📚 AS AQA Chemistry Unit 1: Insert Skills and Core Concepts | AQA AS化学第一单元：数据手册技巧与核心概念
The AQA AS Chemistry Unit 1 paper is normally accompanied by a printed insert containing the periodic table, key physical constants, an infrared correlation table, and sometimes additional data for structure determination. Successful candidates do not simply memorise facts; they learn to read the insert quickly and use it accurately inside calculations and explanations. This article revises the core Unit 1 topics and shows, point by point, how the insert can support your answers.
AQA AS化学第一单元试卷通常附带一份印刷的数据手册，其中包含元素周期表、关键物理常数、红外相关表，有时还包括用于结构测定的额外数据。取得好成绩的考生不只是死记硬背，而是学会快速阅读数据手册，并在计算和解释中准确使用它。本文复习第一单元的核心主题，并逐点展示数据手册如何为你的答案提供支持。
1. Understanding the Insert and Its Structure | 认识数据手册及其结构
The insert that arrives with the paper is an official data source, not a rough working sheet. Every value printed on it has been checked, so copying a number from the insert is always safer than recalling it from memory. Treat it as part of the question paper rather than as an optional extra.
随试卷发放的数据手册是官方数据来源，而不是草稿纸。上面印的每一个数值都经过核验，所以抄录手册中的数值永远比凭记忆写更安全。要把它当作试卷的一部分，而不是可有可无的附赠品。
The contents are stable from series to series. It contains a full periodic table with atomic numbers and relative atomic masses, a short list of physical constants, a correlation table for infrared absorptions, and - in some papers - extra data such as percentage composition or mass spectral peaks to be used in structure determination.
数据手册的内容在各考季之间基本稳定：完整的元素周期表（含原子序数和相对原子质量）、一份简短的物理常数表、红外吸收相关表；某些试卷还会附带额外数据，例如百分组成或质谱峰，用于结构测定。
t room temperature and pressure, and the ionic product of water Kw = 1.0 × 10⁻¹⁴ mol² dm⁻⁶ at 298 K.
你应该预期看到的常数包括：阿伏加德罗常数 L = 6.022 × 10²³ mol⁻¹、气体常数 R = 8.31 J K⁻¹ mol⁻¹、常温常压下的摩尔气体体积，以及 298 K 时水的离子积 Kw = 1.0 × 10⁻¹⁴ mol² dm⁻⁶。
The layout is predictable. Constants are usually at the front, the IR correlation table sits on its own page, and the periodic table fills the final page. In a paper such as the January 2023 Unit 1 insert the pattern was exactly this, so a candidate who has practised with past inserts wastes no time flicking between pages.
排版同样可预测。常数通常在开头，红外相关表单独占一页，元素周期表占据最后一页。2023年1月第一单元数据手册正是这样的结构，因此平时用历年数据手册练习过的考生不会浪费时间来回翻页。
| Item in the insert | Typical location | What you use it for |
| Periodic table | Final page | Atomic numbers, relative atomic masses, group and period trends |
| Physical constants | Front of the insert | Avogadro constant, gas constant, molar gas volume, Kw |
| IR correlation table | Separate page | Identifying functional groups from absorption wavenumbers |
| Structure determination data | With the question, when provided | Percentage composition, mass spectra, Mr determination |
Spend the first minute of the exam locating four things: the periodic table, the constants box, the IR table, and, if present, the structure determination data. After that, never hunt again - you will know where every number lives for the rest of the paper.
开考的第一分钟用来定位四样东西：元素周期表、常数框、红外表，以及（如果存在）结构测定数据。之后就不用再找了，因为整份试卷中每个数值的位置你都已经清楚。
2. Reading the Periodic Table Quickly | 快速阅读元素周期表
e two numbers are frequently swapped. A quick check saves marks: the atomic number is always a whole number and always increases by one across the table, while the relative atomic mass is usually a decimal, such as Ar(Cl) = 35.5 or Ar(Cu) = 63.5.
数据手册中的元素周期表在每个方框上方给出原子序数，在元素符号下方给出相对原子质量。考试紧张时，这两个数字经常被弄反。一个快速检查就能救回分数：原子序数一定是整数，并且横向依次加一；而相对原子质量通常是小数，例如 Ar(Cl) = 35.5 或 Ar(Cu) = 63.5。
Use the table for trends as well as for numbers. Across a period, nuclear charge increases while shielding stays roughly constant, so atomic radius decreases and first ionisation energy generally increases. Down a group, an extra shell is added, so atomic radius increases and first ionisation energy decreases.
