点。图像是抛物线:a > 0 时开口向上,a < 0 时开口向下。

x-coordinate of vertex = -b / (2a)


9. Word Problems Using Quadratics | 二次方程应用题

Many IGCSE questions require you to form a quadratic equation from a real-life situation. Common contexts include area, motion, and number problems.

许多IGCSE题目要求你从实际情境中建立二次方程。常见背景包括面积、运动和数字问题。

torising: (x + 10)(x - 7) = 0, so x = -10 (reject) or x = 7. Width = 7 cm, length = 10 cm.

例:一个长方形的长比宽多3 cm,面积为70 cm²。设宽为x,则长为x + 3。因此 x(x + 3) = 70,得 x² + 3x - 70 = 0。因式分解:(x + 10)(x - 7) = 0,所以 x = -10(舍去)或 x = 7。宽=7 cm,长=10 cm。

Always reject negative answers if they do not make sense in the context.

如果负数答案在情境中没有意义,一定要舍去。


10. Common Mistakes and Exam Tips | 常见错误与考试技巧

Below is a list of frequent errors and how to avoid them.

以下是一些常见错误及避免方法。

Exam tip: If a question says “give your answer correct to 3 significant figures”, use the quadratic formula or a calculator rather than factorising.

考试技巧:如果题目要求“答案保留3位有效数字”,应使用公式法或计算器,而不是因式分解。


Published by TutorHao | IGCSE Mathematics Revision Series | aleveler.com

广告 / Sponsored
预售 英国CGP教材 GCSE/IGCSE Catch-Up Essentials:Edexcel Maths Hig…
数学 备考教辅 · 正版现货 · 与本文内容相关
查看详情 / View on Taobao参考价 ¥209.0

更多咨询请联系16621398022(同微信)

备考资讯每日更新,关注不错过
考纲变化 · 科目分析 · 学习方法
扫码关注公众号 tutorhao
在微信里长按二维码识别关注
或截图后用「扫一扫 → 相册」选择本图
公众号:tutorhao