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A-Level Edexcel Maths: Mastering Integration by Substitution | A-Level Edexcel 数学：掌握换元积分法

2026-08-29 18:47 · 本文部分内容由AI辅助创作

📚 A-Level Edexcel Maths: Mastering Integration by Substitution | A-Level Edexcel 数学：掌握换元积分法

Integration by substitution is one of the most powerful techniques in A-Level Edexcel Pure Mathematics. It allows you to transform complicated integrals into simpler standard forms by changing the variable. Mastering this method is essential for both Paper 1 and Paper 2 questions involving integration, trigonometric functions, exponentials, and rational functions.

换元积分法是 A-Level Edexcel 纯数学中最强大的技巧之一。它通过更换变量，把复杂的积分转化为更简单的标准形式。掌握这一方法对于 Paper 1 和 Paper 2 中涉及积分、三角函数、指数函数和有理函数的问题至关重要。

1. What is Integration by Substitution? | 什么是换元积分法？

able. The goal is to reduce a difficult integral to one of the standard forms such as ∫ uⁿ du, ∫ eᵘ du, or ∫ cos u du.

换元积分法是微分中链式法则的逆过程。当被积函数包含一个函数及其导数时，我们可以把内层函数替换为一个新变量 u，用 u 重写积分，先积分，再代回原变量。这样做的目的是把困难的积分化简为标准形式，例如 ∫ uⁿ du、∫ eᵘ du 或 ∫ cos u du。

∫ f(g(x)) g'(x) dx = ∫ f(u) du, where u = g(x)

∫ f(g(x)) g'(x) dx = ∫ f(u) du，其中 u = g(x)

2. Why Substitution Works: Reverse Chain Rule | 为什么换元法有效：反向链式法则

The chain rule states that d/dx [F(g(x))] = F'(g(x)) g'(x). Therefore, integrating both sides gives ∫ F'(g(x)) g'(x) dx = F(g(x)) + C. When we set u = g(x), we have du/dx = g'(x), which can be written as du = g'(x) dx. This transforms the left-hand side into ∫ F'(u) du = F(u) + C.

链式法则指出 d/dx [F(g(x))] = F'(g(x)) g'(x)。因此，对两边积分可得 ∫ F'(g(x)) g'(x) dx = F(g(x)) + C。当我们令 u = g(x) 时，有 du/dx = g'(x)，也可写成 du = g'(x) dx。这样左边就转化为 ∫ F'(u) du = F(u) + C。

This relationship shows that substitution is not a trick, but a direct consequence of reversing differentiation. In exam solutions, you should always state your substitution u, find du/dx, and show the replacement of dx before integrating.

这一关系说明换元法不是一种技巧，而是逆向微分的直接结果。在考试解答中，你应当始终写出换元变量 u，求出 du/dx，并在积分前展示 dx 的替换过程。

3. Choosing the Substitution u | 如何选择换元变量 u

when x appears alongside, u = sin x when cos x is present, and u = ln x when 1/x appears.

寻找一个内层函数，并且它的导数也出现在被积函数中。一个好的换元通常会约掉剩余的 x 项或简化表达式。常见的选择包括：当旁边有 x 时令 u = x² + 1；当有 cos x 时令 u = sin x；当有 1/x 时令 u = ln x。

Always check that after substitution the integral contains only u and du, with no remaining x terms. If x terms remain, either the substitution is incorrect or further algebraic manipulation is needed.

换元后始终要检查积分中是否只包含 u 和 du，没有剩余的 x 项。如果仍有 x 项，说明换元选择不正确，或者还需要进一步的代数处理。

4. Worked Example: Algebraic Substitution | 例题：代数换元

Integrate ∫ x√x² + 1 dx. Let u = x² + 1, so du/dx = 2x, hence dx = du/(2x). The integral becomes ∫ x √u × (du/(2x)) = ½ ∫ u1/2 du = ½ × (2/3) u3/2 + C = ⅓ (x² + 1)3/2 + C.