这张表不仅用来查数值，也用来判断趋势。同周期从左到右，核电荷增加而屏蔽效应基本不变，因此原子半径减小，第一电离能总体升高。同主族从上到下，增加一个电子层，因此原子半径增大，第一电离能降低。
The group number tells you the number of electrons in the outer shell, which is the key to writing electron configurations, deducing formulae of ions, and predicting oxidation states. The period number tells you how many occupied shells there are. Reading both numbers before you start a structure question makes the rest of the reasoning much faster.
族序数告诉你最外层电子数，这是书写电子构型、推断离子化学式和预测氧化态的关键。周期数告诉你占据的电子层数。在开始做结构题之前先把这两个数字读出来，后面的推理会快得多。
- Group 1 and 2: metals forming 1+ and 2+ ions.
- Group 7: non-metals forming 1- ions.
- Group 0: full outer shells, unreactive.
- Transition elements: variable oxidation states, coloured ions, catalytic activity.
3. Constants, Units and Significant Figures | 常数、单位与有效数字
he constant you are using. The gas constant R = 8.31 J K⁻¹ mol⁻¹ requires pressure in Pa, volume in m³ and temperature in K.
数值正确但单位错误不得分。在代入公式之前，先把每个量换算成所用常数要求的单位。气体常数 R = 8.31 J K⁻¹ mol⁻¹ 要求压强用 Pa、体积用 m³、温度用 K。
1 m³ = 1000 dm³ = 10⁶ cm³
T / K = θ / °C + 273
Significant figures matter too. Data taken from the insert is normally quoted to three significant figures, so an answer given to three significant figures is usually the safest choice unless the question states otherwise. Never round in the middle of a multi-step calculation; carry the full value forward and round only at the end.
有效数字同样重要。数据手册中的数值通常保留三位有效数字，因此除非题目另有说明，答案给三位有效数字通常最稳妥。多步计算中不要中途取整，要把完整数值带入下一步，只在最后才四舍五入。
Finally, always state the unit in your final line, and make sure it matches the quantity: mol for amount of substance, g for mass, mol dm⁻³ for concentration, kJ mol⁻¹ for enthalpy change, and cm⁻¹ for wavenumber.
最后，一定要在最后一行写出单位，并确保它与所求的量一致：物质的量用 mol，质量用 g，浓度用 mol dm⁻³，焓变用 kJ mol⁻¹，波数用 cm⁻¹。
4. Moles, Masses and the Avogadro Constant | 摩尔、质量与阿伏加德罗常数
The mole is the backbone of Unit 1, and almost every mole question begins with the periodic table in the insert. The core relationship is straightforward.
摩尔是第一单元的骨架，而几乎每一道摩尔计算题都要从数据手册中的元素周期表开始。核心关系式很简单。
n = m ÷ M
the insert. For water, M = (2 × 1.0) + 16.0 = 18.0 g mol⁻¹, so 9.0 g of water is 0.50 mol.
其中 n 是物质的量（mol），m 是质量（g），M 是摩尔质量（g mol⁻¹），由数据手册中的相对原子质量相加得到。以水为例，M = (2 × 1.0) + 16.0 = 18.0 g mol⁻¹，因此 9.0 g 水是 0.50 mol。
The Avogadro constant converts between moles and particles, and it appears in the insert so there is no excuse for misquoting it.
阿伏加德罗常数用于在物质的量与粒子数之间换算，它就印在数据手册里，因此没有理由写错。
N = n × L, where L = 6.022 × 10²³ mol⁻¹
Percentage composition questions also lean on the insert. Divide each percentage by the relative atomic mass of that element, divide each result by the smallest value, and the whole-number ratio you obtain is the empirical formula. If the question also gives Mr, divide Mr by the empirical formula mass to find the multiplier and hence the molecular formula.
百分组成题同样依赖数据手册。把每个元素的质量分数除以该元素的相对原子质量，再把所有结果除以其中最小的一个，得到的整数比就是实验式。如果题目还给出 Mr，就用 Mr 除以实验式质量，求出倍数，进而得到分子式。
- Empirical formula: simplest whole-number ratio of atoms.
- Molecular formula: actual number of atoms in one molecule.
- Water of crystallisation: find moles of anhydrous salt and moles of water, then simplify.
5. Gas Volumes and the Ideal Gas Equation | 气体体积与理想气体方程
Unit 1 regularly tests gases, either through the molar gas volume or through the ideal gas equation. The insert supplies the molar gas volume at room temperature and pressure, usually 24.0 dm³ mol⁻¹ at 298 K and 100 kPa, so mixtures of gases can be handled with simple proportion.
第一单元经常考查气体，方式要么是摩尔气体体积，要么是理想气体方程。数据手册提供常温常压下的摩尔气体体积，通常为 298 K、100 kPa 时的 24.0 dm³ mol⁻¹，因此气体混合物可以用简单的比例关系处理。
For non-standard conditions, use the ideal gas equation.
