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Solving Quadratic Equations | 解二次方程

2026-08-30 00:15 · 本文部分内容由AI辅助创作

📚 Solving Quadratic Equations | 解二次方程

his revision guide, we will explore the key methods for solving quadratic equations, understand the discriminant, and apply these skills to real problems.

二次方程是形如 ax² + bx + c = 0 的方程,其中 a ≠ 0。在本复习指南中,我们将探讨解二次方程的主要方法,理解判别式,并将这些技能应用到实际问题中。


1. Standard Form of a Quadratic Equation | 二次方程的标准形式

A quadratic equation always has the highest power of x equal to 2. The general form is:

二次方程的最高次幂始终为 2。其一般形式为:

ax² + bx + c = 0

comes linear. The values of x that satisfy the equation are called the roots or solutions.

这里,a、b 和 c 是常数,且 a ≠ 0。如果 a = 0,方程就变成了一次方程。满足方程的 x 值称为方程的根或解。

For example, rearrange 3x² - 4x = 5 into standard form by subtracting 5 from both sides:

例如,将 3x² - 4x = 5 移项为标准形式:两边同时减去 5:

3x² - 4x - 5 = 0


2. Solving by Factorisation | 因式分解法

the zero product property. If (px + q)(rx + s) = 0, then either px + q = 0 or rx + s = 0.

如果二次方程可以写成两个一次因式的乘积,我们可以利用零乘积性质。若 (px + q)(rx + s) = 0,则要么 px + q = 0,要么 rx + s = 0。

Solve x² - 5x + 6 = 0 by factorisation.

用因式分解法解 x² - 5x + 6 = 0。

We look for two numbers that multiply to 6 and add to -5. These are -2 and -3.

我们需要找到两个数,它们相乘等于 6,相加等于 -5。这两个数是 -2 和 -3。

(x - 2)(x - 3) = 0

Therefore x = 2 or x = 3.

因此 x = 2 或 x = 3。

Always check your answers by substituting back into the original equation.

始终将答案代回原方程进行检验。


3. Completing the Square | 配方法

Completing the square rewrites a quadratic in the form a(x + p)² + q. This is useful when factorisation is difficult or when finding turning points.

配方法将二次式改写为 a(x + p)² + q 的形式。这在因式分解困难或需要求顶点时非常有用。

der x² + 6x + 4 = 0. First, halve the coefficient of x: 6 ÷ 2 = 3. Then square it: 3² = 9.

考虑 x² + 6x + 4 = 0。首先,取 x 系数的一半:6 ÷ 2 = 3。然后平方:3² = 9。

Rewrite the equation as:

将方程改写为:

(x + 3)² - 9 + 4 = 0

(x + 3)² = 5

Take the square root of both sides, remembering the ± sign:

两边开平方,注意 ± 号:

x + 3 = ±√5

x = -3 ± √5


4. The Quadratic Formula | 二次求根公式

olves any quadratic equation, even when factorisation is impossible. For ax² + bx + c = 0:

二次求根公式可以解任何二次方程,即使无法因式分解。对于 ax² + bx + c = 0:

x = (-b ± √b² - 4ac) / (2a)

Use this formula with care. Substitute the values of a, b and c exactly as they appear.

使用此公式时要小心。将 a、b 和 c 的准确值代入。

Solve 2x² + 3x - 5 = 0 using the quadratic formula. Here, a = 2, b = 3, c = -5.

用二次公式解 2x² + 3x - 5 = 0。这里 a = 2,b = 3,c = -5。

x = (-3 ± √(3² - 4 × 2 × (-5))) / (2 × 2)

x = (-3 ± √9 + 40) / 4 = (-3 ± √49) / 4 = (-3 ± 7) / 4

So x = (4) / 4 = 1 or x = (-10) / 4 = -2.5.

因此 x = 4 / 4 = 1 或 x = -10 / 4 = -2.5。


5. The Discriminant b² - 4ac | 判别式 b² - 4ac

ant determines the number and type of roots of a quadratic equation. For ax² + bx + c = 0:

判别式决定二次方程的根的个数和类型。对于 ax² + bx + c = 0:

Value of b² - 4acNumber of real rootsGraphical meaning
b² - 4ac > 0Two distinct real rootsThe curve crosses the x-axis at two points
b² - 4ac = 0One repeated real rootThe curve touches the x-axis at one point
b² - 4ac < 0No real rootsThe curve does not meet the x-axis

the discriminant is (-4)² - 4 × 1 × 4 = 16 - 16 = 0, so there is exactly one root (x = 2).

例如,在 x² - 4x + 4 = 0 中,判别式为 (-4)² - 4 × 1 × 4 = 16 - 16 = 0,因此恰好有一个根(x = 2)。


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6. Quadratic Graphs and Roots | 二次函数图像与根

0 are the x-coordinates where the graph of y = ax² + bx + c crosses or touches the x-axis.

二次方程 ax² + bx + c = 0 的解是函数 y = ax² + bx + c 的图像与 x 轴相交或相切处的 x 坐标。

If a > 0, the parabola opens upwards; if a < 0, it opens downwards. The turning point can be found by completing the square.

若 a > 0,抛物线开口向上;若 a < 0,开口向下。可以通过配方法找到顶点。

1. The vertex is at (2, -1), and the roots are x = 1 and x = 3 because (x - 1)(x - 3) = 0.

对于 y = x² - 4x + 3,配平方得 (x - 2)² - 1。顶点为 (2, -1),根为 x = 1 和 x = 3,因为 (x - 1)(x - 3) = 0。

Sketch the graph by marking the roots, the vertex, and the y-intercept (where x = 0).

画草图时,标出根、顶点和 y 截距(x = 0 处的值)。


7. Problem Solving with Quadratics | 二次方程应用题

Many practical problems lead to quadratic equations. Read the problem carefully, define a variable, form an equation, and solve it.

许多实际问题会导出二次方程。仔细读题,设变量,列方程,再求解。

Example: The length of a rectangle is 4 cm more than its width. Its area is 45 cm². Find the width.

例:一个长方形的长比宽多 4 cm,面积为 45 cm²。求宽。

Let the width be w cm. Then the length is (w + 4) cm. Area = w(w + 4) = 45.

设宽为 w cm,则长为 (w + 4) cm。面积 = w(w + 4) = 45。

w² + 4w - 45 = 0

+ 9)(w - 5) = 0, so w = -9 or w = 5. Since a length cannot be negative, the width is 5 cm.

因式分解:(w + 9)(w - 5) = 0,所以 w = -9 或 w = 5。因为长度不能为负,所以宽为 5 cm。

Always reject solutions that do not make sense in the context.

始终舍去在情境中不合理的解。


8. Common Mistakes and Tips | 常见错误与提示

to zero before applying methods. Also, when taking square roots, do not forget the ± sign.

学生在应用方法之前常常忘记将方程移项为零。此外,开平方时不要忘记 ± 号。

Practise all three methods: factorisation, completing the square, and the quadratic formula. Being fluent in each method gives you flexibility in the exam.

练习所有三种方法:因式分解、配方和二次公式。熟练掌握每种方法能让你在考试中灵活应对。


Published by TutorHao | Mathematics Revision Series | aleveler.com

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