计算 ∫ x√x² + 1 dx。令 u = x² + 1，则 du/dx = 2x，因此 dx = du/(2x)。积分变为 ∫ x √u × (du/(2x)) = ½ ∫ u1/2 du = ½ × (2/3) u3/2 + C = ⅓ (x² + 1)3/2 + C。

Let u = x² + 1 → du/dx = 2x → dx = du/(2x)

令 u = x² + 1 → du/dx = 2x → dx = du/(2x)

∫ x√x²+1 dx = ½ ∫ √u du = ⅓ u3/2 + C = ⅓ (x²+1)3/2 + C

∫ x√x²+1 dx = ½ ∫ √u du = ⅓ u3/2 + C = ⅓ (x²+1)3/2 + C

Notice that after replacing dx with du/(2x), the x in the numerator cancels with the x in the denominator. This cancellation is the key sign that the substitution is working correctly.

注意，在把 dx 替换为 du/(2x) 后，分子中的 x 与分母中的 x 相互约掉。这种约分是换元选择正确的重要标志。

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5. Definite Integrals and Changing Limits | 定积分与更换积分限

its to match the new variable u. If x = a gives u = g(a) and x = b gives u = g(b), then ∫ab f(g(x)) g'(x) dx = ∫g(a)g(b) f(u) du. Changing limits often saves time and reduces errors.

对于定积分，你有两种选择：代回 x 并使用原来的积分限，或者把积分限换成新变量 u 的值。如果 x = a 对应 u = g(a)，x = b 对应 u = g(b)，那么 ∫ab f(g(x)) g'(x) dx = ∫g(a)g(b) f(u) du。更换积分限通常能节省时间并减少错误。

, u = 1; when x = 1, u = 2. The integral becomes ∫₁² u³ du = [u⁴/4]₁² = 16/4 - 1/4 = 15/4.

例题：计算 ∫₀¹ 2x (x² + 1)³ dx。令 u = x² + 1。则 du/dx = 2x，所以 dx = du/(2x)。当 x = 0 时，u = 1；当 x = 1 时，u = 2。积分变为 ∫₁² u³ du = [u⁴/4]₁² = 16/4 - 1/4 = 15/4。

∫₀¹ 2x (x² + 1)³ dx = ∫₁² u³ du = [u⁴/4]₁² = 15/4

∫₀¹ 2x (x² + 1)³ dx = ∫₁² u³ du = [u⁴/4]₁² = 15/4

If you choose to substitute back to x instead, you must not use the u-limits with an x-expression. This is one of the most common errors in A-Level exams.

如果你选择代回 x，就不能在 x 表达式中使用 u 的积分限。这是 A-Level 考试中最常见的错误之一。

6. Trigonometric Substitutions | 三角换元

, du/dx = cos x, so du = cos x dx. The integral becomes ∫ u² du = u³/3 + C = ⅓ sin³ x + C.

有些积分需要把三角函数作为换元变量。例如，∫ sin² x cos x dx 可以令 u = sin x，du/dx = cos x，因此 du = cos x dx。积分变为 ∫ u² du = u³/3 + C = ⅓ sin³ x + C。

∫ sin² x cos x dx = ⅓ sin³ x + C

∫ sin² x cos x dx = ⅓ sin³ x + C

/dx = cos x for u = sin x, du/dx = -sin x for u = cos x, and du/dx = sec² x for u = tan x.

其他有用的三角换元包括：当 sin x 以奇数次幂出现时令 u = cos x；当出现 sec² x 时令 u = tan x。在 Edexcel A-Level 数学中，最常用的是 u = sin x、u = cos x 或 u = tan x。关键是要匹配导数：u = sin x 时 du/dx = cos x；u = cos x 时 du/dx = -sin x；u = tan x 时 du/dx = sec² x。

7. Common Mistakes and How to Avoid Them | 常见错误与避免方法

Many students forget to rewrite dx in terms of du. Always compute du/dx and isolate dx carefully. Another frequent error is mixing x and u in the same integral; the integrand must be entirely in u after substitution. Also, for definite integrals, remember to change the limits or revert to x before applying original limits.

许多学生忘记把 dx 用 du 表示。一定要先计算 du/dx，并小心地分离出 dx。另一个常见错误是在同一个积分中混用 x 和 u；换元后被积函数必须完全用 u 表示。此外，对于定积分，要记得更换积分限，或者在代回 x 后再使用原来的积分限。

8. Exam-Style Practice Questions | 考试风格练习题

Try these questions to test your understanding of integration by substitution. For each one, identify the substitution u, find du/dx, rewrite the integral, integrate, and substitute back or change limits as appropriate.

尝试以下题目来检验你对换元积分法的理解。每题都要写出换元变量 u，求出 du/dx，重写积分，积分，并根据情况代回原变量或更换积分限。