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Quadratic Equations | 二次方程

2026-08-30 00:19 · 本文部分内容由AI辅助创作

📚 Quadratic Equations | 二次方程

Quadratic equations are polynomial equations of degree two. They appear throughout IGCSE Mathematics and in many real-world problems.

二次方程是二次多项式方程,在IGCSE数学以及许多实际问题中经常出现。


1. Standard Form | 标准形式

A quadratic equation in one variable can be written as ax² + bx + c = 0, where a, b, and c are constants and a ≠ 0.

一元二次方程可以写成 ax² + bx + c = 0 的形式,其中 a、b、c 为常数,且 a ≠ 0。

Here are some examples:

以下是一些例子:

Notice that the highest power of x is 2, which makes it quadratic.

注意 x 的最高次数为 2,因此它是二次的。


2. Factorisation Method | 因式分解法

If the quadratic expression can be factorised, we use the zero-product property: if pq = 0, then p = 0 or q = 0.

如果二次多项式可以因式分解,我们利用零乘积性质:若 pq = 0,则 p = 0 或 q = 0。

Follow these steps:

按照以下步骤:


3. Worked Example | 例题详解

Solve the equation x² − 5x + 6 = 0.

解方程 x² − 5x + 6 = 0。

x² − 5x + 6 = 0

Factorise: (x − 2)(x − 3) = 0.

因式分解:(x − 2)(x − 3) = 0。

Using the zero-product property: x − 2 = 0 or x − 3 = 0.

利用零乘积性质:x − 2 = 0 或 x − 3 = 0。

So the solutions are x = 2 or x = 3.

因此解为 x = 2 或 x = 3。


4. The Quadratic Formula | 求根公式

For any quadratic equation ax² + bx + c = 0, the solutions are given by:

对于任意二次方程 ax² + bx + c = 0,解由下式给出:

x = (−b ± √b² − 4ac) / (2a)

This formula works for all quadratics, including those that cannot be factorised easily.

这个公式适用于所有二次方程,包括不容易因式分解的方程。

Be careful with signs and the order of operations.

注意符号和运算顺序。


5. Completing the Square | 配方法

Completing the square rewrites a quadratic in the form a(x + p)² + q, which is useful for solving and graphing.

配方法将二次式改写为 a(x + p)² + q 的形式,这对求解和作图很有用。

For a monic quadratic x² + bx, add (b/2)² to make a perfect square.

对于首项系数为 1 的二次式 x² + bx,加上 (b/2)² 即可配成完全平方。

Example: x² + 6x = (x + 3)² − 9.

例如:x² + 6x = (x + 3)² − 9。


6. The Discriminant | 判别式

The discriminant is Δ = b² − 4ac. It tells us the nature of the roots without solving.

判别式为 Δ = b² − 4ac。它可以帮助我们不解方程就能判断根的性质。

Δ = b² − 4ac Nature of roots | 根的性质
Δ > 0 Two distinct real roots | 两个不相等的实数根
Δ = 0 One repeated root | 两个相等的实数根(重根)
Δ < 0 No real roots | 没有实数根

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7. Solving by Completing the Square | 用配方法解方程

Solve x² + 6x + 2 = 0 by completing the square.

用配方法解 x² + 6x + 2 = 0。

First move the constant: x² + 6x = −2.

首先移常数项:x² + 6x = −2。

Add (6/2)² = 9 to both sides: x² + 6x + 9 = 7.

两边加上 (6/2)² = 9:x² + 6x + 9 = 7。

This gives (x + 3)² = 7.

于是得到 (x + 3)² = 7。

Take square roots: x + 3 = ±√7.

开平方:x + 3 = ±√7。

Hence x = −3 ± √7.

因此 x = −3 ± √7。


8. Word Problems | 应用题

Quadratic equations often arise from geometry or area problems.

二次方程经常在几何或面积问题中出现。

Example: A rectangle's length is 3 cm longer than its width. Its area is 40 cm². Find the dimensions.

例:一个长方形的长比宽长 3 厘米,面积为 40 平方厘米。求长和宽。

Let width = x, then length = x + 3. Since area = 40, we have x(x + 3) = 40.

设宽为 x,则长为 x + 3。由于面积为 40,所以 x(x + 3) = 40。

x² + 3x − 40 = 0, which factorises to (x + 8)(x − 5) = 0.

x² + 3x − 40 = 0,因式分解为 (x + 8)(x − 5) = 0。

Since x > 0, x = 5. The rectangle is 5 cm by 8 cm.

因为 x > 0,所以 x = 5。长方形为 5 厘米 × 8 厘米。


9. Graphical Solutions | 图象解法

tions of ax² + bx + c = 0 correspond to the x-intercepts of the parabola y = ax² + bx + c.

方程 ax² + bx + c = 0 的解对应抛物线 y = ax² + bx + c 与 x 轴的交点。

If the parabola crosses the x-axis at two points, the roots are the x-coordinates of those points.

如果抛物线与 x 轴有两个交点,那么根的值为交点的 x 坐标。

If it touches the axis once, there is one repeated root. If it never crosses, there are no real roots.

如果它与 x 轴相切一次,则有一个重根;如果它从未穿过 x 轴,则没有实数根。


10. Common Mistakes and Tips | 常见错误与提示

Avoid these common pitfalls:

避免以下常见错误:

Always check your solutions by substituting back into the original equation.

始终将解代回原方程进行检验。


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