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Mathematical Proof | 数学证明

2026-08-29 13:34 · 本文部分内容由AI辅助创作

📚 Mathematical Proof | 数学证明

Proof is the logical engine of A Level Mathematics. In Edexcel Pure Mathematics, you are expected not only to use correct algebra but also to justify why a statement must be true, or to show that a statement is false by a single counterexample.

证明是 A Level 数学的逻辑核心。在 Edexcel 纯数学中,你不仅要正确使用代数,还要论证一个命题为什么必然成立,或者通过一个反例说明某个命题不成立。


1. What Is Proof? | 什么是证明

A mathematical proof is a watertight chain of reasoning that starts from known facts, definitions or axioms and leads to the conclusion. Unlike science, where evidence supports a theory, a proof in mathematics establishes truth beyond any doubt.

数学证明是一条严密的推理链:从已知事实、定义或公理出发,推出结论。与科学中用证据支持理论不同,数学证明确立的结论是无可置疑的。

ery case. For example, checking x = 1, 2, 3 does not prove a claim about all real numbers.

在 Edexcel A Level 数学中,证明必须具有一般性。除非定义域是有限的并且你检查了所有情况,否则不能只靠代入几个数值来证明命题。例如,检查 x = 1、2、3 并不能证明关于所有实数的结论。

'For all n ∈ ℕ, n² − n is even' is a general statement.

'对于任意 n ∈ ℕ,n² − n 为偶数' 是一个一般性命题。

There are four main tools you need to know: proof by deduction, proof by exhaustion, proof by contradiction, and disproof by counterexample.

你需要掌握四种主要工具:演绎证明、穷举证明、反证法以及反例证伪。


2. Proof by Deduction | 演绎证明

Proof by deduction starts with known identities or definitions and uses algebra to reach the conclusion. It is the most common method in Pure Mathematics.

演绎证明从已知恒等式或定义出发,通过代数运算得出结论。这是纯数学中最常见的方法。

Example: Prove that the sum of any three consecutive integers is divisible by 3.

例题:证明任意三个连续整数之和能被 3 整除。

d n + 2. Their sum is n + (n + 1) + (n + 2) = 3n + 3 = 3(n + 1), which is a multiple of 3.

设这三个整数为 n、n + 1 和 n + 2。它们的和为 n + (n + 1) + (n + 2) = 3n + 3 = 3(n + 1),这是 3 的倍数。

n + (n + 1) + (n + 2) = 3(n + 1)

ful deduction: if n is even, then n² is divisible by 4. Write n = 2k, so n² = (2k)² = 4k².

另一个常用演绎:若 n 为偶数,则 n² 能被 4 整除。设 n = 2k,则 n² = (2k)² = 4k²。

n = 2k ⇒ n² = 4k²

In a deduction, every step must be a logical consequence of the previous step. Use words such as 'therefore', 'hence' and 'since' to show the flow of reasoning.

在演绎证明中,每一步都必须是前一步的逻辑结果。使用 'therefore'、'hence'、'since' 等词来展示推理过程。


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3. Proof by Exhaustion | 穷举证明

Proof by exhaustion works by checking every possible case in a finite domain. It is valid only if the list of cases is complete and no case is missed.

穷举证明通过检查有限定义域中的每一个可能情况来证明命题。只有当情况列表完整且没有遗漏时才有效。

Example: Prove that for n ∈ {1, 2, 3, 4}, n² + 1 is not divisible by 3.

例题:证明对于 n ∈ {1, 2, 3, 4},n² + 1 不能被 3 整除。

nn² + 1Divisible by 3?
12No
25No
310No
417No

All four possible values are checked, so the statement is proved by exhaustion.

所有四个可能值都已被检查,因此命题通过穷举法得证。

Edexcel questions sometimes ask for exhaustion when there are only a few cases, such as small integers or a limited number of shapes. Make a clear table or list to show every case.

Edexcel 考题有时在只有少数情况时要求使用穷举法,例如较小的整数或有限数量的图形。用清晰的表格或列表列出每一种情况。


4. Disproof by Counterexample | 反例证伪

To disprove a universal claim, it is enough to produce one allowed value for which the statement fails. This value is called a counterexample.

要证伪一个全称命题,只需给出一个符合条件的值使结论不成立。这个值称为反例。

Example: Disprove 'for all positive integers n, n² + n + 1 is prime'.

例题:证伪 '对于所有正整数 n,n² + n + 1 都是质数'。

3 × 7, so the expression is not prime. This single counterexample disproves the statement.

取 n = 4。则 n² + n + 1 = 16 + 4 + 1 = 21 = 3 × 7,因此该式不是质数。这一个反例就推翻了原命题。

n but fail the conclusion. If n = 4 is not allowed, it cannot be used as a counterexample.

请记住:反例必须满足已知条件,但不满足结论。如果 n = 4 不符合条件,就不能用作反例。


5. Proof by Contradiction | 反证法

Proof by contradiction begins by assuming the opposite of what you want to prove. If this assumption leads to a logical impossibility, the original statement must be true.

反证法从假设你要证明的结论的反面开始。如果这个假设推出逻辑矛盾,那么原命题一定成立。

Classic example: prove that √2 is irrational.

经典例题:证明 √2 是无理数。

Assume, for contradiction, that √2 is rational, so √2 = a/b where a and b are integers with no common factor and b ≠ 0.

假设 √2 是有理数,即 √2 = a/b,其中 a、b 为没有公因数的整数且 b ≠ 0。

Squaring gives 2 = a²/b², so a² = 2b². Hence a²

Published by TutorHao | A-Level Mathematics Revision Series | aleveler.com

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