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Edexcel A Level Maths Practice Set 079: Mixed Pure Topics | 爱德思 A Level 数学练习第079套:纯数混合专题

2026-08-29 17:53 · 本文部分内容由AI辅助创作

📚 Edexcel A Level Maths Practice Set 079: Mixed Pure Topics | 爱德思 A Level 数学练习第079套:纯数混合专题

This set brings together exam-style questions and worked strategies from the high-yield pure mathematics content tested in Edexcel A Level Mathematics Paper 1. Each section pairs a concise explanation with a model example so you can revise the method and then apply it under timed conditions.

本练习第079套汇集了爱德思 A Level 数学卷一纯数部分的高频考点,以考试风格例题配合解题策略。每一节都采用简明讲解与典型示例配对,帮助你先复习方法,再在限时条件下独立应用。


1. Algebraic Simplification and Surds | 代数化简与根式

Surds questions in Edexcel papers usually require rationalising a denominator or simplifying an expression such as (2 + √3)(5 − √3). Always look for the difference of two squares before multiplying out brackets.

爱德思试卷中的根式题通常要求有理化分母,或化简形如 (2 + √3)(5 − √3) 的表达式。展开括号前,始终优先寻找平方差结构。

For example, to rationalise 1/(√5 + √3), multiply the numerator and denominator by the conjugate √5 − √3. The denominator becomes 5 − 3 = 2, so the result is ½(√5 − √3). This technique avoids leaving a surd in the denominator.

例如,要对 1/(√5 + √3) 有理化,可将分子分母同乘共轭根式 √5 − √3。分母变为 5 − 3 = 2,因此结果为 ½(√5 − √3)。这一技巧可以避免分母中保留根式。

1/(√5 + √3) × (√5 − √3)/(√5 − √3) = (√5 − √3)/2


2. Quadratic Discriminant and Inequalities | 二次判别式与不等式

l roots; if Δ = 0 there is exactly one repeated root; if Δ < 0 there are no real roots.

判别式 Δ = b² − 4ac 可以判断二次方程 ax² + bx + c = 0 有多少个实根。若 Δ > 0,则有两个不同实根;若 Δ = 0,则有一个重根;若 Δ < 0,则没有实根。

etch the parabola or use a sign table to identify x < 2 or x > 3 as the solution region.

对于形如 x² − 5x + 6 > 0 的二次不等式,先解方程 x² − 5x + 6 = 0,得到 x = 2 与 x = 3。然后画出抛物线草图或使用符号表,确定解集为 x < 2 或 x > 3。

x² − 5x + 6 > 0 ⇒ (x − 2)(x − 3) > 0 ⇒ x < 2 or x > 3


3. Polynomial Division and Factor Theorem | 多项式除法与因式定理

0. This is often used with polynomial division to factorise cubic or quartic expressions.

因式定理指出,(x − a) 是多项式 f(x) 的因式,当且仅当 f(a) = 0。这通常与多项式除法一起使用,用于对三次或四次表达式进行因式分解。

When dividing f(x) by (x − a), you can use algebraic long division or compare coefficients. The remainder theorem is equally useful: the remainder when f(x) is divided by (x − a) is exactly f(a).

用 (x − a) 除 f(x) 时,可以使用代数长除法或比较系数法。余式定理同样有用:f(x) 除以 (x − a) 的余式恰好是 f(a)。


4. Graphs and Function Transformations | 函数图像与变换

lation 2 units to the left, while y = f(2x) is a horizontal stretch with scale factor 1/2.

你需要识别 y = f(x) 的图像在变换下如何变化。例如,y = f(x + 2) 表示向左平移 2 个单位,而 y = f(2x) 表示水平方向以 1/2 为比例因子进行拉伸。

The modulus graph y = |f(x)| eeps all non-negative parts of f(x) and reflects any negative parts in the x-axis. Solving |x − 3| = 5 means considering both x − 3 = 5 and x − 3 = −5, giving x = 8 or x = −2.

绝对值图像 y = |f(x)| 保留 f(x) 的所有非负部分,并将任何负值部分关于 x 轴反射。求解 |x − 3| = 5 时,需要同时考虑 x − 3 = 5 和 x − 3 = −5,得到 x = 8 或 x = −2。


5. Differentiation Rules and Tangents | 微分法则与切线

posite functions use the chain rule: if y = f(u) and u = g(x), then dy/dx = dy/du × du/dx.

幂法则为:若 y = xⁿ,则 dy/dx = n xⁿ⁻¹。对于复合函数使用链式法则:若 y = f(u) 且 u = g(x),则 dy/dx = dy/du × du/dx。

ent m = dy/dx at that point, then use y − y₁ = m(x − x₁). A normal line has gradient −1/m.

要求 x = a 处的切线方程,先求出该点的斜率 m = dy/dx,再用 y − y₁ = m(x − x₁) 写出方程。法线的斜率为 −1/m。

d/dx [xⁿ] = n xⁿ⁻¹, and d/dx [f(g(x))] = f '(g(x)) g '(x)


6. Integration and Area Under Curves | 积分与曲线下面积

efinite integrals from a to b are written as ∫ₐᵇ f(x) dx and are evaluated as F(b) − F(a).

积分是微分的逆运算。基本法则为 ∫ xⁿ dx = xⁿ⁺¹/(n+1) + c,其中 n ≠ −1。从 a 到 b 的定积分写作 ∫ₐᵇ f(x) dx,计算结果为 F(b) − F(a)。

when f(x) is positive. If the curve crosses the x-axis, split the integral and take absolute values of each region.