对于非标准状况，则使用理想气体方程。
pV = nRT
8.31 J K⁻¹ mol⁻¹ and T in K. If the question gives volume in cm³, convert by dividing by 10⁶ before substituting, or convert pressure from kPa to Pa by multiplying by 1000. These two conversions account for a large share of lost marks in gas calculations.
代入时，p 用 Pa，V 用 m³，n 用 mol，R = 8.31 J K⁻¹ mol⁻¹，T 用 K。如果题目给出的体积是 cm³，代入前要除以 10⁶；如果压强是 kPa，要乘以 1000 换成 Pa。这两个换算在气体计算中是失分的主要来源。
Gas questions frequently continue into stoichiometry. Convert the given volume to moles, apply the mole ratio from the balanced equation, then convert back to volume or to mass as required. Always write the balanced equation first, because the ratio decides the whole calculation.
气体题常常接着考化学计量。先把已知体积换算成摩尔，再用配平方程式中的摩尔比，最后按要求换算回体积或质量。务必先写出配平方程式，因为摩尔比决定整个计算的方向。
6. Equations, Ionic Equations and Solutions | 方程、离子方程与溶液中的物质的量
Balanced equations are the gatekeeper of all quantitative chemistry. Check that atoms balance, that charges balance in ionic equations, and that state symbols are consistent with the chemistry described.
配平方程式是所有定量化学的守门人。检查原子是否守恒，离子方程中电荷是否守恒，状态符号是否与题述化学过程一致。
For solutions, concentration links the insert data to titration work.
对于溶液，浓度把数据手册中的数值与滴定计算连接起来。
c = n ÷ V, where V is in dm³
tly. In a titration, calculate the moles of the known solution, use the equation to find the moles of the unknown, then divide by its volume to obtain the concentration.
如果体积以 cm³ 给出，先除以 1000，或直接使用 n = c × V ÷ 1000。在滴定中，先算出已知溶液的物质的量，再用方程式求出未知物的物质的量，最后除以它的体积得到浓度。
tten with only the species that actually change; spectator ions such as Na⁺ and NO₃⁻ are omitted.
稀释题是同一思路的反向应用：加水时物质的量不变，所以 c₁V₁ = c₂V₂。书写离子方程时只保留真正发生变化的微粒，Na⁺、NO₃⁻ 等旁观离子要删去。
- Write the full equation first, then cancel spectators.
- Check charge balance on both sides.
- Include state symbols: (s), (l), (g), (aq).
7. Atomic Structure and Mass Spectrometry | 原子结构与质谱
Atomic structure questions in Unit 1 ask about protons, neutrons and electrons, isotopes and relative atomic mass. The insert supports the numerical side, because the atomic number and relative atomic mass of each element are printed side by side.
第一单元的原子结构题考查质子、中子、电子、同位素和相对原子质量。数据手册为其中的数值部分提供支持，因为每种元素的原子序数和相对原子质量都并列印出。
In a time of flight mass spectrometer, the sample is first vaporised and ionised, usually by electron impact, forming positive ions. The ions are accelerated by an electric field, drift through a field-free region, and are detected. Lighter ions travel faster and reach the detector first.
在飞行时间质谱仪中，样品先被汽化并电离，通常采用电子轰击，形成正离子。离子被电场加速，通过无场漂移区后被检测。较轻的离子运动更快，先到达检测器。
The mass spectrum produces peaks at particular m/z values. The relative atomic mass is calculated as a weighted mean.
质谱在特定 m/z 值处产生峰。相对原子质量按加权平均值计算。
Ar = Σ (abundance × mass number) ÷ Σ abundance
For example, if an element has two isotopes with abundances of 75% and 25% u calculate should be close to the value printed in the insert, which is a useful check on your arithmetic.
例如，某元素有两种同位素，丰度分别为 75% 和 25%，质量数为 35 和 37，则 Ar = (75 × 35 + 25 × 37) ÷ 100 = 35.5。你算出的值应接近数据手册中印出的数值，这是一个很实用的算术检验。
8. Electron Configuration, Ionisation Energy and Periodicity | 电子构型、电离能与周期性
Electron configurations are written in terms of shells and sub-shells. For example, sodium is 1s² 2s² 2p⁶ 3s¹ and chlorine is 1s² 2s² 2p⁶ 3s² 3p⁵. The periodic table in the insert lets you check the number of outer electrons at a glance, which is the quickest way to confirm a configuration.
电子构型按电子层和亚层书写。例如钠为 1s² 2s² 2p⁶ 3s¹，氯为 1s² 2s² 2p⁶ 3s² 3p⁵。数据手册中的元素
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