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Rate Equations | 速率方程

2026-08-29 10:38 · 本文部分内容由AI辅助创作

📚 Rate Equations | 速率方程

Rate equations describe how the speed of a chemical reaction depends on the concentrations of reactants. They are central to A-Level Chemistry because they link experimental measurements to reaction mechanisms.

速率方程描述化学反应速率如何随反应物浓度变化。它是 A-Level 化学的核心内容之一,因为它把实验测量与反应机理联系起来。


1. What is a rate equation? | 什么是速率方程?

For a reaction involving reactants A and B, the rate equation is usually written as:

对于涉及反应物 A 和 B 的反应,速率方程通常写作:

rate = k [A]ᵐ [B]ⁿ

Here k is the rate constant, [A] and [B] are the reactant concentrations, and m and n are the orders of reaction with respect to A and B.

其中 k 为速率常数,[A] 和 [B] 为反应物浓度,m 和 n 分别是对 A 和 B 的反应级数。

The orders m and n are usually 0, 1, or 2 at A-Level, although other values are possible in more advanced work.

在 A-Level 阶段,级数 m 和 n 通常为 0、1 或 2,尽管在更深入的内容中还可能出现其他数值。


2. Order of reaction | 反应级数

The order with respect to a reactant tells us how the rate responds to a change in that reactant's concentration.

对某反应物的级数表示速率如何随该反应物浓度变化。

The overall order is the sum of the individual orders: overall order = m + n.

总反应级数是各反应物级数之和:总级数 = m + n。


3. The rate constant k | 速率常数 k

The rate constant k is temperature-dependent but does not change when reactant concentrations change. Its units depend on the overall order of reaction.

速率常数 k 随温度变化,但不随反应物浓度变化。它的单位取决于总反应级数。

Overall orderUnits of k
0mol dm⁻³ s⁻¹
1s⁻¹
2dm³ mol⁻¹ s⁻¹
3dm⁶ mol⁻² s⁻¹

Always calculate units of k by rearranging the rate equation, not by memorising the table alone.

务必通过重排速率方程来计算 k 的单位,而不要只靠背诵表格。


4. Experimental method: initial rates | 实验方法:初始速率法

In the initial-rates method, the rate is measured at the very start of the reaction, where concentrations are known and reverse reaction is negligible.

在初始速率法中,速率在反应刚刚开始时测量,此时浓度已知,逆反应可以忽略。

n technique is the iodine clock or a tangent drawn to a concentration-time curve at t = 0.

常用技术包括碘钟反应,或在浓度-时间曲线上于 t = 0 处作切线。

Experiment[A] / mol dm⁻³[B] / mol dm⁻³Initial rate / mol dm⁻³ s⁻¹
10.100.102.0 × 10⁻⁴
20.200.104.0 × 10⁻⁴
30.100.208.0 × 10⁻⁴

Comparing experiments 1 and 2: doubling [A] doubles the rate, so A is first order. Comparing experiments 1 and 3: doubling [B] quadruples the rate, so B is second order.

比较实验 1 和 2:[A] 加倍,速率加倍,因此 A 为一级。比较实验 1 和 3:[B] 加倍,速率增加为四倍,因此 B 为二级。

rate = k [A] [B]²


5. Continuous monitoring and concentration-time graphs | 连续监测与浓度-时间图

Rather than only measuring initial rates, we can follow the concentration of a reactant over time. The rate at any point is the slope of the tangent to the curve.

除了只测量初始速率,我们还可以跟踪反应物浓度随时间的变化。曲线上任意点的速率等于该点切线的斜率。


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6. Half-life and first-order reactions | 半衰期与一级反应

For a first-order reaction, the half-life is independent of the initial concentration. This is a key diagnostic test for first-order behaviour.

对于一级反应,半衰期与初始浓度无关。这是判断一级反应的重要特征。

t½ = ln 2 / k

nce ln 2 ≈ 0.693, the half-life is constant for a given temperature because k is constant.

由于 ln 2 ≈ 0.693,在一定温度下 k 为常数,因此半衰期也是常数。

For zero-order reactions, half-life decreases as concentration decreases. For second-order reactions, half-life increases as concentration decreases.

零级反应的半衰期随浓度降低而缩短;二级反应的半衰期随浓度降低而增长。


7. Multi-step reactions and the rate-determining step | 多步反应与决速步骤

Many reactions occur in a sequence of elementary steps. The slowest step, called the rate-determining step, controls the overall rate.

许多反应由多个基元步骤组成。最慢的一步称为决速步骤,它决定总反应速率。

The species in the rate equation must be involved in or before the rate-determining step, but not necessarily in the overall stoichiometric equation.

速率方程中的物质必须参与决速步骤或在决速步骤之前生成,但不一定出现在总化学计量方程式中。

ep might involve only RX breaking into an intermediate, followed by a fast attack by another reactant.

例如,若速率方程为 rate = k [RX],决速步骤可能只涉及 RX 分解成中间体,随后另一反应物快速进攻。


8. Temperature and the Arrhenius equation | 温度与阿伦尼乌斯方程

Increasing temperature increases the rate constant k because more particles have energy greater than or equal to the activation energy Eₐ.

升高温度会增大速率常数 k,因为更多粒子具有大于或等于活化能 Eₐ 的能量。

The relationship is summarised by the Arrhenius equation:

其关系可用阿伦尼乌斯方程表示:

k = A e−Eₐ/RT

Taking natural logarithms gives:

取自然对数得到:

ln k = ln A − Eₐ / RT

A is the pre-exponential factor, R is the gas constant 8.31 J K⁻¹ mol⁻¹, and T is the absolute temperature in kelvin.

A 为指前因子,R 为气体常数 8.31 J K⁻¹ mol⁻¹,T 为开尔文温标下的绝对温度。


9. Catalysts and rate equations | 催化剂与速率方程

A catalyst increases the rate of reaction by providing an alternative pathway with a lower activation energy. This increases k without being consumed in the overall reaction.

催化剂通过提供活化能较低的替代路径来提高反应速率。它增大 k,但在总反应中不被消耗。

At A-Level, a catalyst usually does not change the orders of reaction with respect to the reactants, but it may appear in the rate equation if it is involved in the rate-determining step of a homogeneous mechanism.

在 A-Level 阶段,催化剂通常不会改变各反应物的反应级数,但如果它参与均相机理的决速步骤,就可能出现在速率方程中。


10. Common exam skills and pitfalls | 常见考试技巧与易错点

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