当 f(x) 为正时,曲线与 x 轴之间从 x = a 到 x = b 的面积由 ∫ₐᵇ f(x) dx 给出。如果曲线穿过 x 轴,需要拆分积分,并对每一段区域取绝对值。


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7. Trigonometric Equations and Identities | 三角方程与恒等式

Core identities include sin²θ + cos²θ ≡ 1 and tan θ ≡ ese allow you to rewrite equations such as 2cos²θ + cos θ − 1 = 0 as a quadratic in cos θ.

核心恒等式包括 sin²θ + cos²θ ≡ 1 和 tan θ ≡ sin θ / cos θ。这些恒等式可以将 2cos²θ + cos θ − 1 = 0 这样的方程改写为关于 cos θ 的二次方程。

s θ = 1/2 or cos θ = −1, then use the cosine graph or CAST diagram to list every solution.

解三角方程时,必须找出指定区间内的所有解。对于 2cos²θ + cos θ − 1 = 0,解得 cos θ = 1/2 或 cos θ = −1,然后借助余弦图像或 CAST 图列出全部解。


8. Exponentials and Logarithms | 指数与对数

The natural exponential and logarithm are inverses: eˣ and ln x satisfy ln(eˣ) = x and eln x = x. To solve an equation such as e²ˣ = 5, take natural logs to get 2x = ln 5.

自然指数与自然对数互为逆运算:eˣ 与 ln x 满足 ln(eˣ) = x 且 eln x = x。要求解 e²ˣ = 5,可两边取自然对数得到 2x = ln 5。

or expand logarithmic expressions. Exponential growth models are often written as P = P₀ekt.

使用对数法则 ln(ab) = ln a + ln b、ln(a/b) = ln a − ln b 和 ln(aᵏ) = k ln a 来合并或展开对数表达式。指数增长模型通常写作 P = P₀ekt。


9. Sequences and Series | 数列与级数

erms is Sₙ = n/2 (2a + (n − 1)d). Here a is the first term and d is the common difference.

对于等差数列,第 n 项为 uₙ = a + (n − 1)d,前 n 项和为 Sₙ = n/2 (2a + (n − 1)d)。其中 a 为首项,d 为公差。

the nth term is uₙ = arⁿ⁻¹ and the sum of the first n terms is Sₙ = a(1 − rⁿ)/(1 − r). If |r| < 1, the infinite sum converges to S∞ = a/(1 − r).

对于等比数列,第 n 项为 uₙ = arⁿ⁻¹,前 n 项和为 Sₙ = a(1 − rⁿ)/(1 − r)。若 |r| < 1,则无穷级数收敛于 S∞ = a/(1 − r)。


10. Binomial Expansion | 二项展开

For positive integer n, the binomial expansion is (a + b)ⁿ = Σ nCr aⁿ⁻ʳ bʳ, where nCr = n! / [r!(n − r)!. In Edexcel papers you often expand (1 + x)ⁿ for small powers or use the first few terms.

对于正整数 n,二项展开式为 (a + b)ⁿ = Σ nCr aⁿ⁻ʳ bʳ,其中 nCr = n! / [r!(n − r)!]。在爱德思考试中,常对 (1 + x)ⁿ 进行小次数展开,或使用前几项。

For rational n, the expansion (1 + x)ⁿ = 1 + nx + n(n−1)/2! x² + ... is only valid when |x| . You may be asked to state the range of validity or expand an expression like (1 − 2x)⁻¹.

对于有理数 n,展开式 (1 + x)ⁿ = 1 + nx + n(n−1)/2! x² + ... 仅在 |x| < 1 时有效。题目可能要求写出有效范围,或展开 (1 − 2x)⁻¹ 这样的表达式。


11. Vectors in Pure Contexts | 纯数中的向量

ion and distance in two or three dimensions. The magnitude of a vector a = xi + yj + zk is |a| = √x² + y² + z².

在纯数学中,向量用于表示二维或三维空间中的位置、方向和距离。向量 a = xi + yj + zk 的模为 |a| = √x² + y² + z²。

The scalar product a·b = |a||b| rs. If a and b are perpendicular, then a·b = 0. For coordinates, a·b = x₁x₂ + y₁y₂ + z₁z₂.

数量积 a·b = |a||b| cos θ 用于求向量间的夹角。若 a 与 b 垂直,则 a·b = 0。在坐标形式下,a·b = x₁x₂ + y₁y₂ + z₁z₂。


12. Exam Strategy and Common Pitfalls | 考试策略与常见错误

In Edexcel A Level Maths, method marks matter. Always show your working clearly, especially in differentiation, integration and equation solving, so that even a small slip does not lose the entire question.

在爱德思 A Level 数学中,步骤分非常重要。务必清晰写出解题过程,尤其是在微分、积分和方程求解中,这样即使出现小失误也不会丢掉整道题的分数。

Common pitfalls include forgetting the constant of integration +c, missing the validity condition |x| < 1 in binomial expansion, and using degrees instead of radians in calculus. Check exact answers when the question asks for surd or log form.

常见错误包括漏写积分常数 +c、忘记二项展开的有效条件 |x| < 1,以及在微积分中使用角度制而非弧度制。当题目要求根式或对数形式时,应核对是否为精确答案。


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