📚 AQA A Level Chemistry Insert 5 Jan21 | AQA A Level 化学 2021年1月插页5解析
The AQA A Level Chemistry January 2021 Insert 5 is a data sheet provided in the exam room that gives you essential spectroscopic, thermodynamic, and electrochemical information. Many questions in Paper 1, Paper 2, and Paper 3 expect you to look up the correct value, choose the right half-equation, or combine data to solve a problem, so knowing how to use Insert 5 quickly is a real advantage.
AQA A Level 化学 2021年1月考试的插页5是考场中提供的核心数据表,包含光谱、热力学和电化学信息。卷一、卷二和卷三中的许多题目都要求你快速查取正确数值、选择合适的半反应或组合数据解题,因此熟悉插页5的使用方法是一项重要优势。
1. What Is Insert 5 in the January 2021 Paper? | 2021年1月试卷中的插页5是什么?
Insert 5 is part of the AQA A Level Chemistry data booklet that candidates can use during the written papers. It typically includes infrared absorption data, proton NMR chemical shifts, carbon-13 NMR chemical shifts, standard electrode potentials, selected thermodynamic values, and key physical constants. You do not need to memorise these numbers, but you must be able to interpret them correctly.
插页5是AQA A Level 化学数据手册的一部分,考生可在笔试中使用。它通常包括红外吸收数据、质子核磁共振化学位移、碳-13核磁共振化学位移、标准电极电势、部分热力学数据以及关键物理常数。你不必记忆这些数值,但必须能够正确解读它们。
The January 2021 insert follows the same general layout as other AQA data sheets, so practising with it helps you build speed and confidence. The best approach is to annotate the tables before the exam, mark the values you use most often, and understand the units printed in each column.
2021年1月的插页与其他AQA数据表整体布局相同,因此提前练习有助于提升速度和信心。最好的办法是在考前对表格做标注,标出你最常用的数值,并理解每一列中的单位。
2. Infrared Absorption Data | 红外吸收数据
5 gives the characteristic wavenumber ranges for common bonds. The values most frequently examined are O–H, C=O, C=C, C–H, C≡N, and N–H.
红外光谱通过测量化学键振动时吸收的红外辐射频率来鉴别官能团。插页5给出了常见化学键的特征波数范围。最常考查的数值包括O–H、C=O、C=C、C–H、C≡N和N–H。
| Bond | Wavenumber / cm⁻¹ |
|---|---|
| O–H (alcohols) | 3230–3550 |
| O–H (carboxylic acids) | 2500–3000 |
| C=O | 1680–1750 |
| C=C | 1620–1680 |
| C–H | 2850–3100 |
| C≡N | 2200–2260 |
| N–H | 3300–3500 |
When interpreting an IR spectrum, first look for a broad O–H peak or a sharp C=O peak. The broad O– wer wavenumbers than in an alcohol, which helps you distinguish the two functional groups.
解读红外光谱时,首先寻找宽O–H吸收峰或尖C=O吸收峰。羧酸中的O–H峰通常比醇中的更宽且向低波数移动,这有助于区分这两个官能团。
3. Proton NMR Chemical Shift Data | 质子核磁共振氢谱化学位移数据
The ¹H NMR table in Insert 5 lists chemical shifts relative to TMS. The δ value depends on the chemical environment of the proton, and each non-equivalent proton environment produces a separate peak. Integration traces and splitting patterns then give the numbers of protons and adjacent neighbours.
插页5中的¹H NMR表格列出了相对于TMS的化学位移。δ值取决于质子的化学环境,每种非等价质子环境产生一个独立的峰。积分曲线和裂分模式则可以给出质子数目和相邻质子数目。
| Type of proton | δ / ppm |
|---|---|
| RCH₃ | 0.7–1.2 |
| R₂CH₂ | 1.2–1.4 |
| R₃CH | 1.4–1.6 |
| RCH₂CO– | 2.0–2.5 |
| RCOCH₃ | 2.0–2.5 |
| ArCH₃ | 2.2–3.0 |
| RCH₂OH | 3.3–4.3 |
| RCH₂Cl | 3.5–4.0 |
| RCH₂Br | 3.4–3.6 |
| RCH₂I | 3.1–3.3 |
| RCH=CH₂ | 4.5–6.0 |
| ArH | 6.5–8.5 |
| RCHO | 9.0–10.0 |
| RCOOH | 9.0–13.0 |
| ROH | 1.0–6.0 (variable) |
| R₂NH | 1.0–5.0 (variable) |
Remember that OH and NH protons can have variable chemical shifts because they can exchange with the solvent or form hydrogen bonds. In an exam answer you should quote the range and then use integration and splitting to support your structural assignment.
请记住,OH和NH质子的化学位移可能变化,因为它们会与溶剂交换或形成氢键。考试作答时应引用范围,然后利用积分和裂分支持你的结构判断。
4. Carbon-13 NMR Chemical Shift Data | 碳-13核磁共振碳谱化学位移数据
The ¹³C NMR table is useful because each non-equivalent carbon environment gives one peak. Unlike proton NMR, ¹³C spectra are usually proton-decoupled, so you do not normally see splitting. The number of peaks therefore tells you the number of unique carbon environments in the molecule.
¹³C NMR表格很有用,因为每种非等价碳环境产生一个峰。与质子NMR不同,¹³C谱通常会进行质子去耦,因此通常看不到裂分。因此峰的数量可以告诉你分子中独特碳环境的数量。
| Carbon environment | δ / ppm |
|---|---|
| RCH₃ | 5–35 |
| R₂CH₂ | 15–40 |
| R₃CH | 25–50 |
| RCH₂Cl | 25–50 |
| RCH₂Br | 20–40 |
| RCH₂I | 0–25 |
| C–O (alcohols, ethers) | 50–90 |
| C≡N | 110–125 |
| C=C (alkenes) | 110–160 |
| Ar (aromatic) | 110–170 |
| C=O (esters, acids) | 160–185 |
| C=O (aldehydes, ketones) | Published by TutorHao | Exam Prep Revision Series | aleveler.com
